Thermal Properties Of Matter 05 | Heat Transfer : Conduction part 2 Equivalent Thermal Conductivity

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Live Classes, Video Lectures, Test Series, Lecturewise notes, topicwise DPP, dynamic Exercise and much more on Physicswallah App. Download the App from Google Playstore ( bit.ly/2SHIPW6 ) Physicswallah Instagram Handle : instagram.com/physicswallah/ Physicswallah Facebook Page: facebook.com/physicswallah Physicswallah Twitter Account : twitter.com/PhysicswallahAP?s=20 Physicswallah App on Google Play Store : bit.ly/2SHIPW6 Physicswallah Website: physicswallahalakhpandey.com/ LAKSHYA Batch(2020-21) Join the Batch on Physicswallah App bit.ly/2SHIPW6 Registration Open!!!! What will you get in the Lakshya Batch? 1) Complete Class 12th + JEE Mains/ NEET syllabus - Targeting 95% in Board Exams and Selection in JEE MAINS / NEET with a Strong Score under Direct Guidance of Alakh Pandey. 2)Live Classes and recorded Video Lectures (New, different from those on KZbin) 3)PDF Notes of each class. 4)DPP: Daily Practice Problems with each class having 10 questions based on the class of JEE Mains/NEET level. 5)Syllabus Completion by end of January, 2021 with topicwise discussion of Last 10 Years Problems in Boards, JEE Mains/NEET within Lecture. 6)The Complete Course (Video Lectures, PDF Notes, any other Study Material) will be accessible to all the students untill JEE Mains & NEET 2021 (nearly May 2021) 7)In case you missed a live class, you can see its recording. 8)You can view the videos any number of times. 9)Each chapter will be discussed in detail with all concepts and numericals 10)Chapterwise Approach towards JEE Mains/ NEET & Board Exams. ****Test Series for XI & XII**** We provide you the best test series for Class XI,XII, JEE, NEET chapterwise, which will be scheduled for whole year. The test series follows very logical sequence of Basic to Advance questions.& Evaluation of Test and Solution to all the questions at the end of the test. 11 Physics chapter 11 || Thermal Properties Of Matter 01 || Heat and Temperature |Temperature Scales kzbin.info/www/bejne/sKGyfGetn6hnnpY Thermal Properties Of Matter 02 || Thermal Expansion -All Concepts for JEE MAINS/ NEET kzbin.info/www/bejne/b6GuiZaCoK6Ai9k Thermal Properties Of Matter 03 || Calorimetry - Compilation of Old Videos || kzbin.info/www/bejne/imi1oWSin7Cpo7s Thermal Properties Of Matter 04 || Heat Transfer : Conduction part 1 | Heat Transfer JEE MAINS /NEET kzbin.info/www/bejne/l6bapZeqp86sitU Thermal Properties Of Matter 05 | Heat Transfer : Conduction part 2 Equivalent Thermal Conductivity kzbin.info/www/bejne/jXq6cmB4jstsgLs Thermal Properties Of Matter 06 | Heat Transfer : RADIATION : Black Body and Krichoff's Law JEE/NEET kzbin.info/www/bejne/m2mUoaKCpa6tfqM Thermal Properties Of Matter 07 | Heat Transfer : Radiation 02 | Wiens Law n Stefan's- Boltzmann Law kzbin.info/www/bejne/b3fRqneBbt2EoKc Thermal Properties Of Matter 08 | Radiation 03 | Newtons Law Of Cooling JEE MAINS/NEET kzbin.info/www/bejne/gJXbY3-AebeWgJY

[@nileshanand576]

Sir notes

[@theguruofeverythingchoudha840]

Mene 1k dale h

[@parveshkumar6865]

Sir agar 52:55 par question me heat ki dxn ulti karde to ans 180 aa raha hai.... Vo batado ek baar

[@vishruthvs2714]

sir how do u do the question?

[@vishaltripathi2668]

Sir, jis taraf temperature jada hoga heat udhar se flow karegi kya ??

