UPSC CSAT - Remainder | UPSC 2024 | Short Tricks | OnlyIAS CSAT

[@malavikachandran207]

Able to understand well...thanku sir.. watching for 2025 attempt..

[@yawarhussainbhat123]

Only one beloved person whom I accept my guru ❤️ Love uh sir

[@nadirsabiya77]

Superb! Thanks Rishav sir for the lecture :) ❤

[@avinashdhoke4252]

28:00 cyclicity of 3 is 4 so.2019. 19/4=3. 3 ka power 3 =27 ,, 27/10. R =7.....😊

[@r.prajapati7072]

(3) 2022 = ans. D (9)

[@KhaTik_Raj]

Sir ji great Concepts Share kiye hai aapne Thanku so much

[@shivendra9020]

thankuu sir for this wonderful explanation

[@DheerajKumar-xm6my]

Sir percentage and ratio proportion agla topic lijiye vo sabse important h

[@raushanraj7730]

26:52 Answer is 5

[@kumhar_rashmi021]

First answer -5

[@KanchanAmbwani]

Q2. Remainder 9 option D (3)2022power/10 3cyclicity is 4 That why- 4÷2022=2 remainder 3power2=9 Hence 9 is remainder.

[@KanchanAmbwani]

Q1. (36)power243÷11 (33-3)power243/11 (+3)power242/11 [(3)2power]121 power /11 (9+2)121POWER×3/11 (+1)×3/11 hence remainder 3

[@kumhar_rashmi021]

It's 36 then why you write 33-3

[@kumhar_rashmi021]

It's answer is 5

[@avinashdhoke4252]

35:00 sir 6 ka kitna bhi power lelo unit digit to 6 hi ata means vahi uska remainder 😊

[@r.prajapati7072]

224...remainder 31 ...( Ans. D 15 )

[@Rajubiswalll]

Ye sir alag hai bhai....... Economy God ab edhar b macha rahe ❤

[@KanchanAmbwani]

Thank you so much sir ji 😊😊😊😊😊😊😊😊

[@iama_deity]

The clarity 🎯

[@Dark.eveything]

Ap ache teacher hain❤

[@poonampandey3655]

Bht Achhe

[@Dark.eveything]

@@poonampandey3655 tum bhi achi ladki lagti ho😆😅

[@KanchanAmbwani]

Q3. Remainder 1 Q4. Remainder 1 Q5. Remainder 1

[@SiddhikaKhurrana]

sir abhi to bhut saare topics bche h ap please jldi jldi videos upload kijiye na week me ek video bhut km h aese to csat ka syllabus complete hi nh ho payega

[@jyotsanayadav5987]

Right 👍.. Pls Sir... very humble request.. pls pay attention regarding this

[@supercommandogamingyt]

Sir ne already krwa dia😊​@@jyotsanayadav5987

[@Ann.229]

Kaha pr ??​@@supercommandogamingyt

[@supercommandogamingyt]

@@Ann.229 paid batch pe

[@narendaragarwal3782]

Remainder on dividing X by 7 is 2. What will be remainder if X^6 divide by 7. Sir process let number be X= 2 so remainder,=2/7 =2 now number become X^6 , so 2^6 / 7. Here 2^6 is of cycle 4 so it become 2^2. Now remainder,= 2^2/7 =4. But option is( 0,1,2,3,)....

[@narendaragarwal3782]

Let number X= 7y +2 . Now X^6 = (7y +2)^6 / 7. We get 2^6/7 = 64/7 = remainder 1 I got. But why two answer , sir told that from both method answer will be same

[@mohammedriyas4022]

26:57 detailed answer pls sir

[@sabiashaikh2627]

Sir please jaldi jaldi cover kardo time nhi hai

[@Ann.229]

Sir sare topics civer ho jane pr ,remainder wale topic ka practise question karwaye please . Ho sake toh sare topics ke practics question series nikale . Thank you

[@rajangupta19675]

Sir plz give detailed answer to 36^243÷11

[@Shakti-98]

Iska ans 1 hai kya

[@sheetalchoudhary0260]

Ha yr kha dunde isse

[@student-o6g]

​@@Shakti-9830+5 ÷11 =5÷11=5

[@carlmarks-mj6yc]

26:57 and will be 5

[@ravelkingyt9497]

Can u tell the solution bro

[@Algo_Rhythm_]

Ultimate Solution🎉🎉❤

[@tarunsaini7461]

You good teacher saaaar 🎉

[@naziawasim4655]

Sir we can also use unit digit concept to get the remainder in many cases

[@nadim_haldarwa1738]

