RELATIONS - DISCRETE MATHEMATICS

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TrevTutor

TrevTutor

9 жыл бұрын

Looking for paid tutoring or online courses with practice exercises, text lectures, solutions, and exam practice? TrevTutor.com has you covered!
We introduce relations. How to write them, what they are, and properties of relations including reflexivity, symmetry, and transitivity.
#DiscreteMath #Mathematics #Relations
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Hello, welcome to TheTrevTutor. I'm here to help you learn your college courses in an easy, efficient manner. If you like what you see, feel free to subscribe and follow me for updates. If you have any questions, leave them below. I try to answer as many questions as possible. If something isn't quite clear or needs more explanation, I can easily make additional videos to satisfy your need for knowledge and understanding.

Пікірлер: 355
@sontath7102
@sontath7102 6 жыл бұрын
Thank you. You are literally the only person who can explain this in simple English it seems. My professor seems to get joy from talking in the most confusing, and ambiguous terms possible
@AZAZA19981907
@AZAZA19981907 5 жыл бұрын
It's not always their fault, usually they have limited time and try to provide you with the most accurate statements possible. Though I agree, it's much easier to graps a broader concept after learning the intuition and basic intetion of it on simple examples, i wouldn't be here otherwise :P
@foxxul
@foxxul 4 жыл бұрын
Try having a teacher who not only does that, but also has a thick Chinese accent.
@md123180
@md123180 4 жыл бұрын
@@foxxul My teacher only posts links to KZbin videos...and not Trev or Patrick... I may as well have the lady that designs suits from the Incredibles explaining relations backwards in Dutch while gargling peanut butter. Thank goodness for Google.
@viewerr69
@viewerr69 3 жыл бұрын
@@AZAZA19981907 The problem begins where the college teachers go after completing the syllabus instead of actually teaching. The bigger the difference between the score of best performing student and the worst performing student, the worse the teacher is at his/her job
@BillboMC
@BillboMC 2 жыл бұрын
Me 2 lol
@Trevtutor
@Trevtutor 9 жыл бұрын
x-y != 0 This situation is not transitive. xRy and yRz imply xRz. Consider the case 3R4, 4R3, therefore 3R3. We know 3R3 is 0, so the relationship isn't transitive!
@yeahboi8705
@yeahboi8705 8 жыл бұрын
well if you're given those specific values and are asked if their relationship is transitive you could say yes, but when given only x and y, their relationship must be transitive for ALL values of the given domain, or else its NOT transitive, even if 99.9% of the possible cases are.
@shawonshurid9218
@shawonshurid9218 8 жыл бұрын
thanks dude...
@Thegr8Gupta
@Thegr8Gupta 7 жыл бұрын
but if we say this relation for DISTINCT x, y and z, then it is transitive right?
@ward7576
@ward7576 7 жыл бұрын
Shouldn't it be that z != x to be more understandable in this scenario? 'cause I'm confused af why is it not transitive.
@rayrutzer7238
@rayrutzer7238 7 жыл бұрын
So x , y, z are not distinct?
@richardt.rogers2730
@richardt.rogers2730 5 жыл бұрын
"and if you don't get confused... I really hope you don't" haha thank you
@MuhammadIsmail-un3qd
@MuhammadIsmail-un3qd 4 жыл бұрын
he explained really well 😏
@MaxzeeKVO
@MaxzeeKVO 7 жыл бұрын
I got an A+ on my test.. you're awesome...keep it up 💪👍
@preciouslauranoriega4831
@preciouslauranoriega4831 4 жыл бұрын
Sana all
@nichol071
@nichol071 4 жыл бұрын
@@preciouslauranoriega4831 ito hinahanap ko eh HAHAHAHAHAHA
@preciouslauranoriega4831
@preciouslauranoriega4831 4 жыл бұрын
@@nichol071 HAHHAHAHAHA FILIPINNOOOOOOOO
@preciouslauranoriega4831
@preciouslauranoriega4831 4 жыл бұрын
@@nichol071 HAHAHA troo
@kenzgaming6398
@kenzgaming6398 4 жыл бұрын
@@preciouslauranoriega4831 pede paturo?? Naguguluhan paren po tlga ako..