[@abhilipsasamal8519]

for those who want the solution of last question R1=L/3KA R2=L/6KA SO LET R2=R THEN R1 WILL BE 2R FOR SERIES Req= R+2R=3R H=100/3R SO Req for parallel will be 2R/3 H=DELTA T/Req =(100-0)*3/2R SO H=300/2R H=Q/T 300/2R=Q/4(T=4SEC) 600/R=Q FOR 600/R 9gm of ice melts so FOR SERIES H=Q/T 100/3R=Q/8 SO 800/3R=Q SO FOR 800/3R IT WILL BE (unitary method) 800/3*9/600 =4 gm

[@Kartikey-yoursonly]

U put alot effort to type it really get well, I got help 😄

[@BOLT_9274]

Thanks for help

[@mohammadalam1115]

Couldn't stop myself y typing 'thank you'❣️

[@moinamandahomapaul1642]

@Abhilipsa Samal ,Thank you very much.

[@zzzzzzzzzzzzzzzzzzzzzzzzzzz343]

Bhaiya apne toh yeh comment do saal pehel kiya hai mtlb ab toh aap btech kr rhe hoge

[@henajabeen5608]

Timestamps Revision of Conduction from Previous Class - 1:00 Series Combination Basic Explanation - 7:52 Series Combination Thermal Resistance formula Derivation - 10:32 Thermal Conductivity formula Derivation for Series Combination - 16:47 Q1 (Series Combination) - 20:16 Q2 (Series Combination) - 26:20 Parallel Combination - 31:05 Thermal Resistance Formula Derivation for Parallel Combination - 33:14 Thermal Conductivity formula Derivation for Parallel Combination - 36:08 Recap of Formulae Taught - 37:53 Q3 (Parallel) - 39:08 Q4 (Parallel) - 42:10 Q5 (Y shaped Rod) - 49:32 JEE Mains 2014 Qn - 53:50 Qn about Equivalent Thermal Conductivity of Annular Rod - 1:01:52 JEE Advanced 2013 Qn - 1:07:20 HW Qn - 1:15:15 Answer of Homework is 4grams.

[@hitman-dt2ey]

Thanks bro👍

[@chandrammacs2765]

Thanks bro

[@adikarnik126]

Thank you bhai you saved my time 😢

[@ganesh7024]

30:18

[@vallendsouza]

Thank you so much sir for the lecture. Answer of the last question: For parallel: Req=2R/3 H=ΔT/Req =100-0/2R/3=300/2R=150/R Q=H*t mL=150/R * 4 9L=600/R L=200/3R For series: Req=3R H=ΔT/Req =100-0/3R =100/3R H=Q/t 100/3R=Q/8 Q=800/3R Q=H*t m'*200/3R=800/3R m'=800/200 m'=4g. Therefore, In 8s, 4g of ice melts.

[@Priyanka_Kohli]

👍👍

[@Happy-yg8kx]

Bhai Ms∆T + mL heat honi chaiye kyunki 100C ko 0°C pe laana hai pehle

[@PhysicsWallah]

Inorganic chemistry: Hydrogen , sblock , p block will start soon. But faculty will be someone else

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Sir but why

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hope thy will do well

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But why sir

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When you are able to solve questions and understand the concept: Oh man Physics is so easy, its my favourite subject. When 3 questions get wrong in a row: Oh man I am so weak at Physics, I hate it

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[@vikashsahu344]

Ans.of last QN -m:4g.

[@paragchauhan342]

Yes bro

[@manav7045]

Absolutely correct😄😄

[@bhavyatyagi4896]

Bhaiya appki series or parallel m heat kitni aai h...

[@sangramsingh2862]

Yes mass is 4g

[@tannuagrawal9683]

ryt bro

[@musicayan2900]

😂😂 1:04:14 *This question is in 2019 mains This video was released in 2018 Sar ji predicted this* 🔥🔥🔥🔥

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Really?

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@@kasheenpatel9252 yesss

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Sir said 2001 see 1:01:37

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.

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मिटा देवें, रबड़ से

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The best explanation ever which is useful even after four years..... Hats of to you sir🙇‍♀️

[@Prakhar_the_Conqueror]

Dearest and loveliest sir, answer to the last part: Option(b) 4g

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Yeah bro

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Yes

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@@Vikaskumar-re7ts follow what sir had said you will solve it

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Sir jee mains 2019 mein iss lecture mein padhaya hua example as it is aaya tha.... .....thank you so much Sir. .

