Top 4 reasons why to improve Power Factor | TheElectricalGuy

In this tutorial, we’ll learn about the top 4 reasons why we should improve power factor. We’ll also understand why we should try to maintain the power factor for the system or machineries near to unity (1). So, let’s start.
#Power Factor #4reasons #Improve
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[@sudhaabi3864]

Clear brother. .thanks

[@kabandajamir9844]

So nice explanation the world's best teacher

[@nuwanweerakkody2985]

thanks a lot.

[@mahendharyadavbaira6063]

Great explanation with gun shot points by good clarity

[@jitendradas3776]

Thank you so much sir

[@TECHHABIBBD]

You are a best teacher

[@Er.amarjotsingh]

Great explanation 👌

[@GauravJ]

Glad you liked it

[@hamidjamili]

Thanks for the explaination, you are very understandable. keep it up.

[@ruutu.275]

Thank you very much sir, your video has given me more information for my project . Keep it up God bless you thank you 🙏😚

[@GauravJ]

Glad it was helpful 😊 do share and subscribe 😇

[@vijayanandikola6511]

Nice explanation sir Thank you

[@vaibhavpokale583]

Tysm sir now my doubt cleared..

[@mdfaruqajam2431]

Thank you sir❤️

[@mohamedkhalif1686]

Thanks alot

[@princechaudharyentertainme2250]

Great concept!

[@Bkh611]

Sir please explain transistors, and protection devices used in electrical systems

[@satyarout9377]

Sir u r great

[@dfggggcvv8184]

Great job

[@ajinkyayeolekar2082]

Utility ko kya nuksan hota hai low P.F. ka? Kyu penalty charge karte hai?

[@syedabdurrahman1537]

Great explanation sir

[@GauravJ]

Thanks 😊 do share and subscribe to my channel ✌🏻✌🏻😊

[@syedabdurrahman1537]

@@GauravJ already subscribed sir

[@dragan3290]

Heat kills power factor on Air conditioning unit when I tested at 0.7! When I spray outdoor Aluminium coils, power factor went up and then the current dropped. At 240 volts, 3 amps down to 2.7 amps. Power factor went up! Is this right? And does it make sense? Cheers from Australia just subbed.nice work 🙂👍👍👍

[@outsidelevel7790]

IN RAILWAY TRAIN THE CHARGING SOCKET IS 110V DC.. THE CHARGER TAKES 230V AC AND STEP DOWNS - 5V AC. & THEN IT USES RECTIFIER TO CONVERT AC TO DC IF I PUT MY CHARGER... HOW CAN IT STEP DOWN 110VDC - 5VDC.. AS WE CAN'T STEP DOWN DC HOW IS THIS POSSIBLE SIR

[@YadaYadaYadaYada]

Can you please elborated where the formula for the new current i.e. I subscript 0.7= P/Sqrt3 X v X PF came from? at 4:16 Thanks

[@10kchennal9]

Super sir

[@sunilkumar-zl9er]

Nice sir Hope you are providing vedio on how to improve power factor.

[@GauravJ]

Yes. Here is the complete playlist of power factor series- kzbin.info/aero/PL_Ht1_dWu2Yw7U4iVPGFkc6Xd_nW8QAi7

[@alibaba7190]

Sir please make on ring main unit

[@ambition221]

At the begging of your video you have mentioned that the apparent power is 200 KVA and the active power is 270 KW. If we divide the active power over the apparent power we will get P.F equal to 0.85, does that mean the actual P.F is 0.85?

[@mrida3017]

How utility can measure the power factor?? What I know is that they install a CT which feeds an Energy Meter which will calculate the total Kwh based on the current delivered from CT, please correct me if I'm wrong.

[@mooketsiselotate7471]

You are right sir Maximum and Commercial meter displays kavr, kwh, v, i, kva, kw etc

[@bharathnandagiri5894]

Super

[@vijayakumar_vk9135]

That's a nice video. But one quick question from 03:26 . If my 1HP motor takes 1.42 HP because of 0.7 pf, the utility can still charge me for 1HP only right..Because that's only consumed. Remaining power just flows back and forth without doing useful work and hence can't be chargeable.And thats the very reason why penalty is charged, right? and not like we charged for 1.42 HP taken . Correct me if I'm wrong.

[@TheKingmalik007]

your 1hp will comsume 1 hp only let us say 1KW, but the KVA drawn from the source is more than actual KVA needed.. as 1 KW=0.8 KVA, hence you are using more KVA than required, and you will be charged based on that.. and due to reactive power you are injecting into the TL, its efficiency reduces and losses are increased hence you are penalized too..

[@beaware9218]

hi sir what will happen power factor excesses 0.9 in the induction motor... after power factor correction ?

[@mooketsiselotate7471]

You are talking about pure resistive load such as heat element

[@basanthkp4095]

Sir, u didn't mention about how to improve pf for inductor loads?

[@mooketsiselotate7471]

By installing capacitor banks it is provide reactive power to the motor..

[@bhuvanakrishna1960]

Plz..answer to my question as soon as possible,as long as possible..reply.. -× Why impedence between the windings of transformer kept infinite...?

[@GauravJ]

Transformer with infinite impedance is not possible practically. In practical you will always find some resistance with inductive reactance. Basically it is done to reduce the short circuit current if in case two windings touches each other.

[@bhuvanakrishna1960]

Gaurav J ,hoo.. thanks guruji...do more videos...as Soon as possible... .

[@hamidjamili]

Sir Gaurav J i have a question please help me. Induction motors consume reactive power so why should power factor be close to 1? as you said in another video the closer power factor gets to 1, lesser will be the reactive power. so why less reactive power while our induction motors needs reactive power? thanks

[@GauravJ]

Yes of course, induction motor, transformer needs reactive power. As you have seen in the video, low pf means motor will consume more power from utility, and utility will give penalty for that. And hence to avoid this, pf of motor is increased and the required reactive power is provided locally by installing capacitor banks. The capacitors will provide required reactive power to the motor, and the electricity bill will be reduced.

[@hamidjamili]

thanks sir. your videos are outstanding!

[@GauravJ]

Thanks friend.. 😊

[@onyekaokoye5867]

Dear Hamid Jamili: Reactive power (RP) is of two sources: One, known as lagging, is produced from inductive loads(IL); the other, known as leading, is produced from capacitive loads(CL). Both are used to balance one another as a corrective measure. Thus, a RP from an IL is fed with a RP from a CL to correct it by balancing the effect. They characteristically always cancel one another. I hope this would help. Cheers!

[@hamidjamili]

@@onyekaokoye5867 thanks my friend

[@JafarA-mp6ls]

You have to understand pf pls

[@arun4846]

👍

[@vinayreddy8683]

Every thing is fine, but that background music is quite annoying

[@GauravJ]

I guess it is only for few seconds in starting. Is that annoying? which music you are talking about?

[@vinayreddy8683]

Gaurav J yaa the starting one....

[@GauravJ]

Okay sorry for that, I'll take care about it next time.

[@vinayreddy8683]

Gaurav J music doesn't matter before the knowledge you're sharing....by the way thanks for your wonderful explanations, it's really helpful

[@avantikaparihar1466]

Too slow

[@rubaiyaislam9322]

Boring lage go Bhai!

[@nikis7742]

You r totally wrong in power factor concepts plz go and research about it it's trap dear suppose that if you have 0power factor what would happen to system having induction motors can you think off 🤔🤔🤔🤔🤔