Electro Magnetics - Numerical on Smith Chart

Electro Magnetics - Numerical on Smith Chart
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Lecture By: Mr. Hari Om Singh, Tutorials Point India Private Limited

[@TutorialsPoint_]

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[@ajayrajan8882]

"Nothing" but a good explanation

[@mountainmanws]

Fantastic refresher. Many thanks. I haven't touched a Smith Chart in years.

[@divyadharshini1337]

Sir,you have explained very well and Thankyou.

[@pallavipimpalkar8915]

lmao, the arbitrary circle looks like a perfect ellipse. Excellent explanation btw.

[@satyanarainu]

It is now become nothing but Easy. Thanks a lot bro

[@shreshthgarg4649]

great video sir.....

[@Wanderlens143]

Thank you so much sir 😌

[@suhelsuhi3214]

How to take lamda values canu explain it clearly please

[@raphaelisango2027]

very helpful explanation

[@sagargodase5182]

Thank you sir...!!! Made my day...!!!

[@dr.einstein5981]

Very helpful I was very worried about Smith chart thank you ♥️😊

[@srinaath9845]

Sir thank you so much... Very helpful for students like us

[@peace8461]

Thanks a lot 😵‍💫

[@Peolorios]

I counted around 50 Nothing but in this video, personal record for my guy

[@singhpankaj7330]

we counted 208 ''correct'' in our college lectures....that too in 50 minutes ....correct

[@Gabriel_Naomi]

you are great

[@srihita999]

Very well explained sir....thank u

[@56ur4]

Nothing but thank you kind sir

[@deepikadeepu1107]

Great thankful to you sir for ur wonderful explanation 🙏

[@akhilbabu5242]

Thank you so you had made my day

[@vijaykhati349]

Great lecture

[@subhashrajbhandari4673]

I got to know nothing but something but nothing. I wanna say nothing but thank you

[@josephkiula7752]

Thanks Mr

[@KarthikeyanJayasankar]

Very useful, thank you

[@thavarchandradamor9860]

Thank you very much ..bhai

[@saranshsaxena3956]

Thanks mate. Much appreciation.

[@AnilAgrawal]

Nice! Can you please let me know what whiteboard you are using and what projector and app you are using to project slides and be able to erase and change slides? Awesome!

[@akshitgaur7736]

chusna padega pehele

[@Cookiee-itsme]

Actually input admittance u have obtained in smith chart is normalized in order to get input admittance divide with characteristic impedance

[@shwetahegde8850]

Thanks

[@chriscarlo786]

Great videos thank you!!

[@spiritualguru9050]

Good expalaination sir

[@mageedtelgani9671]

Tank you

[@001Reegan]

thank you very much dude. its really a good job. i really appreciate.

[@potterwithanindianaccent2433]

nice lecture mahn

[@soinc1158]

Great thanks

[@mustaphaalkhafaaf5512]

yoo are better than 10000 idiot university lecturers who just want to finish their lecturers and get paid ... just for the sake of ther salaries ... well done and a lot of respect

[@vyuvaraj8633]

Good

[@kaverimediboina6257]

Tq sir nice explanation

[@supreethavula7891]

Ichi padesnav kali💯👍😂

[@veereshbandi275]

Awesome

[@dineshsrikar4235]

Thanks ra

[@anwarhussein3248]

You have done Very good job explaining sir.

[@soumyodeepghosh3852]

they should put a "nothing but "counter

[@tech_queue]

point 1,0 is any arbitrary point point taken for the center of circle

[@josegeorge6950]

Nice sir

[@muhammadafzaalkhan9277]

How to find normalized input admittance and normalized output admittance on smith chart

[@PriyankaVerma-ld6wx]

why u take axis (1,0)

[@eppadivya8534]

If do you know the answer plz rply me..

[@sindhushankar3147]

reactance circles passes through (1,0) axis

[@SHREEdharSimple]

Super Sir

[@_KTharun]

If the length is not in terms of lamda What should we do..!!

[@aswanthm8679]

How to get the value of input impedance after marking it in the circle

[@muhammadirfanullahkhan7525]

you mean how to find 0.24 and 0.4j So after marking the circle there is a resistance circle and 0.4j is reactance circle so these circle intersect each other at that point.

[@AKLESHKUMAR-dr3vm]

we want 3.3 lambda so we should add (0.135+0.165)*lambda=3.3*lambda approximate???.why are you want 3.43 *lambda sir??

[@mounikaavula8953]

I can't understand input impedance calculation how to write 0.3 value please apload another vedieo sir

[@pradeepkaushikrex8092]

👌

[@Sidhiq.10]

👍

[@aparajeetaguha4237]

why did you consider 1,0 as centre ?

[@aman5655]

Why u draw a circle (1,0)

[@rohitreddy1039]

point 1,0 is any arbitrary point point taken for the center of circle

[@wristcutters4539]

if Zin is given, is the procedure to find ZL the same?

[@aravind1002]

How to draw VSWR circle ??

[@spiritualguru9050]

The point at which load impedance is found,take the radius from centers to that point and draw vswr.

[@samohithachaganti9022]

how u can take (1,0) as a centre point

[@manojjnadvajs6266]

What is ( 1,0) how to take origin while drawing axis

[@rohankademani6406]

Same doubt

[@ravalidasari460]

I didn't got how to trace Zin please explain sir

[@HKNAGPAL7]

see that point as intersection of 2 circles, resistance and reactance ones.

[@HKNAGPAL7]

God

[@tejanandareddy6424]

Pls tell me again input impedance

[@kayalvizhimanikandan4056]

Why you take 1,0 point

[@vamsikrishnagedela8990]

sir how you get the minus in input impedene

[@joshualekan8178]

The impedance circle is on the other side of vswr. Remember that when we wanted to plot the normalized load impedance we took our j from the upper part of the chart. Now since our input impedance has its j on the lower part, it is negative. You can also see the -ve sign on the chart. Hope this helps

[@krishnae]

It's gamma right and not tow ?

[@shruthirepaka7956]

Yeah

[@mralmas928]

I think you have made a mistake

[@PriyankaVerma-ld6wx]

please reply answer