@loremipsum5697
@loremipsum5697 6 жыл бұрын
i wish more teachers were like you. You make stuff way more intuitive and easy to understand.
@kallychicken7654
@kallychicken7654 2 жыл бұрын
i just started computer science at uni this year and i got recommended your amazing videos! They are so helpful, even if my main language isnt english i still managed to understand you easily and mathematics have their own universel language which helps even more. Thank you again
@dianna5619
@dianna5619 Жыл бұрын
I'm in Com Sci too!
@bassitirfan7446
@bassitirfan7446 Жыл бұрын
@@dianna5619 same
@krizh289
@krizh289 Жыл бұрын
@@dianna5619 same
@extremelyhappysimmer
@extremelyhappysimmer 5 жыл бұрын
11:42 "they want you to play with yourself" oh math, when did you become so enticing?
@leafslizer2376
@leafslizer2376 4 жыл бұрын
0:53 smoothest "L" I've ever seen your handwriting is so satisfying >.>
@Skyrim_Says
@Skyrim_Says 2 жыл бұрын
true
@rorydaines3176
@rorydaines3176 3 жыл бұрын
I was so stuck on transitive and your less than sign example just exploded a eureka, thanks a million.
@KillerKeeton
@KillerKeeton 11 ай бұрын
This is such a better explanation than my professor. Everyone in class struggled with the homework on this topic. This helped a bit
@DrewBrooksPB
@DrewBrooksPB 6 жыл бұрын
Glad I found your channel before finals! Wish I found it in August, will recommend! Great stuff, thank you!
@ndumisomaseko9633
@ndumisomaseko9633 Жыл бұрын
How's your exams go?
@JP-xm3qf
@JP-xm3qf 5 жыл бұрын
You are an excelent Prof., thank you very much, it was very clever to introduce the logic tables on the symmetric relationship.
@groundg8397
@groundg8397 3 жыл бұрын
Hey, I just wanna let you know that this video helped me so damn much. Thank you very much, you have no idea how good it felt when I finally had that eureka moment after many weeks having no idea what my professor was talking about. Keep doing what you're doing bro.
@mariageorge7600
@mariageorge7600 3 жыл бұрын
Your explanation is so easy to understand. Hope our Professors could teach as good as you.
@28Graysonvb
@28Graysonvb 5 жыл бұрын
The diagrams for reflexive symmetric and transitive help SO much.
@MyCyberAcademy
@MyCyberAcademy 8 жыл бұрын
Excellent video! Thank you!
@williamcordova7065
@williamcordova7065 4 жыл бұрын
Thank you for putting these tutorials together for all of us that struggle with Math. Very appreciated
@amosmaggy5020
@amosmaggy5020 3 жыл бұрын
Thank you for the tutorial...seems like you are the only one who can help me understand what my lec teaches me☺☺
@jingu127
@jingu127 3 жыл бұрын
u save me while I'm studying last minute for my midterm tmr 🤦🏻‍♀️ thank you so much
@HK-no9wm
@HK-no9wm 6 жыл бұрын
Extremely helpful. Thank you.
@ekleanthony7997
@ekleanthony7997 3 жыл бұрын
I love your course, the explanation is powerful..
@djtygre
@djtygre 3 жыл бұрын
Awesome vid as usual. Thank you for all your help.
@personaincognita2669
@personaincognita2669 2 жыл бұрын
A correction: every function may also be represented as a relation (i.e., as a subset of a Cartesian product), but not every relation is a function. Just think of a simple relation like a total order on a set and you will see that a given argument in a relation may be related to many other arguments and does not have to be related to an exclusive output as a function does.
@fatumeshalla5686
@fatumeshalla5686 2 жыл бұрын
wow , I spend so many hours understanding this but you are awesome !!!
@j.jehml.1446
@j.jehml.1446 Жыл бұрын
it is criminal that a 15 min yt video explains this shit way better than 2 hours of lectures at a uni im paying to go to
@lh5573
@lh5573 7 жыл бұрын
That was brilliant! Thank you so much!
