TIP

[@forestfolks]

Excellent tip! I like the way that you take a complicated topic and make it simple to understand. Thank you so much for doing these videos!

[@RobertFeranec]

Thank you very much Jon

[@victorschlim4644]

I can't believe this content is free :)

[@pinolec]

Thx Robert for a tip. I found it very useful. I had a problem with my arduino mega on my 3D printer. It worked with old computer but refused to work with new. I checked it on short lead and it worked. It turned out it is cheap arduino clone witch ch340 usb to uart chip and they placed 49R9 termination resistor. Changed it to 22 ohm and it works. Looking forward for new tips.

[@RobertFeranec]

Awesome :)

[@aliuzel4211]

Prefer 0402 size as close as possible to output. If 2 of them can be used in parallel for two receiver, Rout + r1//r2 would be close to 25 ohms.

[@kentvandervelden]

Nice explanation. You're a great teacher.

[@RobertFeranec]

Thank you Kent for nice words :)

[@Rottingchristc]

Hi Robert how do we know the capacitance value of the track and the pin? is there a way to calculate that termination resistor? Also why can we disregard the inductance and the resistance of the track and the pin?

[@rok4131]

Hey +Robert, I really like your videos and the way aou're sharing your knowledge. I am wondering if it is still possible to have crosstalk between tracks if there is a ground polygon poured between them? The distance between the edges of the track would be 30 mils.

[@thecankaya]

Everyday one tip! very nice and very thank you +Robert

[@RobertFeranec]

Thank you Mustafa

[@chauhanchirag94]

Thanks, Robe.

[@MDFRESCUER]

Nice.

[@mikal_1]

In my mind the placement of this resistor would be best as close to the signal pin as possible, so that the square wave is "smoothed" as early as possible. Is this correct way of thinking or is there anything else I should be learning about this?

[@RobertFeranec]

Basically, yes, that is correct - as close as possible to the output pin, so the signal is "smoothed" as early as possible.

[@Graham_Wideman]

1:30

[@matheuss5000]

Amazing explanation

[@RobertFeranec]

Thank you Matheus :)

[@myusernameislongerth]

There's one bit that was left unclear for me - the location of the resistor. Should it be close to the clock source, or the destination? Or it doesn't matter?

[@aliuzel4211]

Sould be close the driver side if series. Parallel at the receiver side.

[@irkenlabs]

This should then be placed as close as possible to the output/sender pin on the PCB to minimize the distance the 'sharp edge' is traveling?

[@theondono]

otakuzim correct. Another way to look at it, from the output to the resistor, you've got an LC circuit, the longer the track, the bigger the LC circuit. Since you want your track to behave as little as possible as a RC circuit, bring those resistors close. My pro tip: When prototyping place these things EVERYWHERE. Then just place 0R around the tracks that you don't expect to have termination problems. It costs almost nothing, and saves you the risk of having to do major rework or respin the board

[@RobertFeranec]

Correct

[@Rottingchristc]

otakuzim Hi , what do you mean by sender pin of the pcb? do you mean the connector?

[@RobertFeranec]

Output. The series termination resistor should be placed close to the Output pin (usually the chip).

[@deltaav81]

If we have a TVS diode for transient protection, which would be a better place for a series termination resistor, before or after the TVS diode.

[@theondono]

deltaav81 you need to take into consideration your TVSs parallel capacitance, so place your resistors as close to the pin as possible.