Thank you for the helpful video! I had a little trouble at 6:00 but i realized that all you were doing was rearranging (e' = e - 1) and (v' = v - 1) into (e' + 1 = e) and (v' + 1 = v) and then plugged it into the earlier equation (e = v - 1)! It probably took me a bit because I am just a visual learner and I needed to see all the steps. (I'm also typing this out just in case anyone else has the same issue as me later on!)
@DavidPrice-k1g5 ай бұрын
Probably also worth reiterating that this is a proof around the theorem e = v-1. The final part of the proof begins from where e=v-1 is written. e' + 1 which is equivalent to e = v' + 1 which is equivalent to v then we - 1 (which is representing our hypothesis of e = v-1). Think of each line as a edging together closer and close to the proof. Note the +1-1 cancels out and we are left with e' + 1 = v' which essentially says for a tree if you need the number of vertices add 1 to the number of edges. In the final line we are essentially delivering the final proof statement that if we know the previous (for a tree if you need the number of vertices add 1 to the number of edges) then it is fair to conclude if we remove 1 from the total vertices we are left with the formula e' = v' - 1 essentially finishing the proof that to get the edges we deduct the 1 from the number of vertices. Sorry for the bad english I am at home sick.
@badass24858 жыл бұрын
These tutorials have really been very helpful! Thank you sir for explaining the concepts and making them crystal clear! I'm really surprised of the fact that u just have 15k subscribers u seriously deserve to have a lot more.
@jagritiyadavv4 жыл бұрын
114k now :)
@andromedaghostgames2 жыл бұрын
@@jagritiyadavv 209k now
@mvsdprosniper2 жыл бұрын
@@andromedaghostgames hey babe
@tasfiatabassum51308 жыл бұрын
thanks a lot, it really helped me, thank u for giving so much of time in teaching all these topic.
@shoukathali17682 жыл бұрын
I like everything bout this channel except : he doesn't make playlists and I can't find the order to watch the videos.
@hanyi58678 жыл бұрын
if e >= 1 shouldnt there be at least two vertices instead of one?
@shubhochowdhury68984 жыл бұрын
It is not possible to create a tree with one vertex.
@lyndongingerich14824 жыл бұрын
@@shubhochowdhury6898 Why not? A single vertex is a connected graph with no simple circuits.
@wolfcompany24 жыл бұрын
@@lyndongingerich1482 Thats a loop, itself is a circuit... special type of circuit
@lyndongingerich14824 жыл бұрын
@@wolfcompany2 Interesting. Thanks!
@dacianbonta28403 жыл бұрын
@5:16 Whif the vertex has more than one edge coming outta it? well, the graph disconnects, but proving THAT complicates things. better unleash Euler's Bazooka (v-e+r=2, with r=1). giving the desired answer. I mean, what's the use of developing Euler's Bazooka (moar like Euler's Panzerfaust, amirite) if you don't use it?
@anakinkylo.thepomenerianan90842 жыл бұрын
Awesome you can also use Eulers formula to prove a tree has n-1 edges since the region is 1(infinite space) and trees are planar r=e-v+2, r=1 & v=n . However I like the way you proved it makes more senser
@valeriereid23377 ай бұрын
Thanks for this.
@benjaminandersson2572 Жыл бұрын
3:01 Do you mean cycle? Or is loop = cycle in your terminology?
@ericgill18126 жыл бұрын
Hey man, what if you delete a vertex with a degree of 2? Doesn't that throw the proof of e=v-1 out of whack? Thanks
@Trevtutor6 жыл бұрын
But then you would have an isolated vertex below it (the deleted vertex's daughter) and thus it would no longer be a single tree.
@ericgill18126 жыл бұрын
Of course, thanks for your reply!
@tomh66674 жыл бұрын
@@Trevtutor That's true, but you glossed over that a bit. The proof didn't seem very robust as a result, IMO. I realize that you have limited time in a video when you're trying to cover material, but just trying to throw out some (hopefully) constructive criticism.
@maheshkumargupta80416 жыл бұрын
Show by means of an example that a simple diagraph in which exactly one node has indegree 0 and every other node has indegree 1 is not necessary a directed tree?
@hinaafzal12547 жыл бұрын
Thnx for uploading all of ur videos are like diamond to me..thnx it helped a lot
@tryingtolearn29668 жыл бұрын
I am having difficulty with the proof by induction. The basis step talks about |e|=0. and then you show that if the property already holds for some tree, then it'll hold for a **smaller** tree. But this is not the same as the "k+1" step. for this proof to be complete, don't you need to start from the largest possible tree instead of the smallest possible tree?
@Trevtutor8 жыл бұрын
You show that it holds for the smallest possible tree (e=0), then for some arbitrary e=k+1, you show that it can be broken down into components e
@tryingtolearn29668 жыл бұрын
Thanks! I am still a bit confused as to what is going on around time 6:05. The way I understand it, is that you apply the induction hypothesis to the bigger tree (using e'+1), and from that, you show about e'. by the way, my I ask which tools you're using to produce these beautiful videos? software? devices?
@commenting0004 жыл бұрын
@@tryingtolearn2966 Really, it's just that if you assume the tree you're working with is consistent with e = v - 1, then by removing an edge, the resulting tree also seems to show the same properties. All you need to do is prove that this resulting tree actually does follow the hypothesis, and to prove that, you just need to remove an edge from it and prove that the next tree also follows it. Eventually, you'll stumble upon the base case tree that has already been proven to have the wanted consistency, which creates a chain reaction. Remember, all trees start out with 1 vertice. By adding an edge, you must also add a vertice that it will connect to, keeping the degrees of each individual vertice = 1.
@maheshkumargupta80416 жыл бұрын
How many different directed trees are there with three nodes ????