Tutorial on if, else and else-if (elif) conditions

[@avenumadhav3568]

#1 Find whether the given number is odd or even: 0:23 #2 Find whether the given number ends with 0 or 5 or any other number 7:43 #3 Find the grade of students based on given marks 8:41 #4 Convert given flowchart into Python Code 20:22 my code: #1 i = int(input()) if(i%2 == 0): print('even') else: print('odd') #2 num = 0 if (num % 10 == 0): print(0) elif (num % 5 == 0): print(5) else: print('other') #3 marks = int(input()) if (marks >= 0 and marks =90): print('A') elif (marks >=80 and marks =70 and marks =60 and marks

[@YasirKhan-mb1iy]

sir, which book is used for the tutorial? or if can suggest any good book for python,which have problems to solve with python?

[@ojasmehrotra2821]

For q2, is this method an efficient method to do the question or is it more prone to mistakes while programming? n1 = str(input("Enter a number- ")) n2 = n1[-1] if (n2 == '0'): print ('The number ends in 0') elif (n2 == '5'): print ('The number ends in 5') else: print ('Other output')

[@raj_patel]

Thanks Bro

[@MUTHU_KRISHNAN_K]

Nice I think,we can even avoid mentioning the 'str' explicitly 😊👍

[@sayanghosh6996]

6:30 why do we need another if statement? Why cant we simply print num%10 ? Seems a simpler solution to me.

[@armanbothra118]

rint("enter a number") n=int(input()) if(n%5==0): print("number ends with 0 or 5") else: print("the number is not end with 0 or 5")

[@thamizhan_on_yt]

What is the text editor you use sir?

[@SSCTechInsights]

which key is used for right alignment of all the selected text ?

[@PriyaSingh-ex8ps]

print('Travel Fron Indore To Delhi') Time=int(input("Enter maximum no of Hours you have to reach to Delhi ")) Time_Longer=8 if(Time

[@nikulpd8137]

sir, for question 2 what if i do it like, a=str(input('enter the number: ')) if(a.endswith('0')): print('0') elif(a.endswith('5')): print('5') else: print('other') is it okay?

[@MUTHU_KRISHNAN_K]

Nice I think,we can even avoid mentioning the 'str' explicitly 😊👍

[@kajukatli9985]

#code by divyankpapa print('start') print('travelling from Bhopal to Delhi') time=int(input('enter travel time:')) #minimum travel time should be greater than 2 hours if(time>=2): if(time=3000): if(3000=150): if(150 =450): print('take train') else: print('invalid amount') else: print('invalid input') print ('thank you')

[@054_nirajkumar3]

थैंक्यू

[@akarshk1]

Whats up man I see your THANK YOU comment on every video LOL

[@snehamukherjee9800]

@@akarshk1 true XD

[@MilanoMine2002]

Now are u in which term? Of iitm ​@@snehamukherjee9800

[@DHEERAJSINGH-b9e]

what is longer here??

[@shayanchakraborty5761]

Why am i getting a syntax error in the first if statement with the following code? Can anyone please point out the mistake? print("Enter the marks: ") marks=int(input()) ( if(90

[@induvardhan_m]

Look at the open parenthesis before if block and make sure to use nested if only for the second check i.e, it works only for AND operations not for OR operations.

[@induvardhan_m]

Look at the open parenthesis before if block and make sure to use nested if and only if there is a second check i.e, it works only for AND operations not for OR operations.

[@ishu7891]

you are using the else condition without its "if" part which will be if(marks>=0 and marks

[@steveraphaelpulikottil5755]

( not required before & ) " " after if statements, respectively

[@umarulf]

nd cool