Excellent tip! I like the way that you take a complicated topic and make it simple to understand. Thank you so much for doing these videos!
@RobertFeranec7 жыл бұрын
Thank you very much Jon
@victorschlim46443 жыл бұрын
I can't believe this content is free :)
@pinolec7 жыл бұрын
Thx Robert for a tip. I found it very useful. I had a problem with my arduino mega on my 3D printer. It worked with old computer but refused to work with new. I checked it on short lead and it worked. It turned out it is cheap arduino clone witch ch340 usb to uart chip and they placed 49R9 termination resistor. Changed it to 22 ohm and it works. Looking forward for new tips.
@RobertFeranec7 жыл бұрын
Awesome :)
@aliuzel42114 жыл бұрын
Prefer 0402 size as close as possible to output. If 2 of them can be used in parallel for two receiver, Rout + r1//r2 would be close to 25 ohms.
@kentvandervelden7 жыл бұрын
Nice explanation. You're a great teacher.
@RobertFeranec7 жыл бұрын
Thank you Kent for nice words :)
@Rottingchristc7 жыл бұрын
Hi Robert how do we know the capacitance value of the track and the pin? is there a way to calculate that termination resistor? Also why can we disregard the inductance and the resistance of the track and the pin?
@rok41317 жыл бұрын
Hey +Robert, I really like your videos and the way aou're sharing your knowledge. I am wondering if it is still possible to have crosstalk between tracks if there is a ground polygon poured between them? The distance between the edges of the track would be 30 mils.
@thecankaya7 жыл бұрын
Everyday one tip! very nice and very thank you +Robert
@RobertFeranec7 жыл бұрын
Thank you Mustafa
@chauhanchirag946 жыл бұрын
Thanks, Robe.
@MDFRESCUER7 жыл бұрын
Nice.
@mikal_14 жыл бұрын
In my mind the placement of this resistor would be best as close to the signal pin as possible, so that the square wave is "smoothed" as early as possible. Is this correct way of thinking or is there anything else I should be learning about this?
@RobertFeranec4 жыл бұрын
Basically, yes, that is correct - as close as possible to the output pin, so the signal is "smoothed" as early as possible.
@Graham_Wideman4 жыл бұрын
1:30
@matheuss50007 жыл бұрын
Amazing explanation
@RobertFeranec7 жыл бұрын
Thank you Matheus :)
@myusernameislongerth7 жыл бұрын
There's one bit that was left unclear for me - the location of the resistor. Should it be close to the clock source, or the destination? Or it doesn't matter?
@aliuzel42114 жыл бұрын
Sould be close the driver side if series. Parallel at the receiver side.
@irkenlabs7 жыл бұрын
This should then be placed as close as possible to the output/sender pin on the PCB to minimize the distance the 'sharp edge' is traveling?
@theondono7 жыл бұрын
otakuzim correct. Another way to look at it, from the output to the resistor, you've got an LC circuit, the longer the track, the bigger the LC circuit. Since you want your track to behave as little as possible as a RC circuit, bring those resistors close. My pro tip: When prototyping place these things EVERYWHERE. Then just place 0R around the tracks that you don't expect to have termination problems. It costs almost nothing, and saves you the risk of having to do major rework or respin the board
@RobertFeranec7 жыл бұрын
Correct
@Rottingchristc7 жыл бұрын
otakuzim Hi , what do you mean by sender pin of the pcb? do you mean the connector?
@RobertFeranec7 жыл бұрын
Output. The series termination resistor should be placed close to the Output pin (usually the chip).
@deltaav817 жыл бұрын
If we have a TVS diode for transient protection, which would be a better place for a series termination resistor, before or after the TVS diode.
@theondono7 жыл бұрын
deltaav81 you need to take into consideration your TVSs parallel capacitance, so place your resistors as close to the pin as possible.