Understanding Oscilloscopes - Bandwidth

  Рет қаралды 18,909

Rohde & Schwarz

Rohde & Schwarz

Күн бұрын

Пікірлер: 28
@kumara5288
@kumara5288 Жыл бұрын
Nice explanation about Bandwidth. Thank you so much!
@pauldenisowski
@pauldenisowski Жыл бұрын
Really appreciate the comment - thanks!
@krish2nasa
@krish2nasa Жыл бұрын
Excellent explanation as always. Thank you very much.
@pauldenisowski
@pauldenisowski Жыл бұрын
Thanks for the feeback!
@shalom-shlomi-zigdon6465
@shalom-shlomi-zigdon6465 Жыл бұрын
GREAT presentation, excellent speaker, Thanks
@pauldenisowski
@pauldenisowski Жыл бұрын
Thank you!
@sinojha1
@sinojha1 Жыл бұрын
Great presentation as always, thank you!
@pauldenisowski
@pauldenisowski Жыл бұрын
Thank you!
@gonzaloroca5143
@gonzaloroca5143 Жыл бұрын
Very useful information.
@pauldenisowski
@pauldenisowski Жыл бұрын
Thanks!
@ChristianSamsung-z6e
@ChristianSamsung-z6e 7 ай бұрын
Hi, the flat response in the graphs on most pages don't correspond with the BW indication...just on page 12 it is shown right. Otherwise really good...thanks!
@pauldenisowski
@pauldenisowski 7 ай бұрын
Yes - on slide 11 the BW line is in the wrong place (should be to the right) and on slide 9 it's correct for Gaussian but should have moved to the right for Flat. All the other slides are correct. Thanks for letting me know!
@Mr.Not_Sure
@Mr.Not_Sure 6 күн бұрын
Joining the party, on slide 5 lower BW waves should be shifted, because each edge starts at the same moment, but at low BW it rises slower.
@genericdynamics6618
@genericdynamics6618 2 жыл бұрын
This is great content
@pauldenisowski
@pauldenisowski 2 жыл бұрын
Thanks! There's more oscilloscope-related content coming soon!
@yosmanyhernandezsanchez9760
@yosmanyhernandezsanchez9760 3 ай бұрын
Thanks a lot for this video.
@pauldenisowski
@pauldenisowski 2 ай бұрын
Thanks for watching!
@AdelAlmahmoud-yv3nd
@AdelAlmahmoud-yv3nd Ай бұрын
Sir, how does the bandwidth relate to the scope sample rate ? and should the sample rate be at least twice as the bandwidth of the scope ? Thanks Eng.Paul
@arash4232
@arash4232 Жыл бұрын
Hi, Thank you, that was excellent. Is the 10x on the probe related to this topic as well? How does it contribute? Regards.
@pauldenisowski
@pauldenisowski Жыл бұрын
Thank you! The bandwidth of a probe is a function of several things, but the attenuation (10x) is not a significant contributor to probe bandwidth in most cases.
@arash4232
@arash4232 Жыл бұрын
@@pauldenisowski thank you.
@ゾカリクゾ
@ゾカリクゾ 9 ай бұрын
Maybe I'm misunderstanding the comment, but doesn't a 10x probe increase probe bandwidth?@@pauldenisowski
@pauldenisowski
@pauldenisowski 9 ай бұрын
@@ゾカリクゾ 10x probes generally have wider bandwidths than 1X probes because the capacitance in the probe tip of a 10x probe helps to cancel out the inherent capacitance of the scope input - it's this capacitance, not the attenuation _per se_ ,that leads to wider bandwidth. Hope that makes sense!
@ゾカリクゾ
@ゾカリクゾ 9 ай бұрын
Thanks for the clarification! Totally clear now.@@pauldenisowski
@lillyzegarra8025
@lillyzegarra8025 11 ай бұрын
Why are you saying that frequency attenuated by 3 dB is (~30%)? WTF!
@pauldenisowski
@pauldenisowski 11 ай бұрын
If you listen to the spoken text (or turn on subtitles), I say "The bandwidth of an oscilloscope is defined as the frequency at which the measured amplitude of a sinusoidal input signal is decreased or attenuated by 3 dB" Since oscilloscopes measure voltage, a 3dB reduction is approximately 70% of the original amplitude (sqrt(2)/2). You're absolutely right that it would make no sense to talk about frequency being decreased by 3 dB :) But I can see where the bullet point might be confusing by itself, so thanks for letting me know!
@gopip2605
@gopip2605 2 ай бұрын
As per mentioned formula, -3dB = 20 log10(Vout/Vin) 0.7=Vout/Vin This is the standard ratio as it attenuate 3dB. So, if Vin=5v, then Vout=3.5v if Vin=10v, then Vout=7v Then it reduces 30% whatever the input voltage.
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