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Really???

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Abhijeet reAlly aaya tha kya

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[@mukundmaheshwari9648]

Yes jee main mai cylinder vala as it is aaya tha

[@aayushgamingop6202]

Hello alakh sir , The answer of last question is - 4g of ice melts in 8s . Option (b).👍👍

[@shashwatchaudhary2530]

how bro?

[@abhirupkundu2778]

correct

[@abhirupkundu2778]

See, since latent heat of ice is a constant, what you can do is find latent heat of ice in terms of K,A and l from the parallel combination. For that, first find equivalent thermal conductivity, and find heat flown in 4 s, equate this heat with mL, where m is mass of ice melted and L is latent heat. Mass must be in kgs though, now use this value of L in the series combination to find mass of ice melted in the same way, and u end up with 4 gms of ice@@shashwatchaudhary2530

[@rmmusic69]

Correct

[@MukeshGora-d6d]

Correct

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[@Cricket_360_official]

Answer of this question is optiona (b):- 4 grams

[@lokeshsdr.s.lokesh5414]

Same answer bro

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Yes bro....👍👍same

[@pjtsauagcpalem]

Yaah bro

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Same here🙏🏼

[@umeshg561]

kaise bhai pls tell i am getong 81

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Lecture starts at 7:43 for those who are taking the previous and this lesson one after another with no time in between...!

[@lingeshlingesh4171]

LEGEND

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20:00 Now students will have to give JEE 4 times.........Sir predicted the future that NTA will change the rule

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Exactly

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True!!!

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[@roshan87891]

Ans :- 4 gm

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Bhai kaise kara

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Ans is correct bro

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6000k Ho gye broo (bhaiya)😅

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Almost 10M now❤️

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@@anushkagarg1834 now it's 9.53🤘👏

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2023 - 11.1 M

[@mr.gen-z7623]

1:17:43. Answer:- 4g Last step after equating, m1/m2 = 9/2 × t1/t2 m1= 9g t1= 4s t2= 8s 9/m2 = 9/2 × 4/8 therefore, 1/m2= 1/4 and thus we get m2= 4g. HOPE THIS HELPS FOR RE-CHECKING. ALL THE BEST MY FRIENDS😊😊😊😊

[@thegirl4570]

Thank you so much😙

[@sumayyashaheeda3420]

"H" ke value kya aai aap ke??

[@guggillasrinu4559]

Q=KeqA(t1-t2) t/l =(9k/2)2A(100)4/l ...(1)parallel Q'=KeqA(t1-t2)t/l =2kA(100)8/2l ...... (2)series Q=9l Q'=ml (Q'/Q) =2gms

[@guggillasrinu4559]

Could you say how did u get 4gms

[@srvlogs-nr8sw]

Thanks bro

[@blastergaming6540]

31:55 " CARRY MINATI " 39:52 "Technical guruji " 😂😂😂😂😂😂😂

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1:02:40 "harsh beniwal". Hit like if u understand.😂🔥

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Now it's more than millionss

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Sir aap jese log lakho me ek hote ha 🙏highly appreciate your teaching sir

[@merajahmad6806]

For parallel Re 2R/3 H = 150/R M1×L = H×t 9L= 600/ R L= 200/3R For series Re =3R Then H = 100/3R M'L=H×T Put L value here M'×200/3R=100×8/3R M'= 4g

[@arunjyotisahoo7195]

I want to ask you one thing that when there is change in Temperature we use mcΔT But why u use mL

[@rohmaasim1988]

@@arunjyotisahoo7195 in question sir asked about how much ice melt not about how much temp increased so we use latent heat not specific heat

[@arunjyotisahoo7195]

@@rohmaasim1988 OK Bhai

[@rihan6063]

@@arunjyotisahoo7195 because change in state 'L' is same for both parallel and series so you can calculate the value of m

[@arunjyotisahoo7195]

@@rihan6063 yes Bhai Now I can understand

[@merc.5802]

(b)4g:- answer to the last question

[@souradipsoudipabhattacharj3888]

kaise

[@rajraj-pu5uo]

Same here 4g option b

[@darkseid856]

8 gram aana cahiye

[@png403]

@@darkseid856 apne dono ki mistake same hogi lagta hai 😅😅😅

[@abhashdeep2676]

@@darkseid856 sir ke method se 4g aa rha ar convectional method se mera bhi 8g aa rha tha lekin fir maine correct kar liya. Wo 2nd case me series hai to length 2L ho gayega. Ar 1st case me parallel hai to area 2A ho gayega.

