#183

[@MajorHenricks]

A common error: relative motion between a magnet field, and a conductor, does not induce a current in the conductor; it induces a voltage; then, if, there is a complete circuit, a current will flow.

[@w2aew]

Yes, a common error that I make! I'll pin this comment so others will learn from my mistake.

[@ricardothedardothebeastfro4747]

V = L di/dt

[@ernestb.2377]

@@ricardothedardothebeastfro4747 The Professor was talking about: e = N(dΦ/dt), I suppose.

[@keena1326]

I've watched about 15 different videos on this subject lately and this is by far the best explanation I've seen yet. The scope shots are very good.

[@NeilMartinsenBurrell]

Great use of the schematic, the circuit and the scope all together. Elegantly presented and very compelling for learning.

[@miket5506]

This video brought a perfect visualization to something I've only ever been told about--NOW I understand it. Thank you!

[@RideGasGas]

Why in the world would anyone give this video a thumbs down. OK, a couple nit-picks as noted below, but the video was quite informative, the scope traces quite illustrative, and will really help the average hobbyist.

[@RexxSchneider]

Thanks for the very clear explanations. I thought I knew all there was to know about flyback diodes, but seeing the explanation about the current rating only needing to be equal to the current taken by the coil was a moment of revelation.

[@gerryjamesedwards1227]

Having the scope demo along with the theory makes it super-easy to comprehend. Great series of videos, all the 'back-to-basics' ones you've done. For people, like me, who are just getting into electronics it really helps when someone who thoroughly understands the subject takes the time to explain it fully, and including a well thought-out demonstration makes it the sort of tutelage you normally have to pay a lot for. Much appreciated!

[@gilmertugahan]

Just by watching these videos, my mind starts to shift from an ordinary fix-no-fix electronic hobbyist into an engineering-level enthusiast. This really encouraged me to buy an oscilloscope. I wish all schools were like this. Thanks so much.

[@ww9l]

I've been playing with electronics for 40+ years and never had anyone explain this concept so well. This only proves the point that you're never too old to learn, Thank you!

[@jpol3808]

THANK YOU THANK YOU THANK YOU. I had a problem with a 20yr old industrial bake oven, the oven kept shutting off intermittently. It had a 5 pin 120v control relay, a 120v main power contractor for the blower and tapped from top of that, a 120v contractor for the 3ph heat elements. I changed an original stop button with weak spring, a noisy element contactor, an original control relay, and a original dual element thermocouple. Then by looking at the schematic, I figured out someone prior had changed a hi temp limit controller and during the rewire had removed the snubbers across the coils. Funny thing was it worked like that for more than two years before developing the problem which gradually grew more frequent. Now I fully understand why those are necessary, what they do, how they work and could probably diagnose the situation with a scope or analog voltmeter. THANK YOU. Your videos are complete and to the point. Keep up the great work. You made my day! Merry Christmas!

[@ernestb.2377]

You really explained it very good. Especially the part the current from the coil rushing into the switched off transistor that is high impedance and producing that high voltage. If there was a low impedance path there would be no high voltage.. Collector−Emitter Breakdown Voltage of 2N3904 would be 40V(min value). That is also the abs max voltage. So that has not "killed it" right away but it is not "healthy" for that type 🙂 In your configuration and that specimen it was more of a 60-70V. I was thinking (wrongly) that the diode should be of a high voltage type, but that is not the case, as the diode prevents that high voltage to occur in the first place 👍

[@sanjayd411]

Great explanation as always Alan. Watching your videos takes me back to my university days studying electrical engineering. I have an MSEE degree and have been a wireless communications systems engineer for over 35yrs now, but these circuits related videos still teach me things that I have not done since a long time. Thank you so much for all your efforts and please keep ‘em coming. 👍👍🙏🙏

[@thomasmaughan4798]

Excellent use of storage oscilloscope and actual breadboard circuits. Snubber diodes protect BUT slow down relay release. Closely related to all this is the presence of non-ferrous shim at the relay to prevent the armature from sticking. Long ago in a galaxy far away I used a scope to detect a bad shim in IBM electronic accounting machines. When the armature clamps shut, the velocity of the armature will produce a small spike of voltage (moving magnetic field) and at the moment of closure its velocity becomes very high. The stainless steel shim prevents full closure and that, combined with an RC snubber, greatly speeds up release. When everything is proper there's not much of a energizing spike but if you see a relay that has a voltage spike across its coil a few milliseconds after engergizing, that means the armature has clamped down and there's no shim. It is very difficult to see this with your eyes that the shim has broken off.

