View Serializability Gate Numerical (Large Schedule Example)

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Ritu Kapur Classes

Ritu Kapur Classes

Күн бұрын

Пікірлер: 20
@azlanahmed2811
@azlanahmed2811 Ай бұрын
We can make this problem even simpler by checking blind writes, if there are no blind write then we can directly conclude that the schedule is not view serializable, if there are blind write then only we can proceed your way
@gouravsen4946
@gouravsen4946 Жыл бұрын
In update read, we consider those reads except the initial reads. So for y update read should have T3,T1 only not T3,T2,T1 . Also no update read is there for z.
@invaderffgaming4475
@invaderffgaming4475 11 ай бұрын
Yes bro mam pls reply tomorrow is my exam
@ritukapurclasses1591
@ritukapurclasses1591 9 ай бұрын
Either its Read or its update. We never club them both.
@020hamza2
@020hamza2 2 жыл бұрын
But last part I understand very nicely from you
@harishks308
@harishks308 2 жыл бұрын
Thank you mam🙏..helpfull for exams🤩..well explained🔥
@ritukapurclasses1591
@ritukapurclasses1591 2 жыл бұрын
Thanks! All the best!
@dr.amandeep6752
@dr.amandeep6752 10 ай бұрын
T3 is also writting Y. Please tell correct
@ritukapurclasses1591
@ritukapurclasses1591 9 ай бұрын
Yes, that is why I have written T3 in update cell for Y. But, since T1 writes its finally so only T1 is written in final update. Hope it is clear 😊
@AlphaMagnus2312
@AlphaMagnus2312 Ай бұрын
Maam your definition of initial read is incorrect. It does not have to be before a write condition to the same data. So initial read for x is T2, for y is T2 and for z is T2
@berry3269
@berry3269 2 жыл бұрын
Final update for z is t3🤔🤔🤔
@simonebattiato5221
@simonebattiato5221 2 жыл бұрын
Final update for y Is t1
@ritukapurclasses1591
@ritukapurclasses1591 9 ай бұрын
Yes you are correct
@ritukapurclasses1591
@ritukapurclasses1591 9 ай бұрын
Well Done!!!
@payalkaur779
@payalkaur779 4 жыл бұрын
niceee
@020hamza2
@020hamza2 2 жыл бұрын
You are way of teaching is not good because you not told why we not taken in initial read T3 in y section
@cihansariyildiz1748
@cihansariyildiz1748 2 жыл бұрын
its not initial read, there is another transaction write before that read which makes it not initial read
@ritukapurclasses1591
@ritukapurclasses1591 2 жыл бұрын
W2(y) is updating y and hence it cannot be initial read for T3 as an update is happening before read. Also, I have mentioned this in the video at 3.16 seconds. Here is the link for the clip: kzbin.infoUgkxI-_BZXibtlmD7lIb-dJCpr_ISjzqioKS I request you to update your view on my teaching. Thanks!
@ritukapurclasses1591
@ritukapurclasses1591 2 жыл бұрын
@@cihansariyildiz1748 Yes, thanks for stating this. It is mentioned in my video at 3.16 s: kzbin.infoUgkxI-_BZXibtlmD7lIb-dJCpr_ISjzqioKS
@kawale626
@kawale626 Ай бұрын
So irritating
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