Vector Equations of Spheres (2 of 2: Circle of intersection)

[@沈博智-x5y]

instead of comparing similar triangles, i compared areas. Area of that triangle made with radii 3 & 4 is 0.5(3)(4) = 6 From another angle, it's 0.5(5)h = 6 (making 5 the base, the line segment joining the two centres) h = 12/5 (this is the radius of the circle of intersection) Use pythagoras to find the "scalar projection" length z = sqrt(3^2 - (12/5)^2) = sqrt(81/25) therefore z = 9/5 equation of circle of intersection on the plane z = 9/5 is x^2 + y^2 = 144/25 (and z = 9/5) so radius of cicle of intersection is 12/5 centre at (0, 0, 9/5)

[@ashish4k07]

yeah its an easy method

[@mathsandsciencechannel]

Great video sir... ♥️♥️♥️

[@aashsyed1277]

9:29 when a proffeser becomes a *master* at math.

[@CMtutorials313maths]

Ratio of two numbers is 3 : 4 And their HCF = 4 What is the LCM= ? #hshmaths313

[@thejojoshow9238]

😘😘😘😘💛💛💛🥕🥕🥕 Thank you.

[@aashsyed1277]

let me guess the future.......tomorrow he will be uploading a integration video i promise.

[@CMtutorials313maths]

5-2+6÷3 = ? If your answer is 1 or 3 then you are Wrong #hshmaths313

[@foul8917]

It's 5 right?