Solved the error and got to know that your code doesnt work when there is only one feature and facility added
@tj_webdev Жыл бұрын
Great👍
@femiajao9082 Жыл бұрын
Please I need your kind assistance with this project source code.. Thank you
@AnishGiri-fl8ws3 ай бұрын
Hlo bro
@AnishGiri-fl8ws3 ай бұрын
@@aayushshah6783 can u please send me the source code
@TúHải-r8m3 ай бұрын
If everyone watches up to minute 45 of the video and cannot add to the three tables ( rooms,room_ facilities,rooms_features) then please review it CAREFULLY ; there is no mistake. I was wrong in the part: data.append('features', JSON.stringify(features)); data.append('facilities', JSON.stringify(facilities)); After reviewing it very carefully, keep it up, everyone.
@jheremiemagat3190 Жыл бұрын
hello, does anyone have this kind of problem "Uncaught mysqli_sql_exception: Cannot add or update a child row: a foreign key constraint fails ". I repeated the video many times but still cant figure out where i was wrong. please help. thank you
@ralpheco8903 Жыл бұрын
i have the same problem how did you solved it?
@jheremiemagat3190 Жыл бұрын
@@ralpheco8903 cannot resolve it til now, so i just remove the "Edit" action HAHAAH
@femiajao9082 Жыл бұрын
Please I need your kind assistance with this project source code.. Thank you
@gridsingh47058 ай бұрын
Hi, in MyPhpAdmin, at 42:11, you can modify the ON UPDATE setting to NO ACTION in any table (room_facility or room_feature) in the RELATION VIEW. In my example, the query shows up to have been executed successfully, but it then goes back to the restricted state. This issue only occurs when you select NO ACTION, but it does work for cascade. I tried Google, ChatGPT, and Stackoveflow, but I was unable to find a practical solution.
@gridsingh47058 ай бұрын
the CASCADE works fine too
@prashantchavan569611 ай бұрын
need help in code i am trying to delete feature & facilities but delete query not allowed to do it, Too many arguments to function delete(). 3 provided, but 0 accepted.PHP(PHP0443) this is the error
@ubgaming61202 ай бұрын
When i try to delete feature or facilities which are already added in room, i get server down alert instead of feature or facility is added in room . How can i solve this problem!!!! Plx help
@KazePz193 ай бұрын
Can't use the php code in the modal ,please help
@Hodophile_Albatross Жыл бұрын
Sir data is not added in database it shows server down plz help us
@femiajao9082 Жыл бұрын
Please I need your kind assistance with this project source code.. Thank you
@MrMATH-nn7cy4 ай бұрын
Watch video from 20 mint to 43 mint with full attention
@rcpoint933610 ай бұрын
Sir mujhe Active Aur Inactive Krne Pe Kuchh Ho Hi Nhi Rha Hai 55:29 Aur Node Not Krke Kuchh Yellow colour me console me error aa rha hai Please Help Me Sir I Hope You Are see my comments ❤ I Follow Your video from 1 to 14 please reply me sir I searched this problem at Google but not getting result
@AnishGiri-fl8ws3 ай бұрын
In 14th video in my case there was an error of foreach loop not a function. Please help me
@ViladaThammasack Жыл бұрын
at 20:02 why it doesn't show add_room_form.elements when i checked the inspect
@badattitude Жыл бұрын
25:49 me aapne run kiya magar muje us jagah :- Uncaught TypeError: add_room_form.elements.facilities.forEach is not a function
@scuti-lp6fl Жыл бұрын
same problem here
@femiajao9082 Жыл бұрын
Please I need your kind assistance with this project source code.. Thank you
@alvn.dwkyy229 ай бұрын
i have question why my stmt execute on q3 fatal error?
@ankursingh6518 Жыл бұрын
Sir aapne ne homepage jo search bar banaya hai use kis videos me dynamic kiya Jai maine sare video dekhe liye kisi ke dikha nhi
@jonathanfenoud-viard56362 жыл бұрын
Hello Great series of videos, is the series over or will there still be videos?