@ikeikeikeikeikeikeikeike
@ikeikeikeikeikeikeikeike 5 жыл бұрын
You my man, are fantastic, please never stop haha
@astraadamskhan1399
@astraadamskhan1399 8 жыл бұрын
play with your self......:) more teachers should be like this
@Trevtutor
@Trevtutor 8 жыл бұрын
+Astra Adams Students who want to play with themselves are encouraged to sit in the back of the room with other students that want to play with themselves, that way they can play with each other instead ;)
@CharlieJ2588
@CharlieJ2588 7 жыл бұрын
I thought I was the only one that caught that xD
@tF6U
@tF6U 7 жыл бұрын
TheTrevTutor Dawg wtf I was tryna understand discrete math but here you are making sex jokes. Smh math nerds wildin' these days
@Kevessi
@Kevessi 3 жыл бұрын
TheTrevTutor omfg lol
@animejacker4218
@animejacker4218 4 жыл бұрын
Am really grateful 🙏 your explanation was superb , it really helped me , thanks sooo much , looking forward to more of your videos 😊
@jenicawoitowicz8895
@jenicawoitowicz8895 6 жыл бұрын
Thanks for the video! Better than my university prof.
@Start-upsandinvestment
@Start-upsandinvestment 6 жыл бұрын
hi dear.
@juanbecerra5073
@juanbecerra5073 6 жыл бұрын
Great video! Helped me cram for my final
@jeremyedbert5092
@jeremyedbert5092 4 жыл бұрын
I'm from Indonesia, and I appreciate this one... Love your explanation
@Carrymejane
@Carrymejane 4 ай бұрын
Aku telat nih 😁
@mamo987
@mamo987 2 жыл бұрын
you and people like organic chem tutor are god sends
@diegovasquezrevilla
@diegovasquezrevilla 3 жыл бұрын
Great work! Cheers from Spain and Perú
@Carrymejane
@Carrymejane 4 ай бұрын
This is a very good explanation for basic introduction, for one that doesn't learn them at othe sources.
@edemcudjoe5053
@edemcudjoe5053 3 ай бұрын
9 years and it's still very comprehensive
@Paul-P
@Paul-P 7 жыл бұрын
the inflection in your voice at 13:20 so excited about math lol.
@siddharthuzumaki6830
@siddharthuzumaki6830 2 жыл бұрын
That's nice, You are helping me so much right now.
@abdullateefidris-jf3ub
@abdullateefidris-jf3ub Жыл бұрын
Thanks 👍,I really understood the relations concept
@goodnightvids
@goodnightvids Жыл бұрын
amazing now i finally understand thanks!!!
@nouraaliabuhlega4023
@nouraaliabuhlega4023 6 жыл бұрын
you r super hero ,, u saved me thanks
@xsba7
@xsba7 5 ай бұрын
was struggling so harddd thankk youuuuuuu
@sulafafaleh9297
@sulafafaleh9297 5 жыл бұрын
Your channel helps me a lot thank you very much 😍😊
@WftYT
@WftYT 3 жыл бұрын
So clear thank you. I don't know why my professor is turned on by using such big words. Your explanation was clear and easy to understand.
@benukhanov960
@benukhanov960 3 жыл бұрын
This guy is a fu*king genius. He explained everything so simply.
@harindudilipa1559
@harindudilipa1559 4 жыл бұрын
Sir this helped a lot thanks a lot❤️
@Oskar-ps1dr
@Oskar-ps1dr 7 жыл бұрын
What about Irreflexive and antisymetric?
@XXgamemaster
@XXgamemaster 5 жыл бұрын
Oskar Midbøe A relation R on a set X is antisymmetric if and only if x R y and y R x implies x = y. A relation is irreflexive if and only if every point x is not related to itself. An example of this is inequality since it’s illogical for an element say x to be not equal itself.
@mohameddoudou3285
@mohameddoudou3285 4 жыл бұрын
@@XXgamemaster i appreciate that replay, thank you
@knanzeynalov7133
@knanzeynalov7133 2 жыл бұрын
Thank you for the awesome explanatory videos! I have been preparing for my final exams by watching your videos. I hope I will pass the lesson.