[@amritmaheshwari410]

HELLO SIR , I AM A REGULAR STUDENT OF YOUR LECTURES I WATCH THEM AT 1.5 SPEED JUST TO REVISE THEM . I AM A STUDENT OF A GREAT INSTITUTIONS HAVING GREAT TEACHERS . I USED TO COMPARE YOU WITH PHYSICS TEACHER THEM BUT NEVER CAME UPON ANY CONCLUSION . BUT AFTER WATCHING THIS LECTURE I HAVE UNDERSTOOD THAT YOU ARE BETTER .

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chaitanya..?

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Hats off to this man educating the new generation

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30:00 wale sawaal ka answer direct mil skta tha agr 12th ache se pdhi h to... Resistor ke around potential difference utna hi girega jitna phle gira tha... Kyuki situation same h... Phle 70 gira tha k2 ke around to ab bhi 70 girna chahiye Vo tbhi gir skta h jab theta 30 ho That is my alternative way All thanks to alakh sir❤️

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Sahi dimag lagaya bro...!

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Attitude but still down to earth...I think u r not only a good teacher but also an honest and very practical person. In short ek dam bindas ho aap.#THANk YOU BHAIYA. LV u...

[@varungupta1404]

1:17:40 I am getting option b) 4g this was a bit tricky Question though 😅. If you are getting 81 g then somewhere you have taken wrong values of the series and parallel like I did initially

[@Asifusain]

Same here I substituted 4s in series!

[@khagendranathsarma1080]

Same bro.....i took first one as series combination.....so I was also getting 81 initially

[@nanivasihnav1357]

tnk u bro i realized after seeing ur cmt 😅

[@MRpark-ss4pm]

Me too, I took first one in series and 2nd one in parallel and then solve for about 15 min and then looked at the answer then got confused then again check the values of my answer and got the same answer then looked at the question again then finally found my mistake( took 30 min for this ques.)😅

[@sanjeev546]

Wow I'm greatly surprised that some people did just like me. So yall took series in first and parallel one second right? Haha I did same and got 81g as answer

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Sir aap ke dost aap ko aaj dekh krr salute krte honge

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At 31:55 carryminati Kaise hai app log 39:51 technical guruji

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Mai bhi notice Kia bhai

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lagta sir bhi dekhte hoge doono ko

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@@vrajshah1590 sorry bhiya 😔😔

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4g answer for last question From Nepal 🙏🙏🙏🙏

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tiya

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#800k completed

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Sir reminds us about- 31:53= Carry Minati 39:53= Technical Guruji

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Mai comment Karne hi aya tha kya Bhai!

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28:40 sir phli baar meine bina dekhe numerical solve kiya aur vo bilkul correct tha sir thanku

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Become

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Sir ...u must be awarded by National award......who support then like

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Which national award It has already been commented by someone He got 3.2k likes😂

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I was going for revision but watching ur video I came to know that my concepts wasn't clear but now I am done, Thank you so much sir☺

[@sahilrao957]

hi

[@nidhidongre]

Rp=( 1/9)R Rs=(1/2)R Qp= (100×t)/(1/9) =100×4×9 Qp =3600 similarly Qs= 1600 M1L/M2L =3600/1600 9/M2 = 9/4 M2 = 4g

[@amankumar-hw6xh]

Bro I have question... this video is 3 yrs old but if you are watching this now... will it still help?... I mean level must have been increased of questions...🤔

[@ushasoni7551]

@@amankumar-hw6xh question practice can be done by other sources but the concept is same.

[@avikkarmakar7269]

Ans of the last question is :) (b)- 4 gm Thanks sir . For this awesome lecture.

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🤔PHYSICS🤔 + 🤯CHEMISTRY🤯+ 🤣FUN🤣 = PHYSICS WALLAH

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in every lecture uploaded around this period of time, alakh sir has sung "1, 2, 3, 4, get on the dance floor" and sometimes "bandh karo ye athyachaar" 😂😂 we're blessed to have someone like you teaching us.. thank you very much sir.