@AnishGiri-fl8ws3 ай бұрын
Ismain booking and payment ka system hai
@karandevendra52432 жыл бұрын
error mysqli object is already closed in ...how to solve
@XhyCorrea4 ай бұрын
Fatal error: Uncaught mysqli_sql_exception: Cannot add or update a child row: a foreign key constraint fails (`dolphins_hotel`.`room_facilities`, CONSTRAINT `facilities id` FOREIGN KEY (`facilities_id`) REFERENCES `facilities` (`id`) ON UPDATE NO ACTION) in C:\xampp\htdocs\Dolphins-Hotel\admin\ajax ooms.php:30 Stack trace: #0 C:\xampp\htdocs\Dolphins-Hotel\admin\ajax ooms.php(30): mysqli_stmt_execute(Object(mysqli_stmt)) #1 {main} thrown in C:\xampp\htdocs\Dolphins-Hotel\admin\ajax ooms.php on line 30
@jokerkhan7524 Жыл бұрын
i spend 5 hour to find error i write values instead of value hahahahhahaahah thanks Touseef sir i learn alot
@CR-wz4qs2 жыл бұрын
bro from where i can find or receive PPT of SYSTEM DESIGN AND ANALYSIS (your lecs playlist)
@muhammadusman-mh4og Жыл бұрын
can someone help me i have error regarding this lecture.
@sheikhmshoeboo72 жыл бұрын
Thanks bro
@AnishGiri-fl8ws3 ай бұрын
Hlo
@sheikhmshoeboo72 ай бұрын
@@AnishGiri-fl8ws hi
@abhishekpatil9875 Жыл бұрын
Ye selectAll function ka code kidhar he
@calebmaguling3042 Жыл бұрын
why when i click the edit button, the edit room modal didnt show up, and i cant interact with website?
@iqmalhaikal3352 Жыл бұрын
i got the same situation like u , are u ald solve it ?
@calebmaguling3042 Жыл бұрын
Yes, the structure of my modal have a missing closing div. Check your modal structure
@Its_nivas3 ай бұрын
for me to bro how to solve
@mahamedmuqtaar26952 жыл бұрын
Room availability page ,,like how many room in the hotel ,,how many booked and how many available
@akshaynagarwal2 жыл бұрын
Brother , at 1:24:51 How to start sr_no (serial wise) with 1 except 5 or other numbers in room_facilities table(both tables).✋
@binishabhattarai8895 Жыл бұрын
Sir did this project run
@akshaynagarwal Жыл бұрын
@@binishabhattarai8895 yes
@binishabhattarai8895 Жыл бұрын
@@akshaynagarwal do you have source code sir could you please provide me
@akshaynagarwal Жыл бұрын
@@binishabhattarai8895 plz try with owner.
@fierceromanova5502 Жыл бұрын
mera data edit nei horaha hai ....error kuch nehi dekha raha hai or kaha se error dhundu😂 error submit edit room pe else part dekha raha hai server down
@buriburizaymon51910 ай бұрын
Hii have you solve it?
@swez64 ай бұрын
Hi did u get for this one can you help me too
@swez64 ай бұрын
Hello please help
@fierceromanova55024 ай бұрын
I'm in home now not with my laptop ....after some day if you not solve this problem i will send my source code here....
@pemagyalpo50704 ай бұрын
@@fierceromanova5502 do u got the code bro, i need help in this section, my data is getting into rooms but not into the room_feature and room_faciliites table
@kasper93592 жыл бұрын
Hi can you make upload little more fast , my project submission date is coming closer
@nish01822 жыл бұрын
Data table me toh insert ho rha hai Par alert mein server down aa rha hai
@sanskarunkule2549 Жыл бұрын
same issue how did you solved it
@badattitude Жыл бұрын
sir aapke playlist se hi code kr raha hu magar error de raha he 1 jagah pr