Residue Theorem to Calculate Inverse Z-Transform

[@TutorialsPoint_]

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[@adityaanand7185]

Mam if mod z greater than 1/2. Then we consider only z=1,z=4. No need to take z=1/2

[@Infanuu]

at 8:16 magnitude becomes -2/3

[@hero-ep3zm]

Isnt it -2/3 ?????

[@sravanimadimi776]

Same doubt mam

[@gandrakavya8201]

Mam taken magnitude of -2/3

[@saranraj2028]

Magnitude can't be in negative. That’s why the magnitude is 2/3

[@hunkokoesejiro526]

The final answer should be -2/3

[@PetBuddies]

that's probably a typo brother, do you realize how helpful her videos are for us, this is no big deal, brother... happy learning

[@nikitakotkar3490]

Mam, u forgot to write - sign at the end.

[@saranraj2028]

Magnitude can't be in negative. That’s why the magnitude is 2/3

[@planckx8328]

thank u girl i dont even know, very helpful

[@meghrajchiniya6539]

for mod z>1/2 why shuld i consider 1/2 ? only 1, and 4 enough

[@nqobizithamathuthu1397]

great explanation

[@sudheerreddy8289]

How to calculate n value if there are not given in question??

[@ramyanaidu7569]

If n* value is not given ? What will we do ?

[@aqibdawood9080]

the eqn of n is your final answer

[@sudeshnaguharay5187]

Mam if there is a pole of order greater than 1 than how to compute such ques(s)?

[@hiteshchoudhary9871]

Usko bhi nahi ata

[@darshanbndarshu1465]

calculate the inverse z transform of the following X(Z) = z( z²- 4z+5)/(z-3)(z-2)(z-1) ROCs:2

[@swetashalini5739]

What if pole is in the form.of (z+1) ? Should we follow the same procedure?

[@narendramuthireddi2511]

Excellent madam👌👌

[@pedropggPP]

I'm sure the explanation is good but I hardly understand her accent