[@SubhankarNaik-cs9sm]

Haa😂

[@mohitbhoj7401]

Ans of Q is option b-4g.... Thanks sir for doing amazing Q on the topic..keep smiling sir 😀😀😀😀😀

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Ans kaise aaya plz tell me

[@ranadeepdebnath1892]

@@ratna3359 Q=H×t use this equation for both parallel and series... First for parallel: Q=mL=9×(100-0)=9×100 H=∆T/R ( 1/R=1/R1+1/R2 =>R=....) and (R=l/KA) =100×9KA/l t=4sec So,using Q=Ht we get, KA/l=1/4......(1) ........use it for series In series Q=x(100-0)=100x H=∆T/R (R=R1+R2..)and H=100×2KA/l So, 100x=100×2KA×8/l..(use eq (1) here ) => x=100×2×8×1/4 =>x=4....ans. Don't forget to use K1=3K and K2=6K (given )

[@sumanag7343]

Whenever I get bored I do physics but in my 10 the STD whenever I get bored I used to play football but now this change has happened because of my best teacher in this world that is alakh sir

[@iitmotivation4370]

Alakh sir is waiting for me...😙😙

[@gulzarsadique343]

Those who have watched previous lecture... New topic begins from 7:50. Until this revision is being done. All the best.

[@rishavagarwal2045]

100 view 200 likes😨 How it is possible? It is possible bcz #physicswallah is #godofyoutube. .........

[@ayushjain8781]

Dont judge anyone with his likes or views.... Bande ki personality hi uski pahechan hai....

[@rishavagarwal2045]

@@ayushjain8781 tu yahaa bhi aa gaya😂😂

[@ayushjain8781]

@@rishavagarwal2045 kya karoo yaar aadat se majboor hoo... Please....Dont mind Its just for fun....

[@HarshSingh-ik7cq]

@@rishavagarwal2045 glitch samajhte ho vahi hua Hai!

[@superbkitchen2015]

Advanced wala swal khud solve kr diya Maja agya 😉

[@shivanipriya3418]

Aur ye possible hua Sirf the great Alakh sir ke wajah se☺️

[@vineelabandi7220]

Sir u wear such a good t-shirts 😁which are study related and help us in recalling other formulae

[@maxxgamerzgaming7567]

No

[@ayush_pekamwar]

😂

[@arpityadav6619]

Ure tu kaun se grah se aao hai

[@iitaspirations769]

Kya chutiyapa hai bhai,

[@adityavolvoikar7709]

i dont think he understood what his T-shirt meant 🤣🤣

[@chaitalipaul7558]

0:22 the smile for achieving success in life 😌😌

[@aryanx225]

Tru

[@shivanipriya3418]

7:05 sir : kaisa feel kr rhe hain aap log Me : aapko dekhne ke baad ek dm msstt

[@rakshityadav5895]

28:01 thanku so much sir for such a nice way of teaching i solved this question very smoothly

[@adityamjha8980]

Koi ye plzz bata sakta hai ki ye waale sawaal HC Verma ke konse chapter mein hain? kyuki mene Properties of matter mein dekha to usme to pura fluids hi karwaya hua h. Plss somebody help!!!

[@manojtiwari5196]

45:00 in que 4...sir I got same ans when I use H=KA∆T/L formula... Thanks for ur auspicious concepts

[@riturajsingh8676]

37:50 sir's timepass ........ and our timepass :- TV, MOVIES , DANCE , PLAYING ETC .............

[@CristicMesper]

46:30 sir reciprocal nhi hoga kyunki 1/R he......... Video age dekhne se pahle comment kar diya 😝

[@pratikkumar9303]

Hit like for alakh sir

[@maheshnarode9342]

Pratik Kumar aap kaha see ho

[@aryangamers5205]

Sir dil garden garden horiya hai ❤❤❤❤❤

[@vishalpanchal6973]

For regular students lecture starts at 7:34😊

[@alex2528k]

Thanks bhai👍

[@captainevil198]

Thanks bro

[@hdhdshs7299]

Thank you sir for this wonderful long class.

