Type 2 improper integrals! calculus 2

[@bprpcalculusbasics]

Check out type 1 improper integrals: kzbin.info/www/bejne/rWWZpJ2IftCJbbs

[@benmiddleton3176]

This guy's the goat i got an exam tomorrow and I feel way more confident thank you so much

[@andreki6127]

very useful video. way better than the real analysis lecture notes from my "top-class" school

[@dpmike32819]

Lmao

[@Iomhar]

Shouldn't that be MINUS 1/24?

[@ryancantpvp]

20:43 misteak -(-1)/[3(-2)^3] = 1/[3(-8)] = -1/24 Also (-1)/[3(1)^3] = -1/3

[@barracuda6817]

i'd like that misteak done medium well please

[@NotSoStNick]

@@barracuda6817 now that's the real misteak

[@petereziagor4604]

Please consider adding link to practice problems... I've been studying calculus from KZbin

[@peachbleach5060]

I wish you were my professor

[@beachwave5705]

love u bro im preparing for my first calc 2 exam. im definitely going to ace this shit. calc 2 is my bitch so far. I fucking love this class. I hope sequences and series dont kill me but I think ill be fine. any tips for preparing for calc 2 final? u got a vid for that

[@Elpsycongroo1130]

AT 8:08 if we use -ln(cosx) as the integral of tanx , can we say it diverges because ln(cos(pi/2)) is ln(0) which is undefined?????

[@matmat2462]

Isnt the (-1)^(2/3) in 20:25 undefined?

[@rpjtv8041]

don't we have to take the limit of the integral?

[@matmat2462]

It's a bad notation, he said it in his few videos but the answer's still the same. He's just making quick work of it

[@Arter64]

I was wondering about one thing. 20:17 moment reminded me about your words in another video. You said you can't integrate 1/x from (-1) to 1 using odd property of the 1/x function, because "(0-) and 0+ can be different". It's not exactly what you said (you were pointing on graph, where 0- and 0+ were different "lengths"), but I still don't quite understand how you can take them different? Why can't they be the same? If I messed smth, don't be rude pls)

[@bprpcalculusbasics]

I think I explained it better in this example. The improper integral of x from neg inf to inf: kzbin.info/www/bejne/mYW3hmSmmLp5aZo

[@Arter64]

@@bprpcalculusbasics hah, didn't notice this video. Thx

[@madeby30e42]

the integral of tangent x is -ln|cos x| + c. Or i'm i worng? great video tho

[@mathswithpana]

correct move negative to exponent of ln and you have 1/cosx which is secx

[@nguyenduy2712]

In example 1: When dx= -x^2 du >> 1/x^2 dx = - du >> You forgot "-1" when subsitution into integral. Then the Integral must be -Infinity right?

[@halaabutair4554]

no, he used the -1 to flip the integral. notice when we substituted with the u the integral is going in the opposite direction

[@markarmstrong8659]

How is it possible 1/0+ is infinity

[@abi7068]

imagine that 0+ is a slightly bigger number than 0 like 0.00000…..1. 1 is so much bigger that the result is essentially infinity

[@Eng586]

Just graph 1/x and see what the graph looks like and find the limit

[@Ppooh002]

hi, what happened to the negative at 3:03 ? shouldnt it be included?

[@OkayFine-ie5pm]

Sir used a property of integrals with allows us to swap the lower and upper limits.. -{F(a)-F(b)}={F(b)-F(a)}

[@aarona5329]

How do you tell if a function is approaching from positive or negative without looking at the graph?

[@alejandroarreguin3628]

assuming you're talking about bounds. For the example of 1/(x)^(1/3) from -1 to 8. we split it into 2 parts. from -1 to 0 and 0 to 8. from -1 to 0 we approach 0 from the left because it's our upper bound and it's not possible to approach it from the right because 0 is our upper bound. For 0 to 8 we approach 0 from the right because it's our lower bound and 8 is our upper bound.

[@jagula]

Is this official account or you just reupload his videos?

[@bprpcalculusbasics]

It’s mine. kzbin.info/www/bejne/o5OciJRugJuEa8k

[@Nylspider]

This is Steve's channel, yes

[@Earlx3n_shorts]

POV: you are a student @UL and chuene gott you here

[@drivenfromjamaica876]

Ohhh so thats the mic

[@fernando63668]

😂😂😂😂😂😂😂😂

[@goldenclockwise3513]

why are you holding a pokeball

[@Chaoticduuude]

I think it’s his microphone

[@charlesreyes6278]

Hello I Wanna learn calculus plssss do calculus tutorial for beginners and i will sub to all of ur 3 channel if u do calculus tutorial for beginners

[@alejandroarreguin3628]

I believe he has a playlist for calc 1.

[@dpmike32819]

I thought you need to take the LIMIT of an improper integral?

[@leomcpie7904]

This is an improper integral because certain values within the integral aren't defined!