Visual Basic Tutorial - 21 - Formatting Strings

[@w.b.r.6332]

Just wanted to say thanks Sam for all of these awesome tutorials.

[@DigitalMonsters]

Blitzing through these ^^ will have 200 done in a few days at this pace

[@HikikomoriDev]

The Easy tutorials allow people who have no idea what the computing world may be are just getting out of the shell for the first time. You could always try more stuff like extreme Java and complex databases. but please always remember there will be people who have no idea where they are going, and this is their solution. there is also solutions for you, please search advanced programming.

[@ImperialPlanet]

It actually rounds the decimals in the number you have stated.

[@23Drezzy]

Thank you. I was just about to ask if it rounds off OR truncates values.

[@chanwookim8263]

Excellent tutorial once again. Keep up the good work

[@Jbergawane9]

Thank you so much, but what is the difference between rounding and string formating ?

[@jasonmesa4224]

I can't get (String.Format("{0:n2}", myDouble)) to work in VB 2015 using buttons or other referenced portions. Cant use console.writeline for everything...

[@robertmccully2792]

Here are there variations using window forms. They all work vb 2010 2015 is a memory hog... Dim dblNumber As Double dblNumber = 12.123456789 dblNumber /= 7 MessageBox.Show(String.Format("{0:n2}", dblNumber) & "HI..", "hello") MessageBox.Show(String.Format("Test..." & "{0:n9}", dblNumber), "Floating Numbers") MessageBox.Show("test.." & String.Format("{0:n5}", dblNumber)) Close()

[@thishitscustom333]

@onlivegamer For Console.WriteLine(String.Format("{0:n2}", myDouble))....... How can you format a string (which are letters) with {0:n2}? I understand what {0,n2} does but if you want to format a number shouldn't the statement be (myDouble.Format("{0:n2}", myDouble)) ? If myDouble is as double, why do you write String? Thanks

[@arsenalprince4]

@bomer890 I don't know if this is a late reply and I am still a beginner. What I suppose the String.format does is not to alter the number's format, but only display it as a string which has the format{0:n2}, myDouble is unchanged.

[@TDawg-de8sb]

its so funny looked at vb a week ago expecting it to be really hard its not that complicated because all the syntax and stuff are easy to pick up on I love vb

[@greatbucket85]

Hi Sam, please assist me with line number 9. I have followed it to the detail and didn't receive anything on the error list. however once I start debugging. an error exception occurs.

[@bradmillington5569]

Any chance you remember how you fixed this 7 years on? 😅

[@TheVerbalAxiom]

2nd day of Vb.net, Time for my 22nd tutorial, on top of already creating side projects. #GettingStronger

[@bomer890]

Hey..i'm not really know about the .format('{0.n2}'; myDouble).... can somebody explan to me...??

[@DailyFrankPeter]

I get an InvalidCastException in line 7

[@muazabdool6047]

Probably because of you used . instead of , i know its annoying :) also had the same problem

[@newhuman9458]

تحية لكل عربي لم يفهم ههههههههه

[@23Drezzy]

I might be late but once you type "String." it uses the string class in .NET to convert the values given to string format. I am not 100% sure though.

[@harishli2020]

I have exactly done what you have shown, but when I type 2142.2342, I'm getting 21.422.342,00.

[@RahilWazirAli]

No!!! In the 19th tutorial he didn't forget :D

[@spyroglitcher]

@deenotheman2 thats right.

[@VijayNandwani]

You didn't explain what is the use and function of String.Format("{0:n2}"

[@FonteneleNXT]

I think it coud be useful for a calculator program.

[@Blackllama13]

Keep in mind, it rounds to the first .2 deciaml points. so if I did 15.666 i'd come out as 15.67

[@greatbucket85]

Right, anyway I figured it out. Thanks

[@mattablack23]

This is me being late to the game but this uses what we have learned from a few previous lessons up to now.. Module Module1 'rapping up from tutorial 19 to 21... Tutorials by Sam AKA TheNewBoston.. AKA OnliveGamer.. Sub Main() Dim myString As String = Nothing Dim dValue As Double = Nothing Console.WriteLine("Please enter a set of letters or a word that equals up to 5 characters or more.") myString = Console.ReadLine() If myString.Length >= 5 Then 'I sat here for like 10 minutes wondering why mystring.length.Equals(5) did not work when I 'typed because I never typed exactly five letters.. Console.WriteLine("Please enter a decimal value") dValue = Console.ReadLine() Console.Clear() Console.WriteLine(String.Format("{0:n2}", dValue)) Console.WriteLine(myString.ToUpper()) Console.WriteLine(myString.ToLower()) Console.ReadLine() Console.WriteLine(myString.Substring(0, 1)) Console.WriteLine(myString.Substring(0, 2)) Console.WriteLine(myString.Substring(0, 3)) Console.WriteLine(myString.Substring(0, 4)) Console.WriteLine(myString.Substring(0, 4)) Console.WriteLine(myString.Substring(0, 3)) Console.WriteLine(myString.Substring(0, 2)) Console.WriteLine(myString.Substring(0, 1)) Console.WriteLine(myString.Substring(0)) Console.ReadLine() Else Console.Clear() Console.WriteLine("The string must be at least 5 letters long.") Console.ReadLine() End If End Sub End Module

[@davidebettina2792]

go ahead

[@voltaquake]

hehe

[@ben1996123]

haha

[@VijayNandwani]

:D

[@Sajib115]

You are.

[@spyko94]

Yeah sure dude, I'm the stupid one here.

[@XModding7]

You are....

[@jared0801]

hehe