Vectors | Past Papers | Physics AS (updated 2022)

Hello! download the PDF form of worksheet first. Solve side by side for better understanding. Cheers!
www.icloud.com/iclouddrive/00...

[@judith____]

6:05 this is the best

[@clapz514]

9:25

[@user-ld4yj7fm8q]

The resolutions for the first question , why cos30 in vertical component

[@phychemwithyousufwasil]

The angle given is with vertical axis

[@gloriafa1160]

Hi how can I get the 2022 past paper

[@phychemwithyousufwasil]

solved paper video or just a link

[@gloriafa1160]

@@phychemwithyousufwasil the full paper

[@hanaaa8849]

do u have private lessons?

[@phychemwithyousufwasil]

Yes I do you may send Querry on [e-mail]

[@jacqueline-zb8qp]

any full solutions for last 5 question?

[@bigbunda06t9]

answer is 60

[@kazutoravfx]

@@bigbunda06t9 yes

[@kazutoravfx]

If you want solution here it is So, Let direction of v be towards north N V slows down (θ)* in the easterly direction and magnitude is V/2 Resolve V/2 into Vertical and horizontal They have said in the question that one of the compononets is V/4 in the same direction as the original V, hence vertical component = V/4 Vertical Component = (v/2)*sin(θ) (v/2)*cos(θ) = V/4 sin(θ) = 1/2 (θ) = sin-1(1/2) (θ) = 30* Deviated angle = 90 - (θ) = 90 - 30 = 60* You can also solve by assuming V is towards east and in that case youll directly find deviated angle by performing cos-1(1/2) = (θ) (θ) = 60*

[@user-vq2sk2uz8u]

Super helpful but the mixture of another language id understand 💔

[@phychemwithyousufwasil]

I will upload in english my bad

[@nthati6206]

​@phychemwithyousufwasil please use English for all your videos