This SAT question is harder than it looks...

[@Shameilia2004]

I definitely got this wrong

[@reflxyy2228]

Glad I’m not the only 2004 baby still struggling with the SATs

[@adplayz3054]

It is D. Since the variable is in a radical we know that whatever is inside the radical cannot be less than 0 as imaginary numbers like the name suggests, don't exist so we know that m has to be > -7. so if we solve the equation algebraically (square both sides, subtract 7) we get x

[@Th3Fr0ntGuy]

It asks for an even number rather than a positive number. Root of(7+2) = 3 Root of (7+0) < 3 Root of (7-2) < 3 Root of (7-4) < 3 Root of (7-6) < 3 Root of (7-8) = Imaginary Number Answer: D

[@rodrigoll8407]

East, D. Also the reason why imaginary numbers (for m = 8, for example) is because we can't compare an imaginary number with a real number.

[@mrmimi807]

I thought that the concept of even and odd doesn't apply to negative integers

[@alexthebold]

I thought zero wasn't odd or even

[@adw1z]

It makes more sense to class 0 as even

[@rosshenderson8139]

why would complex expressions not apply?

[@nasdfigol]

Not an integer I think?

[@donmoore7785]

Because by default we only consider the domain the square root function as non-begative.

[@concerned9890]

Saying something like 2i

[@rosshenderson8139]

why would the magnitude of the complex vectors not be comparable? My first inclination is all even integers down to -16 would satisfy this

[@davidgillies620]

ℂ has a total order but not a well order so w < n, w ∈ ℂ, n ∈ ℤ is meaningless.

[@OmVerma-x1w]

Finally a queetion arrived to trick me😅😅

[@adw1z]

Clearly m >= -7 (positivity) and m

[@Faneshnsh]

Ngl but trickiest question I saw on the ACT

[@markcroxall1263]

Integers can only be positive natural numbers. The only even integers that satisfy the equation for m are 0 and 2. So B is the correct answer

[@murtazaali5322]

Nope, they can be -ve

[@bridgeon7502]

I thought even numbers had to be ≥ 0

[@jimmygamify]

Yeah this is honestly pretty easy not gonna lie when you know what to do

[@alexlu8178]

too easy, need harder questions

[@ashna1120]

....i wish i was born in USA cause if i saw a question like this in my entrance, i would question my exam for being too easy 😭😭😭

[@babideeran6212]

The question are easy but time is low tho , Most exam offer 1 min + to solve a question+ you don't have to score 90% in most entrance to get into a good college In sat you need atleast 1200 for a good college

[@Rg-nk3rc]

You can have negative square root, just use your *imagination* .

[@Mustafa_Shahzad]

Uh.. no. Less than or equal to restricts this to real numbers

[@ccjl9160]

You can't *imagine* integers. Stay rooted in reality

[@jacktaylor9290]

It's a trick question.

[@travisr82]

This for 10 year olds ?

[@milothebeast1832]

Harder❌ Just one of class 8 questions

[@GetMeThere1]

I doubt you would find this on the SAT. To answer it requires knowing that zero is an even number -- and that's....kinda specialized knowledge, IMO.

[@rhythm8263]

Not really, if you don’t know that 0 is an even number then you shouldn’t be able to get a perfect score. 0 being an even number is not «specialised knowledge» it makes sense, it’s a multiple of 2, (2 * 0) while it doesn’t fit into the definition of an odd number 2n + 1, where n is an integer

[@donmoore7785]

I disagree. That is like saying knowing how to tie a shoe is specialized for a 6th grader.

[@GetMeThere1]

@@donmoore7785 I think your use of simile could use a little work, LOL

[@GetMeThere1]

@rhythm8263 "...if you don't know...then you shouldn't..."THAT is what we call "an opinion." It's your personal feeling. Of course, my comment is also an opinion -- but of a much different kind. My is a reasoned estimation (from someone who got 780 -- lo, those many years ago, lol) about the goals and intentions of a testing company. Yours is just....your feelings about how the world should work.

[@rhythm8263]

@@GetMeThere1 no I have never taken the SAT, because I’m not American, and it’s not an opinion it’s a fact, if you don’t know that 0 is an even number then why should you get a perfect score? This question is testing if you are able to reason. This is not «specialised knowledge», because why would 0 be odd? Just by logic you can figure it out. Everything you learn about odd and even numbers would tell you zero is an even number. You often learn that even numbers are divisible by 2, is 0 divisible by 2? Yes, because zero is divisible by every number. Even just basic number sequences would tell you 0 is even. If you know -4, -2, 2, 4 are even, it would also make sense for 0 to be even: -4, -2, 0, 2, 4.

[@Joedoesty]

Easy problem😊

[@Mrmakeyoumad]

What grade math is this

[@alphareborn9908]

Pre K

[@Mrmakeyoumad]

@alphareborn9908 Sounds like you have a lot of experience in that grade. Perhaps demotion got too intense?

[@alphareborn9908]

@@Mrmakeyoumad Mr make you mad? 😂 I see why you chose that name, nice try

[@alphareborn9908]

@@Mrmakeyoumad but to answer your question, no I haven’t. I was put in AP Pre-K.

[@Mrmakeyoumad]

@@alphareborn9908 they don't call me that for nothin'

[@aksdmanboi2961]

M equals 10 black guys

[@trevorjames4619]

Please explain this.

[@thecryingknight6527]

@@trevorjames4619you do not want him to explain this

[@alphareborn9908]

Show your work

[@Mortadelo_]

are they big tho? 🤨 If they are we'll have to add another equation that includes the 3rd leg

[@AdityaPrasadSahu1804]

Bro that's just basic of functions

[@Vusi2020]

🙏🙏🙏

[@fjccommish]

This SAT quesion isn't hard.

[@geekonomist]

Two

[@hassanawdi3793]

Hardest HA 😂

[@tylerwalton4573]

This stuff is so stupid

[@mariapotamitou8018]

Jesus died on the cross for you and your sins