[@prasadalahari]

Sir your explanation was superb Thank you sir 😊 And the answer for the last question is b) 4 grams

[@abhishekprasad9129]

31:56 katai carry wali feel sir ji😆

[@tonugamer2430]

First time i have solved a jee advance question without any help Alakh sir is great 😙😀😁

[@KalpanaKumari-op]

sir in the jee question at 51:22 how can the heat flow from lower temp to higher tem

[@BikashRoy-kj1ul]

Sir....eagerly waiting for videos.. New faculty will surely be good because it's ur selected person but Sir............my frequency matched with u...so no one is better than u for teaching me physics and chemistry.. take care of urself, sir.

[@vijayjain397]

Wow sir congrats for 600k subscriber.may god always bless you and give you all the happiness of the world.love from Moradabad.

[@ManjeetKaur-ke3oi]

Thankkk youuu Sirrrrrrr 😊😊😊😊😊😊😊😊😊😊😊😊😊😊😊😊😊😊😊😊😊😊😊😊😊😊😊😊😊😊😊😊😊😊😊😊😊😊😊😊😊😊😊😊😊😊😊😊😊😊😊😊😊😊😊😊😊😊😊😊😊😊😊😊😊😊😊😊😊

[@atharva2122]

Sir, is the ans 8 seconds..? Sir, it is my humble request that you pin the answers of the H.W questions.

[@laxminarayanmunnalalsugand6398]

No it's 4g

[@rohansengupta667]

answer gm me pucha hain aur tum seconds meain bata rahe ho . 8s to given hi hain . answer 4 gm hain.

[@vatsalramprakash3247]

Vo jee adv 2013 ki Baat Kar raha hai shayad

[@ssinha1701]

I also got 8seconds... I am bit confused😕🤔

[@saanvibhagat4110]

Even I got 8 g

[@futureengineeer3093]

Feeling confident after solving advance questions within minutes 💪💪💪😄 thankuuu sir 😍😍

[@ASHOKKUMAR-gi4fl]

56:28 who had checked the mistake... Spelling of rod... 🙂🙂 Luv U Sir from Aligarh❤❤

[@clown3055]

Physics Wallah is not a channel. It’s a family of 6 lakh students and the man who needs no introduction. ✍️✍️🙏🙏

[@rashigupta4095]

Sir,, answer for last question is 4g.😁 Thanks sir for all ur efforts and wish u to be healthy. 😊😊😁

[@fanofabdevillersandmathslo5960]

Answer to homework question is OPTION-B(4g) Thank u so much sir....................... Lots of love from Andra Pradesh..................

[@vedanshhi6616]

It is most lovely video ever on KZbin on Heat transfer and most interesting topic in whole series

[@manojtiwari5196]

Yeah dude✌🏻💫

[@titisha7624]

Option (b) 4g Thank you so much sir ji🙏🙏🙏🙏🙏👍😊😊😊😊😊😊😊🤗

[@nidhihooda8670]

I think that at 46:58 sir haven't done the reciprocal 🤔 Am I right ??

[@anandmani1504]

Yes bro u are right my answer is different. 😊

[@anshumanrath6703]

We love you sir! I sincerely thank you for all your efforts.. And yes it's our favorite channel - "Physicswallah "

[@shashwatsaxena6220]

At 20:00 Yes sir NTA has changed the exAm pattern. Sir knows the future😅

[@arrowbang2725]

Yup

[@yuvraj9586]

Sir sabka baap hai . Salam sir aapko 👍👍🤩

[@risingaditya4192]

It has changed also Wah sir kya prediction hai apka👍👍👍🙏

[@sanchitsingla2945]

Sir at 1:17:28 heat firstly water ke temp ko change karegi from 100deg to 0deg then state change hogi. Sir phir Q=mc∆t + mL honi chahiye...

[@adityadeshmukh871]

han

[@swatinaidu7134]

U r an excellent teacher. Thank you for clearing basic concepts in such simple way.

[@AmitKumar-rl8zw]

sir since i am a student of aakash institute and very happy and proud to say that u covered all the topics that has been taught by my teacher .bahaut achee se samagh aaya sir. app kisi aakash teacher se kam nhi hai sir balki unse bhi achaa padhate hai.

[@anjaliverma8978]

Same bro akash is useless totally useless