EQUILIBRIUM IN ENGINEERING MECHANICS IN HINDI LECTURE 12

[@glitch4771]

Sir distance of 100kN force from A will be 3-x, not 4-x. This is because, let that distance be 'y'. Now, total distance is 4. So 4=1+y+x. So x+y=4-1=3 and so y=3-x.

[@bhaumik250]

nhi bhai 4-x he hoga dekhna a to b 4 hai 100 kn maan le c pe act kar rha hai to bc tera x hai toh ac kitna hoga 4-x

[@yubrajkarki.]

how u have solved please answer is detail. prove karr k toh dikha na

[@yubrajkarki.]

the total length of bar is 4 m so 100 * ( 4-X ) not 4-1 = 3-X yeh keise karsakta hai yesa nahi hota yeh galat hai so solve it properly.

[@savitagunjal2165]

Right hain it is 3-x..... because total length is 4m but we have also one distance i.e. 1m...so we have to consider that 1 m

[@ravirajan4739]

Sir surface par 3 force lagta hai 1 Please reply

[@devilszone4214]

Thanks sir🙏🏻

[@Mohitchavan6822]

Thankyou sir 😊🙌

[@laxmirajput9715]

Thankyou sir

[@nileshsharma9769]

Sir aap cuet leet ka engeneering graphics ka pura syllabus pada dijiye

[@SujataSamleti]

Ra and Rb kaise find kiya hai

[@nileshsharma9769]

Cuet leet ki taiyari Kara dijiye

[@SUBHASHKUMAR-xc6th]

Sir Engineering Meterials subject Padhate haye Keya... Please Ans sir...

[@yubrajkarki.]

final moment from A is loads are in clockwise direction and last one is in Anti-clockwise direction. the take moment from A. It means 200*1+ 100* (4-x) - Rb sin (45) * 4 = 0. final value of X will be 1.607m. because the total length of bar is 4m

[@VishalYadav-gl8dt]

Sir aap ka ye mechanics ka ye sabhi lecture mumbai University ke liye aaplicabel hai kya

[@yubrajkarki.]

haa hai because is a lecturer and professor

[@hacker001-m8c]

Your Calc is wrong

[@yubrajkarki.]

Tera dimag wrong hai and he is right because he is a professor