PROJECTION OF STRAIGHT LINE IN ENGINEERING DRAWING IN HINDI (SOLVED PROBLEM 1)

[@trm_solves]

all bow down to the goat of engineering graphics, underrated hero of many engineering students

[@saarza9991]

🐐

[@AmanPrajapati-b4v]

😅9😅H

[@Lulzmania-dt1jh]

blud its been a year, the reason my cg is down today is because of this subject, I'll be moving into my 4th semester this January, and to this date this course has given me the worst grade, i cant comprehend I've gone through tougher courses than this, but i fail to realise how i got the lowest grade in a course where you just have to just join lines,smh!

[@ShreyaKamath27]

Thankyou for taking out your time and teaching on KZbin. I'm not an engineering student but my boyfriend is. You're great help to him. He says that you teach better than faculty itself and he can understand everything easily by seeing your videos. I'm so happy that he can easily learn without any difficulty, thanks to you. I hope other students also take advantage of your teaching. Thankyou once again sir, keep up the great work!

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😊😊😊

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Aapko bf ki boht fikr h.. Aap loyal lagte ho.... Is it true ? ❤🎉

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Hn mere gf hai Tere ko dikkat hai ​@@KushalYadav-kk9rz

[@shahnawaztarique3250]

Thanks a lot sir because of your videos I could prepare my engineering drawing paper and the paper went well.... God bless you and your channel.

[@mubeenabegum357]

Good...Ma sha Allah. Please pray for the hidaya of Professor saab.

[@vidswith_pratham]

i was so afraid of engineering graphics but after watching sirs lectures i am feeling more confident

[@doc2407]

Thanks sir! You are savior for students. Otherwise, some PhD holders in Mechanical engineering are just lol!

[@mamirulkhan6997]

Sir mera jo problem tha sare projection of line ka tropic dekkar solve ho gaya.Thank you sir.

[@TIKLESACADEMY]

Thanks for watching....

[@CreepyHistory409]

Listening to ur lecture one night before exam is fascinating 😅

[@thorodin1598]

Lol true

[@RushikeshFalkeArtVlogs]

Same

[@Animeisrealll5]

Pass hue?

[@chayannim9665]

Thank you sir aap ke vedios dekh kr me😁 pass hogya love uh..sir🥳🥳🥳❣😊

[@aswinunni-fr2wq]

Sir you are really the goat of indian engineering❤❤🎉🎉

[@pradeepkumarmaurya8112]

Exam ke ek din pahle padhne wala hu mai 😂😂.

[@harshdeepbangar4574]

Mai bhi😅

[@AjayPatil-hu1fd]

Mai bhi bhai

[@mdsaifkhan7871]

Same here

[@lalitha4199]

@@mdsaifkhan7871 Kisko pakaate ho be MSBTE k saare exams ho gaye abhi koi exam baaki hi nahi hai

[@akashap6330]

@@lalitha4199 do u know him.@md Saif khan

[@srusthidevaray]

Super teaching sir I understand how to solve the problem your explanation is super sir 😊😊😂😂

[@Rohitkumar-kg1bh]

TL=75.17mm,Theta=30deg.,phi=43deg.

[@twilight7138]

How? Help me

[@thevishwass]

same but that TL = 75.17 bruhhh, how that 0.17 you calculated 💀💀

[@bhavana.v2270]

S

[@bhavana.v2270]

TL=73 mm and thetha is 30 and phi is lieing between 43 and 44

[@PAGALDRG]

Yes​@@bhavana.v2270

[@rjrahul4765]

Thnkq you so mach so collage me kuch nahi samjte hi aap se total samaja a jata hi love you sirrr

[@VedantNitinMore]

Fantastic explanation sir, It completely cleared my topics thank you very much sir

[@vanillabean1077]

Thank you for the amazing explanation ! ✨✨

[@SoniKumari-yg2gm]

the top view of a 75mm long line pq measures 50 mm. the end p is 15 mm above hp and 50 infront of vp . the end q is 20 mm infront of vp and above hp . draw the projection of pq and determine its inclination with the reference plane

[@ishanverma9336]

True length= 75mm Theta = 42° Phi = 31°

[@shreyashkale9900]

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[@mr._.headshoter]

bhai woh sab jaye bhaad mai answer kya hai?@@shreyashkale9900

[@jatinsatyam6852]

Thankyou so much sir, we are grateful to be able to learn from you.❤️❤️

[@all-rounder_editor]

Sir you are very best learner for the graphic

[@sahanaafreen9540]

TL =75 MM Thetha=31 degree Phie =43 degree

[@omnaringe2166]

Right 👍😊

[@vinitsolanki7094]