@071aleksandra
@071aleksandra Жыл бұрын
Oh wow! You are a star, keep doing this.
@anubhabchakrabortybkppathf6819
@anubhabchakrabortybkppathf6819 8 жыл бұрын
In which video can I learn more about equivalence class and relations?
@benlewis-jones6719
@benlewis-jones6719 3 жыл бұрын
the first video that is very good on this topic 👍
@sulafafaleh9297
@sulafafaleh9297 5 жыл бұрын
What about Anti- Symmetric and irreflexive relationships?
@Kwatch
@Kwatch Жыл бұрын
i like that you use different collor for each section. it makes things much easier to swallow
@jemand1685
@jemand1685 2 жыл бұрын
Thank you for the Video
@The6thProgrammer
@The6thProgrammer 7 жыл бұрын
When determining reflexivity, symmetry, and transitivity at 11:31. Could we analyze x - y != 0 as x != y instead? Just seems like it may be a simpler approach. Do you see anything wrong w/ that approach? I noticed you actually worked out x != y at the end of the video. My question is: is there anything wrong with manipulating the variables around the operator? I'm assuming this should not change reflexivity, transitivity or symmetry. (i.e. x - y + z = 0 is the same as figuring out the relations of x = y - z, etc.)
@Trevtutor
@Trevtutor 7 жыл бұрын
There's nothing wrong with that. In fact, it's easier to understand x != y rather than x-y != 0 for this kind of question, so the fact that you were able to change that and work with it better is a good thing.
@elkanacapelle5701
@elkanacapelle5701 5 жыл бұрын
thank you so much really help alot
@wudayskitchensaffloho6421
@wudayskitchensaffloho6421 6 жыл бұрын
hi i love your videos and requesting if you can make a video on relational closures
@rajeshdansena
@rajeshdansena 6 жыл бұрын
At 15:05 for proofing it is not transitive you took x and z same. don't you think it's wrong to take same value ? All x,y,z must be of different values? If you still says we can take same values for x and z then in that case, for symmetric property we also can take x and y same and which will say (let) 2=2 and hence it do not hold symmetric property as well. Appreciate you response on my query. Thanks. You are doing awesome job :)
@joanneyuen6308
@joanneyuen6308 6 жыл бұрын
thanks! it helps a lot :)
@oshadayasiru6224
@oshadayasiru6224 2 жыл бұрын
Thank you, Very usefull
@bagochips1208
@bagochips1208 2 жыл бұрын
god my college discrete math course was so bad that straight up skipping the lecture and only studying the slides and videos like you got me better grades
@triscuit5962
@triscuit5962 4 жыл бұрын
About to take a discrete structures test, wish me luck!
@marvinrichardson2668
@marvinrichardson2668 8 жыл бұрын
Set of all integers where (x,y) is in R. xy>1 is it ref , symm , trans or anti? Could you help me understand more of this? I answered symmetric for this one and I got it correct. e.g (4 2) (2 4) > 1 but what about say (1,0) (0,1)? Also, why can't it be reflexive? like (2,2) but we can't have (1,1) (0,0).
@leulteferi285
@leulteferi285 2 жыл бұрын
Thank you
@javiermelendrez5763
@javiermelendrez5763 7 жыл бұрын
thank you!
@Bryanbro
@Bryanbro 3 ай бұрын
In the example x-y=!0, I assume you don't include negative numbers? Because then the relation would not be symmetric right?for example pick x to be -y?
@Pandzi
@Pandzi 2 жыл бұрын
Thanks fir the help
@castlemagic4746
@castlemagic4746 2 жыл бұрын
11:44 Play with myself? Set Theory doesn't get me quite that excited... Great videos tho man. Thanks.
@rosesofficialhusband5728
@rosesofficialhusband5728 2 жыл бұрын
I would like to know what app are you using for writing things Trev!
