Relative Motion with rotating reference axes Example (part 1)

[@camdenndean]

Reading the textbook, I could not have been more lost. Watching your video, I could not feel more confident walking into my exam. Thanks bro.

[@Sunil_Manohar]

I will be waiting for your next video 👍

[@mwont]

Awesome video. Thanks. To sum up. Both links will go up (anticlockwise), and pin A will go up the slide since it has negative velocity in x direction.

[@carolinecochran29]

wow you just took all my jumbled thoughts and fit them together to create a video I actually understand

[@mousaalsaeed9410]

You work hard to teach people, this is a noble job..🖒

[@virtually_passed]

Thanks again for the nice comments :)

[@bobbyspiers5260]

Bravo, Sir. Great work!

[@matheussiqueira2313]

That's an amazing resolution.

[@virtually_passed]

480p ~ 1080p :P

[@michaelsedillo4723]

would that interior angle for omega*r not be 60? If you drew a perp. line and it would make a right triangle being 180-90-30?

[@BoZhaoengineering]

this is exactly what I want when I try to design a transmission

[@melissafigueroa4218]

How come you didn't choose the pin rotating with omega is your non-rotating reference frame (left side of little r)?

[@themaanism]

Doesn't the absolute velocity of A change with whatever Primary reference frame you are analyzing the motion from? For example, I see you superimposed your primary and secondary reference frame at point B, but what If my primary reference frame was at the point on the left end of little r but my secondary rotating reference frame was at B? Doesn't the absolute velocity change then?

[@virtually_passed]

Hey mate, I'm assuming by Primary reference frame you mean the inertial non rotating reference frame XY (ie, the earth)? And by the secondary reference frame I assume you mean the rotating reference frame xy? In this example, you're right, I have placed the xy frame at point B, however I haven't even bothered showing the XY frame. This is because the absolute velocity of A and B will remain the same. This is because Vb and Va will be measured as the exact same since the derivatives of the constants will be 0. Proof: kzbin.info/www/bejne/apOwlYenZsmCoaM However, all this assumes that the XY axis is inertial and non rotating. If you place the XY axis at the right end of little r then XY will be rotating and the formula won't apply. I hope that helps :D

[@umutunlu726]

Very good!

[@virtually_passed]

Thanks, mate :)

[@hppaviliona1700la]

Naaaaaaught

[@virtually_passed]

:-}