Total Kinetic Energy (Translational and Rotational)

[@TheNat2341]

Wow this is literally the best video - excellent explanation

[@NotTechLead]

Very awesome. You are incredibly clear and informative. My physics teacher has nothing on you.

[@AKLECTURES]

Robin Hood lol! thanks Robin! glad you found it helpful! :)

[@dhruvpaniker9661]

I wonder y u don't have more subscribers..... u r the best !!!!!!!!!man u r a great teacher!!!

[@christopherapuan9968]

Thank you for the knowledge. 😀

[@paulcohen6727]

Why do you use the parallel axis theorem about point B? If you observe point B's motion, it describes a cycloid and not rotation. Then, it seems that you switched from two rotational energies to translational and rotational kinetic energy to get the right answer.

[@arisnow1855]

Why point B? Because it's the instantaneous center? What about if you have a rod that's translating and rotating (about it's end and not about it's center of mass), could you use the end of the rod for I ((ml^2)/3) as point B as in your example? Or does point B have to be the IC?

[@amanuddin1896]

Why would the wheel rotate about an axis through the point B ?

[@JackChickenwing]

hi thanks for posting the vids. I dont unerstand the step from the ex from (1) -> (2) where I is substitued for (2/5)mr^2, where does the 2/5 come from??

[@AKLECTURES]

You're welcome! Thats simply the equation for the moment of inertia of a solid sphere!

[@JackChickenwing]

thanks!

[@suryadevkumar4887]

Nice sir, thank you so much.....

[@lailakc9288]

Amazing . Thanks

[@sahilllustrious]

Totally understand it ✌✌✌✌

[@sailawayteam]

Very clear explanation. But shouldn't the last eq. 5 be square root of 7gh instead of division by 0.7?

[@ritika9631]

Nice... I like it

[@robertkaranja3113]

What do you mean rotating about point B? I can't picture it... anyone else?

[@sarahminawi1875]

Same

[@ismail4842]

Thank you

[@nitish8659]

Its very nice vedio

[@bhavendrajha6460]

Thank you sir, always been confused about rolling object K. E, now got clear

[@headholio]

Ky-netic energy!

[@AKLECTURES]

;-)

[@dishant8126]

For all those poor souls in the comments . Moment of inertia is always taken about the same point *with respect* to which you have the body's angular velocity (w) and Moment of inertia is along an axis parallel to angular velocity (W) vector (it's an axial vector if you don't know )

[@emirhamarat3287]

Are u freak?

[@naion0]

Is there difference between total kinetic energy and total translation kinetic energy

[@anilsharma-ev2my]

Show the formula in stencil manner Your writing is not so good 🕉🕉🕉