@AvarLalo
@AvarLalo 3 жыл бұрын
Hey, i just wanna know at the end of the video for transitivity, why do we choose x=2, y=1, z=2. What if we choosed x=2, y=1 and z=3, wouldnt that make it transitve?
@buensons
@buensons 5 жыл бұрын
0:40 Not all relations are functions....
@kingneo4186
@kingneo4186 4 жыл бұрын
Yea! All functions are relations, but not all relations are functions. How could he say this? OMEGALUL
@divyanshigupta1568
@divyanshigupta1568 3 жыл бұрын
Yes
@WhiskeredBope
@WhiskeredBope 2 жыл бұрын
"Cool it with the anti-symmetric remarks!"
@kingstonmocktail7744
@kingstonmocktail7744 4 жыл бұрын
So for a set like this {5,10,15,20 ......}, could you say that it follows a relexive relation? Because each element is related to itself?
@divitasharma
@divitasharma 3 жыл бұрын
Can u pls tell the software u used here. I found it great
@michaelkievits7073
@michaelkievits7073 6 жыл бұрын
you are great!
@azadalmasov5849
@azadalmasov5849 5 жыл бұрын
Thank you for your explanations of these kind of intuitive abstract stuff. I heard you saying relations are functions but isn't it vice verse?
@IStMl
@IStMl 4 жыл бұрын
Actually not all rel are functions
@farrukhsaif108
@farrukhsaif108 2 жыл бұрын
@@IStMl Exactly, but the professor said at the beginning of the video that relations are functions
@philosophyversuslogic
@philosophyversuslogic 4 жыл бұрын
The last example doesn't work when (xRy, yRz -> xRz) and x=z. For instance, 1-2 doesn't equal 0, 2-1 doesn't equal 0, but 1-1 equals zero.
@JamesHanzimanolis
@JamesHanzimanolis 7 жыл бұрын
Nice video!
@kk999la
@kk999la 8 жыл бұрын
for set like R={(2,3),(3,2), (5,4)} can i say it it symmetric becuz it contains 2,3 3,2...but what i confused is it doesn contain (4,5)..but hv (5,4) ..so it is symetric?
@TharanaMayuranga
@TharanaMayuranga 7 жыл бұрын
thanks a lot
@alberteinstein983
@alberteinstein983 Жыл бұрын
hello identity relation is what he explained in the place of reflexive! reflexive relation's are those in which elements are related to themselves, also they can be related to any other element! peace out.
@rudyeilabouni
@rudyeilabouni 7 жыл бұрын
I'm kinda struggling with this question I have... It's about Hash functions... SHA64 to be specific... It goes like this: We have a set of S which is a random long String combination (Cardinality is infinity therefore) and another set of Hex64, which consists of the Hexadecimals {0,1, 2...., 9, A, B, C, D, E, F) and this function takes any String input and generates a 64 digit long hexadecimal number from that string... However, because there are infinite input possibilities, however limited output possibilities (16^64 to be specific) there are bound to be "collisions" and that is when you enter 2 different strings but get the same output... and now my question is this... The following relationship is defined so: s1 and s2 are elements of S and are related as such: s1~s2 : Hex64(s1) Hex64(s2) So it's basically saying that 2 different strings are related, when they cause a collision and it's saying that this is an equivalence relation, and I have to show: a) How this is reflexive b) how this is symmetric c) how this is transitive Now I understand it in principle, but I'm not sure how to do it mathematically....
@vanessamariemanalac3105
@vanessamariemanalac3105 3 жыл бұрын
How do you identify the relation R? Our prof said the condition or formula is x+y divided by 2 and the answer must be an integer. But I am just quite confused bc he gave us a problem to answer but the domain(x) is a vowel and the range(y) is a number. But the formula said that the answer must be an integer to say that xRy. But the set contains vowel and a number, for example (a,2). So my question is can (a,2) be aR2? Hope you can answer my question even after 5 years. Thanks in advance😊
@theezakjezuyd8221
@theezakjezuyd8221 5 жыл бұрын
On the Transitive relation part, what do you do if you only get 2 variables? i.e. (x > y + 1)
@moatazahmed2771
@moatazahmed2771 5 ай бұрын
you don't think of it like that, transitive Rel. means if x relates to y and y relates to z, then x relates to z, and it is just a property, i.e. It doesn't enforce that, you check for that, if x relates to z then it is transitive otherwise it isn't
@shwetakhadse7522
@shwetakhadse7522 7 жыл бұрын
identity relation is both symmetric and antisymmetric?; can u give more examples for antisymmetric relations?
