Using WolframAlpha to check 1^x = 2

[@akmubilin4363]

You can't just take x*ln(1) = ln(2), divide both sides by ln(1) and get x = ln(2)/ln(1) because ln(1) is actually 0 and you can't divide by zero, it doesn't make sense

[@michlop452]

the assumption is that ln(1) has infinitely many values if you write 1 as e^(n*i2pi)