"Remarkability lives at the intersection of excellence and the unexpected." Yes.. yes it does!
@PW-qy8mf7 ай бұрын
before watching the video: I would need 3 moves: 1. weigh 6 against 6 --> eliminate the 6 on the lighter side 2. of the heavier 6, weigh 3 against 3 --> eliminate the 3 lighter ones 3. weigh any 2 of the 3 remaining ones against each other --> if one side is heavier, this is the one with the weight in it. If the scales are in equilibrium, the one with the weight is the one you didn't weigh in the final step. Now I'm excited if that was the most efficient solution...