@bradfin12
@bradfin12 Ай бұрын
Wouldn't it be a type error rather than a syntax error? If function expects input int int and receives float int?
@urmomispeng1997
@urmomispeng1997 7 жыл бұрын
Ily still thanks for the help :)
@sethmuange9207
@sethmuange9207 3 ай бұрын
I have a question concerning the last equation what if you changed z to 3, wont the equation be transitive
@semitones9106
@semitones9106 6 жыл бұрын
Im not really understanding 11:08 you said 4-4!=0 is true because it being false makes it true. Can you clarify this for me some more? Does that only happen in a transitive case and is it like a rule that has to be memorized?
@needlermasta
@needlermasta 6 жыл бұрын
en.wikipedia.org/wiki/Material_conditional#Truth_table Suppose I say: "If I go to the store, I will get eggs." The only time that statement is definitely not true, is when I go to the store and I DON'T get eggs, T -> F. If I don't go to the store, I can't lie.
@suchithrasuchithra7991
@suchithrasuchithra7991 5 жыл бұрын
This is vacuous truth. Implication is false only when the premise holds and the conclusion does not. If the premise is false, the implication is true no matter how absurd the conclusion is!!
@wanoyua8630
@wanoyua8630 2 жыл бұрын
you made a comment on symmetry: "if the first part is false, then the whole thing is true". Does this logic also apply to the antisymmetric property?
@nadianoormohamed4432
@nadianoormohamed4432 7 жыл бұрын
not all relations are functions as implicitly stated in your video. Apart from that great video, thanks.
@churchillobiakalusi1593
@churchillobiakalusi1593 Ай бұрын
I think the answer for the exercise question is false. If X-y ≠ 0, and y-z≠ 0, it’s doesn’t necessarily mean x-z≠0… For example, when X= 2, y = 1, and z = 2, 2-1≠0 (true), and 1-2≠0(true); however, 2-2≠0(false). Therefore, it isn’t transitive.
@hta-bi249
@hta-bi249 6 жыл бұрын
in the last example where you said it's not transitive but (x not=y and y not = z implies x not =z SO T and T should imply T) so it should be transitive shouldn't it ?
@birengesobemerdine1521
@birengesobemerdine1521 2 жыл бұрын
sufficient explanation
@Jessedegans
@Jessedegans 4 жыл бұрын
What? This guy is a mind reader and a math god ?!?!?!
@stephaniewainaina4150
@stephaniewainaina4150 3 жыл бұрын
What if at 2:01 (x,y)is an element of natural numbers iff instead of x is greater than y it is x
@keka54321
@keka54321 5 жыл бұрын
In the example when x-y != 0 10:00 It seems as if it's not symmetric, contrary to what is said in the video, because if you pick x as (-3) and y as (3) you get : '(-3) - (3) != 0' imply '(3) - (-3) !=0' which in the second case is false. Have I missunderstood something?
@twinklerambhia3236
@twinklerambhia3236 2 жыл бұрын
Both the sides are true , they both are not equal to zero hence by going with the logic truth table of implication the final truth value is true which means it is symmetric for this very example.
@SrgntLoveGaming
@SrgntLoveGaming 6 жыл бұрын
So, was x-y =/=0 transitive? I can't seem to find a counterexample, nor your solution in the description or the comments.
@Trevtutor
@Trevtutor 6 жыл бұрын
Not transitive. If it were, then 1-2 != 0 and 2-1 != 0 implies that 1-1 != 0.
@MonkoGames
@MonkoGames 3 жыл бұрын
is there a relation that is reflexive and symmetric but not transitive
@xkillalex
@xkillalex 7 жыл бұрын
You saved my grade ;'D
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