TRANSMISSION LINE EQUATIONS - PART II - EM WAVES AND TRANSMISSION LINES PREVIOUS PAPERS

In this video lecture
1) Both exponential & hyperbolic Transmission line equations are converted into two constants
2) The constants A & B are determined from sending end boundary conditions

[@kudipudipraneeth8237]

7:40, sir differentiation cos x = -sin x khada.....but you won't wrote minus(-)

[@karthigajeyanthi2198]

sir transmission line equation - general solution ikkum video poduga sir

[@aruvantiabhinay5819]

Sir......you forgot differentiate - cos.....it is -sin..... At the last hyperbolic formula

[@udaykumar7380]

Sir if a question is asked to derive transmission line equation should we write total first video and second video sir..

[@MrPprasanna]

1st video is enough

[@udaykumar7380]

@@MrPprasanna Many many thanks for the reply sir I saved your total playlists and your videos are very very helpful in the exam times sir You are saving me from exams Thank you soo.. much sir

[@urFriend97]

Sir .....can we take ae^x + be^-x As ae^-x + be^-x As you have took different in 2 videos

[@MrPprasanna]

Take a*e^-x + b*e^x