Virtual Work Method Lec 5 || (Problem 4)|Engineering Mechanics|First Year Students

[@KS-gw4je]

How del y1 = 500 del theta!??

[@barbie0103]

y2 should be 400sin theta right cus its in y coordinate?

[@jaypatel7632]

7:40 the direction of force as well as displacement will be same.. Then how it can be negative?.

[@ashishpurohit9138]

If I am assuming that the piston is moving virtually down, to satisfied the constraints, point at force P is acting will go upward. Means point is moving upward but my force P is acting downward. so the work will be negative. I tried to answer your query, If yet not clear, inform me.

[@jaypatel7632]

@@ashishpurohit9138 but sir, we have assumed that piston is mass less.. Then how it can come downward automatically... Means in this case we have first applied force P in downward direction after that piston comes down... So force P and application of that point's displacement have same direction.. So it should be positive...

[@ashishpurohit9138]

my no is 9540680833, call me I will explain. it is very difficult to explain in text.

[@madeedkhursheed]

sir, shouldn't y1 be 500 cos theta

[@sayanbanerjee1145]

same question here. could you get the answer after all?

[@stockmarketarena2282]

Thanks sir🙏🙏🙏🙏🙏

[@akshitagupta6152]

Sir what is the value of y1 here?

[@jaypatel7632]

I think it will be zero.. If we will take fix point at honge.. I'm also confused😕 in this question...

[@akshitagupta6152]

@@jaypatel7632 okay