Universal Modus Tollens Rule

[@the_ocean_eyes]

1) Let, P - x is computer science major. Q - x is taking discrete maths course. For all P(x) -> Q(x) Q(riya) P(riya) -> Q(riya) -By universal --------------------------- So, P(riya) - Fallacy 2) Let, P - x eats granola everyday. Q - x is healthy. For all P(x) -> Q(x) ~ Q(Linda) P(Linda) -> Q(Linda) -By universal --------------------------- So, ~ P(Linda) -Modus Tollens

[@SamSam-gx9ql]

1.) False (Fallacy of Affirming Conclusion) 2.) True (Universal Modus Tollens)

[@emadalomran8719]

My u explain the why the first one is false?

[@SamSam-gx9ql]

@@emadalomran8719 basically it's just P1: C -> D P2: D therefore C which is false because it's Fallacy of Affirming Conclusion

[@JD-eb5qu]

1.)I think 1st sentence false 2.)1. For all x{p(x)->q(x)} -premise 2. ~q(linda)-premise 3.P(linda)->q(linda)-[universal instantiation from 1] 4.~p(linda)[modus stollen from 2,3] ~p(linda) So this is TRUE according to UNIVERSAL MODU'S STOLLEN RULE Sir thanks a lot indeed sir this is very useful to me my text book couldn't help to me but your explanation is helpful very much 👌🙏🙏🙏

[@rajeshprajapati1851]

Finished Chapter 1 and Chapter 2. Thank you so much !!

[@saswateesahoo7440]

Thank you so much sir for this amazing explanation

[@jayxcoder]

a) False, Fallacy of affirming the conclusion. b) True, Universal Modus Tollens

[@saimalli3741]

Let p(x) denotes "x is a computer science" Q(x) denotes "x takes discrete mathematics course" a)1.forall x(p(x)->q(x)) premise 2.p(ria) premise 3.p(ria)->q(ria) (by universal Instantiation (1)) 4.q(ria) (by modus ponens from2&3)

[@vishwajit9290]

Wrong answer coz it's seems like it is right argument but it's not, it's a fallacy.

[@Tera_Baap25]

@@vishwajit9290 what is fallacy means bro?

[@CHATUR__RAMALINGAM]

i liked this channel very much. but sir i want give you a tip that you are not making playlist names of recent videos , for example your playlist analog electronics consist of serial videos arranged together so for new subscribers it becomes easy to study , what they want to.

[@Lavkush23424]

Nice explained

[@brahmanandakabi8796]

Thank you sir

[@acriziosouza]

Modus Ponens: p -> q OR [(p -> q) ^ p] -> p p _____ q Modus Tollens: p -> q OR [(p -> q) ^ ¬q] -> ¬p ¬q _____ ¬p Universal Instantiation: this rule is used to conclude that P(c) is true when ∀xP(x) is true. ∀xP(x) ______ P(c) A) Let P(x) denotes "x is a computer science major" Q(x) denotes "x takes discrete mathematics course" ∀x(P(x) -> Q(x)) Premise Q(Ria) Premise P(Ria) -> Q(Ria) By universal instantiation from (1) P(Ria) = ? Fallacy -> Affirming the consequence (Ria could take discrete mathematics course and not being a computer science major) B) Let P(x) denotes "x eats granola everyday" Q(x) denotes "x is healthy" ∀x(P(x) -> Q(x)) Premise ¬Q(Linda) Premise P(Linda) -> Q(Linda) By universal instantiation from (1) ¬P(Linda) Modus tollens from (2) and (3)

[@harshsharma5768]

First is false and second one is true ?

[@JD-eb5qu]

I think so bro

[@kunaldhyani]

1) False 2) True

[@shivajichalise_]

HELP! Everyone in math class loves proof. Someone in math class have never taken calculus. Conclusion Someone who loves proof have never taken calculus.

[@gamexd3228]

Sorry To Say But I Am Watching This Playlist From beginning But After video No. 45 I am Not Able To Understand Your Videos I don't Know why I am not Able To Understand because i watched every video atleast 2 time but still the Concept Is Not Clear to Me This could be due to You Are Teaching Very Fast Or switching the topics fast Please don't Take It As hate Because i Love to watch your Videos So Take It As my Feedback "Thanks"

[@LogicInfozRPKP]

I am agree partially

[@rajeshprajapati4863]

He is teaching great. Just listen carefully and note things down. Everything is not available in presentation.

[@cromzkiesvlog4307]

NBSC student!! Like this comment

[@cromzkiesvlog4307]

NBSC student!! Like this comment