76mm,30°,42°

[@amaankhancreations1285]

75 30 42

[@gauravmaheshwari1107]

Tl= 75 Q=30 ¢=42

[@jaymahakal7488]

Tl =75 Theetha= 31° Phie=43°

[@PujaSingh-hw9wq]

Teaching very well sir thnku so much

[@dhananjay1321]

Thank you very much Sir... Explanation is highly Good and very Helpful vdo we can watch this anytime.... This vdo means a lot for us 🙌🙌🙌🙌

[@samirbhai2632]

Thank you so much sir ❤❤❤❤

[@manjalimaurya1916]

Thank you sir ji 🙏

[@TIKLESACADEMY]

Thanks for watching

[@davdakunal7566]

Great Teaching sir ❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤

[@TIKLESACADEMY]

Thanks and welcome

[@Mahamaya_meldi_ma]

Sir Aap bahut acha padathe ho

[@akshaymanikjade]

Tikale sir appreciate your way of explanation but you never touch concept that why we have to rotate the view in order to get TL and inclination. Pls try to explain it conceptually also which will complete discussion of this topic. Pls consider it as suggestions not comment. Rest everything is fine in explanation

[@aradhyapandey9366]

Thank you sir... You have helped me so much🙏🏻

[@prateekpallav1867]

kya haal h bhai

[@sumitjayswal3276]

Sir aap itna accha padhate hai ki kuch doubt hi nhi rahta 👏

[@akshaysolanki8521]

Thank you so so much sir sabhi topic itne aache se aapne clear ki hai thanks so much sir

[@abdullahakramsheikh1388]

Allah bless u sirr.. Thanks for these useful videos.. Love from Pakistan

[@mubeenabegum357]

Aameen.

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Sir aap bahut accha samjhate hai

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Sir sayad hi ed.ka apse acha teacher ho🙏🙏

[@akashmapari1127]

Thanks you sir watch this video my all doubt are clear

[@darknessboy8062]

Sr . U r great.. Sb koi like karenga

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Mr perfect sir❤

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Mast samjhate hai sir Mai aap Ka fan Ho Gaye sir

[@TheBaljitSingh]

Aaj sham ko exam hai aur aaj subah me padh raha hu. Kya din hai 😍

[@rutikbodkeacademy1247]

Wow,sir.... amezing teaching.....I am from mumbai, Maharashtra.....

[@nayeemuddin2467]

Thank you so much sir

[@asifkhan-yr5rv]

A line AB 90mm along is inclined to 30 degree to HP it's end A is 12 above HP end 20mm in front of VP it front view 65 degree .draw the projection of line AB and determine its inclination with HP Please solve that question Sir please

[@nayandeshmukh70607]

Punnet superstar 💓💓

[@omnaringe2166]

Great teaching 👏 sir 🙏

[@noobinsaan3418]

Kal ld me mid sem hE, And guess what I am here 😁, btw thx Sir for giving such efforts ❤️❤️❤️

[@muhammadmajidkhan9907]

thank you very much sir g..

[@TIKLESACADEMY]

Thanks for watching

[@adityarajsinghrathor]

Dhanyawad Guruji 🙏🙏🙏🙏🙏

[@SanidhyaYadav-cm5ic]

Thank you sir you are great

[@janhveeghewari2578]

Q3. A straight line AB is inclined 45 deg to HP and 30 deg to VP. The point A is in HP and point B is in VP. The length of the straight line is 70 mm. Draw the projections of the straight line AB. Also mark its traces.

[@a_43_sayyamjain30]

Your efforts are fantastic sir

[@MechanicalGuy]

Ed ke best teacher aap ho

[@AdityaKumar7000-nl4wy]

Kaun kaun 2025 me dekh raha hai ❤❤❤❤❤ comment me batye

[@airmyson5276]

Sir, i have the following doubts hope you clarify them as soon as possible 1: reference line should be drawing with 2h or hb pencil? 2: is there a requirement for 4h pencil in drawing? 3: points like a a dash should be written with hb or 2h pencil? 4: scales pe exam me RF aur LOS likhna jaruri hai kya?

[@TIKLESACADEMY]

Your all points are correct.

[@pranshulkevines3362]

tommorow is my exam aur aaj ye video dekh raha hu ,😂 Thank you sir ✌️

[@shubhamugale1504]

love you sir sooo much

[@samjoshua4585]

you save my my marks

[@karunada-ff]

Sir your lecture is unbelievable sir

[@Jaw_blader]

Thita=150° TL=750mm (75 cm) Five angle= 224°

[@sivakalyan670]

U r amazing sir

[@vrutikapatel6690]

Thank you so much sir......