[@donpgibson]

Alan, Just a quick note of gratitude for all of your excellent videos and this one in particular. As I am educating myself on basic electronics and building circuits for my ham station, I come across topics I don’t fully understand. When I find that you have addressed one of these topics, I know I will be learning something valuable. In this case, I knew that a diode is necessary when you have to switch inductive loads and I could have just followed the “formula” and always included one in my circuits, but I wanted to know more of the “why” and “how” this works. I was a bit confounded on this one for some reason. This video nailed it down for me! Thank you so much for taking the time to educate us all. 73 de Don KJ6FO

[@user-su5sq5ib3i]

This was a great lesson Allan, thanks!

[@ToddEmmershy]

This is the BEST video I found that details the test point locations to validate if a flyback protection circuit is working via an oscilloscope! Thank you!

[@Roy_Tellason]

This strikes me as a good place to use up salvaged 1N4001s, which I would likely never use in any power supply application due to their low PRV rating... Way back in 1975 I was called in to help out with getting a bit of industrial machinery working. This was a *big* machine, had a whole room to itself. I was told that the original designers had spent $160,000 to get this thing built, and that since then between $300,000 and $400,000 had been spent to try and get it working right. One of the first things that I noticed was that every single fault indicator on the thing was indicating. These were driven by a panel of relays, which were in turn driven by some open-collector logic. (Look up Amperex "norbits" some time, those were some really bizarre parts.) Every single one of those driver parts was shorted at its output, because nobody along the way had bothered to put those diodes in. I ordered replacement logic, and put some diodes in, and that fixed that particular problem. It amazes me to this day that nobody along the way had seen fit to do that.

[@spelunkerd]

What a great explanation.

[@wa4aos]

I knew what snubbers did and basically how they work but seeing it all displayed on the scope really nailed it down for me..Thanks Professor and thanks for taking the time to make your most excellent videos!!!

[@matey6760]

I remember my grandfather explaining this to me about 40 years ago when I was very young. Thank you for your lesson I actually think I get it now. Thank you so much.

[@onecircuit]

@5:09 My mouth drops. I had no idea... holy crap that's a massive potential from a little relay like that. Tons to be learned from this video. Thanks!

[@Observ45er]

+OneCircuit Yes. The voltage that the inductor generates is proportional to the rate of change of the current. Do something to get the current to drop rapidly and you get a very high voltage. If you pull a connecting wire away from the inductor really, really fast, the arc can have tens of thousands of volts in order to maintain the arc over the long distance and therefore keep the current flowing.

[@jpopelish]

Couple nitpicks; At 11:44 "and dissipate it safely into the positive supply". No energy is going back into the positive supply, while the diode is conducting. The stored energy is being dissipated in the diode, but mostly into the relay coil resistance, because only one lead of the supply is connected to the current loop through the coil and diode. You keep saying the changing magnetic field induces coil current. I think a clearer way to think about this is that the changing magnetic field induces coil voltage, and the entire circuit determines how that induced voltage affects instantaneous current. Instant by instant, as that current changes, it alters how the magnetic field is changing and those magnetic field changes keep inducing resultant voltage. Current produces magnetic field. Rate of change of that magnetic field produces voltage. Voltage drives current. And round and round we go.

[@w2aew]

Yes, I miss-spoke about the energy going into the supply rail. Thanks for the correction.

[@hernancoronel]

Thank you for the deep explanation, it was kind of difficult to understand until I read this comment. Now I see how the energy moves and dissipates in that diode/coil pair. Thank you both for an excellent addition to the incredible video! Keep up the great work w2aew!

[@kakagaming7693]

@@w2aew hello i want to talk you.personaly

[@thomasmaughan4798]

Moving magnetic field induces a *current* in a wire. Whether that current produces a voltage depends on encountering *resistance* (ohms law). In a superconducting storage ring you will have zero volts but hundreds or thousands of amperes of current.

[@jpopelish]

@@thomasmaughan4798 What if this current is induced into an open circuit? How much voltage will it produce to drive that current through an infinite resistance?

[@copernicofelinis]

11:04 the sag in the exponential curve of the coil current is due to the change in the magnetic circuit. It's common to all relays driven in DC: there are basically two exponentials associated with the two different limiting values of the inductance: one when the magnetic circuit is open, and one when it is closed. The sag (or bump when you go from unenergized to energized) is what happens in between.

[@m1geo]

This was my guess too. That or the metal moving inside the relay.

[@GiorgiAptsiauriX]

I was asked this exact question at a technical interview. Except, they had made it incorrect and asked me to correct it. One of the mistakes was how the diode was connected...