Thank you 😊

[@Trader_S._Kumar]

Bohot mst class hai

[@Suraj-g6o4y]

Very well explained 🎉

[@nidhiyadav-mi4qp]

HW1.ans(a)1 HW2.ans(d)9 HW3.ans(b)1 HW4.ans(d)15 HW5.pyq2023,ans(d)9,but sir 1186 me se 31 minus krne pr 1155 aa rha uska factor nikalna mere liye bahut time taking hai, sayad exam me half question krne ke baad chod du. Sir csat is my weakest part,i am trying pr pass nh ho pa rhi Thank you sir

[@debashishdev8741]

Please explain hw 1 (36)²⁴³/11

[@dominicbhai-gaming8847]

31:31 Answer - d- 9

[@ChuleshSahu67]

TQ so much sir ❣️

[@Radhakrishna-e8l]

22:33 Sir hm 9×131=1279/5 =4remainder ase bi kr skte h n

[@teeny-weeny2806]

Que. 1 - Ans is 5

[@jayadixit5526]

HW 1-5 2-9

[@LuxyGardenLover1975]

36:20 cyclic system se karne par 2 remainder aa rha hai .. Naa ki 4

[@avinashdhoke4252]

Wahito

[@devarajpatil1243]

D :9

[@Ari-ly1uc]

Sir Percentage + Ratio Proportion next

[@shraddhanikam396]

Aur kitne vedios bache hai sir?? please roj ek vedio upload kijiye

[@rajangupta19675]

Very interesting topic

[@ramanpatel1258]

Thank u so much sir ❤

[@RajnishKumar-tj1fl]

Nice session

[@swatikapoorkapoor]

Thankyou Sir

[@mojahedulshaikh589]

Sir daily class lijiye

[@priyankachoudhary0070]

Question pdf nahi h telegram pr

[@Asoulwithdivine....]

Factorization??

[@ayu24222]

1/5 ka rem 1 kaise ata hai , someone plz quickly explain

[@nayanwaghmare1014]

Remainder 3

[@DheerajKumar-xm6my]

Sir 1/5 ka reminder to zero aayega remainnder 1 kaise aa sakta h 😂😂😂😂

[@himanshiwithart]

Pta chale toh koi mujhe bhi bta do yrr dhund liya kahi method ni mili

[@vijetasain3131]

Dear places in news ki single video bnao

[@mojahedulshaikh589]

Sir avi tak telegram me pdf nahi aya h

[@hudeshwarsingh5708]

Sir 2/8 = 4

[@ayu24222]

can u plz explain how?

[@ayushinayak2499]

Please koi bata sakta hai ki 1009 kaise aya?

[@avinashdhoke4252]

2018/2

[@kohinoornehar5221]

How 1/5 remainder 1? Someone please explain 🥺

[@LuxyGardenLover1975]

Decimal ko bhul jao. Bhul jao ki point jaisa kuch hota hai . Ab socho reminder

[@kohinoornehar5221]

@@LuxyGardenLover1975 Thank you.

[@himanshiwithart]

Mujhe toh abhi smjh ni aya yer plzz explain kr do

[@LuxyGardenLover1975]

@@himanshiwithart 5) 1 ( Ab bhul jao ki point dekar 1 ko 10 bana sakte ho . 5) 1 ( __ 1

[@himanshiwithart]

Ohh achha smjh gai thnkuu yr

[@kafeelurrehman25625]

🎉🎉🎉🎉

[@priyajain7109]

36^243/ 11. How will this question be solved?

[@rajangupta19675]

Same question

[@c256pradeep]

3^243/11 cyclicity of 5 , will leave 3^3/11 =27/11 , reminder 5

[@rajangupta19675]

@@c256pradeep bro how to solve this based on concept taught in class.The method used by you is lengthy and not applicable in all cases

[@anamikarao1010]

Behen preshaan kr diya tha iss question ne finally ho gya solve 😅my method - 33^240+3^3÷11,33 is purely divisible by 11 then we will focus only on 3^3÷11 =27/11 it's remainder will be 5

[@rajangupta19675]

@@anamikarao1010 you are wrong

[@RahulKumar-g5u3d]

❤❤

[@MonikaYadav-r7n]

😇😇😇😇😇

[@richaverma8545]

Sir profit and loss and time and work bhi krwa dijiye

[@ayushinayak2499]

Sir 1009 kaise aya

[@avinashdhoke4252]

2018/2 viceverca 1009*2=2018

[@mohdkhalid4871]

✨✨✨✨✨✨

[@sunitasaini3431]

Thank u sir 🎉🎉❤❤