[@filmyengineer...1836]

It is very helpful 🥺.... thanks you so much sir 😍🙏🏼

[@funkyyaar8553]

This lecture is more valuable

[@TIKLESACADEMY]

Thanks for watching

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Sir u really really deserve many more subscribers 😭❤️❤️❤️

[@maliksamiullah9856]

Legendary

[@nishaeshu232]

Very nice video sir jii

[@ABHI-bi8fe]

Nice explaination sir 👍 tnqu

[@TIKLESACADEMY]

Thanks for watching

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I am so grateful to you sir . This videos helped me a lot

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Thank u ☺️

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🙏nice sir .nice teaching.😅😅

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Fentastic video sir

[@TIKLESACADEMY]

Thanks for watching

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Thak you sir

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Thanks for watching

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Nice sir ❤️

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THANKS 🙏🏻❤

[@arjunbs8041]

Osm videosssss

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Thanks for watching

[@daoudkamili]

awesome

[@MuskanSingh-qi8nh]

Ur teaching is awesome sir👍

[@davil905]

🙏🙏🙏🙏 very nice explanation

[@parassontakke3753]

Sir I have doubt A line PQ has its end P, 10mm above H.P. and end Q,70mm in front of V.P. The F.V. of the line is inclined at 40° to the XY line. The H.T. of the line is 30mm in front of the V.P. and it's V.T. is 20mm below the H.P. Draw the projections and find its true length n true inclination with H.P. n V.P.

[@fullstackdeveloper2025]

ekdm mast😁😃

[@akshaysolanki8521]

Sir bhot help ho gyi aapki vajah se

[@madanbk5527]

Sir plz solve this question A uniform section with contact departs freely supported over a span of 4m.if the point load at mid span is 40kN and moment of inertia is 15.614*10-¹⁰m⁴and elastic of material is 200GN/m² Determine ,central deflection and slope end of the beam .plz sir 🙏

[@atharvasenson4951]

in projection of points you draw the ponits with dash a' on vp but here you said that point releation with hp is always drawn with dash

[@Symahry]

Sir question may likha hai 10mm above the hp and in the vp. So, ham 10mm distance neechey bhi lena hogana sir

[@TIKLESACADEMY]

Point is in VP it means top view ka point aapko in XY lena hai.

[@prashantmendhe9728]

Top view of the line measures 50 mm. The line is inclined 300 to HP. Draw its projections when its one end is in the HP and 20 mm in front of VP when it’s other end is 55 mm in front of VP

[@prashantmendhe9728]

Sri 1 vdo on this question

[@Theamit7951]

God for every pour students 🥺

[@Kit-ev2eo]

Kadak

[@bajrangisharma1144]

Splendid 👍

[@All_in_one_19383]

Before 2hour of exam😂😂

[@Mcg-vn8xd]

True length=7.5mm Theta=30 degree Fai=40 degree

[@jackup4468]

Great sir 👌👌👌👌👌👌👌

[@eshitarathore1068]

Thnkyou sir subh paper he 🥺🙏

[@AfjalismailKhan]

Just making this comment to remember some memories of these days.

[@25_ronniee]

Video starts at 3:10

[@Madhav_mv_123]

I remember when I study one day before the exam, And I am doing the same even today. 😅

[@lazzy5173]

TL = 75mm Theta = 30 degrees Phi = 43 degrees.

[@somilvijay31]

kaise nikale angles length ?

[@vmfilms672]

TL = 75mm Theta =30 Phi =42

[@eireshmedidar2156]

Super sir

[@jelsenapk2408]

Sir one doubt in HP We get plan or top view it indicate by a in VP we get front view it indicate by a' then problems how it changed

[@Manasa1877]

I am grateful for you sir

[@electrocode4095]

Sir thank you so much for your help :-)

[@RishabhSharma-q9i]

3 hour bad exam hai guys 😅

[@NazParveen-l1e]

To padho na

[@realgamervishu3191]

1 hour baad 🗣️

[@muneebpeerzada6699]

pass hogaya?? ​@@realgamervishu3191

[@muneebpeerzada6699]

pass hogaya??

[@realgamervishu3191]

@@muneebpeerzada6699 bhai pata ni shayad hojau

[@skillershaza]

Sir please is q kah solution par bhi video bnah dain Assignment # 2 A line AB has its end A (20+x) mm below the H.P. and (30+x) mm behind the V.P. The front view of the line (40+x) mm long and is inclined at (45+x) to the xy line whereas its top view is inclined at (65+x)° to the xy line. Draw the projections of the line AB and find its true length. Also find its true inclinations with the H.P. and the V.P. Where x = last digit of your registration number.