[@ptianu]

Great tutorial and your illustrations were literally worth a 1000 words.

[@michaeljburt]

Excellent explanation!!! An old EE can even learn some more about this topic. Great work

[@pedrochirivella2473]

Thanks for such a great video

[@frequencydrive]

I loved watching this. I'm an electrical engineering student and although we do get experience in the lab with diodes, capacitors and transistors what we don't get exposed to is some of the practical things you have to do in "real life" to account for unexpected things like the "fly-back effect." You have really nice equipment too. That current probe cost thousands of dollars and you have a 1 Ghz 4 channel TEKTRONIX scope. Very impressive.

[@w2aew]

It certainly helps when you work for a company like Tektronix ;-)

[@jaredkusner1137]

Your use of the schematic, circuit, and test equipment made it fun to walk through. I really enjoy the back to basics. Thank you.

[@njnear]

I really enjoy your videos. The back-to-basics posts are always interesting, and great reminders of why I wanted to be an electrical engineer to begin with. Thank you for the effort you put into these. Also enjoyed your visit on The Amp-Hour.

[@w2aew]

Thanks! I enjoyed talking with Chris and Dave.

[@osvaldocristo]

Thank you. I was looking for if the diode type could be significant in the circuit performance and the peak current value in the snubber diode. You answered both questions.

[@tdumnxy]

Very clear and useful, thank you.When you show the circuit diagram, do the experiment and explain the resultant trace(s) on the oscilloscope, it really helps in understanding the theory. Inspired by your KZbin videos and by the efforts of a few others on YT I have been motivated to get a radio license. I am taking the Foundation course and exam this coming weekend. Wish me luck and many thanks for sharing your knowledge and enthusiasm.

[@w2aew]

Great! Good luck with the exam, and hope to catch you on the air in the future!

[@___xyz___]

Is getting a ham radio licence something you would recommend? I'm a physics freshman and electrical engineering enthusiast of a few years. I own a good Tek 2232 and always look forward to your scope videos. Lately, I've been exposed to a lot of applications for radio transmissions, especially the capability for spectral analysis with a SDR and satellite communications, with FM stations sadly being "shut down" across Norway. I looked into a licence this winter and realised there are some things I anyway ought to know about circuits. But whether it is still a worthwhile pursuit to acquire a licence is beyond me.

[@iddiadam857]

Hello steven i am from africa(kenya).

[@kd5ozy]

Aaaaaaah, your videos are always refreshing. There are things I forget about and take for granted. Your videos are by far the best and the most informative. Thanks!

[@SkypowerwithKarl]

Thank you! You are so easy to follow. Never have I learned so much so quickly. I’m an old fart trying to figure out the diode polarization across a fuel solenoid on a boat. I wanted to protect the contacts of the relay from fly back voltage. Just the opposite of a LED. Your diagram showing (+) was great help. Thanks. PS I sure hope you are a teacher

[@w2aew]

Nope - not a teacher. I'm a Field Applications Engineer for Tektronix (Test & Measurement Equipment).

[@jenko701]

Great video, I've been a TV tech for over 25 years and have seen this circuit all my life and never gave it a second thought , but it makes a lot of sense . Every once in a wile you will find this diode shorted ,but it's almost always because of lightning.

[@normandgallant8106]

Best basic tuturial sofar and I've been using KZbin for some years , thanks for your time

[@curtisbeef]

I use flyback diodes in brushed motor control. This video was extremely helpful to understanding why! Thanks! I love the Back to Basics videos.

[@SuperJetjockey]

I never tire of watching your informative videos. Bob

[@Radiowild]

I used to carry a roll of diodes in the back of my company car when I would find diodes missing from high current relay coils in equipment that was removed in the field! Nice Vid!

[@krishnakhandelwal9466]

I was so confused. I heard people saying that when we suddenly stop flow of current through an inductor, it generates a reverse voltage. I was not able to visualize it. But now I understood. It's the increase in voltage at other terminal. Due to this diode gets forward biased and allow passing of this high voltage through it. Now, it's clear. Thank you so very much.

[@edwardvan00]

Excellent presentation and tutorial for a method to protect sensitive electronics used in many applications. I particularly found it interesting when getting advice from SilverLeaf Electronics tech support on protecting their circuits from a suspected issue with a White Rogers solenoid used as a bridging circuit for house and chassis batteries in our RV. Protection for expensive controllers is of utmost concern and importance. Thank you for the education.

[@mattrothe149]

Good video all the experimenters should see this. you could do a series on protection. Back in the day we used to ask "What does a diode want to do?" or a coil, electron, etc. I miss that. A coil with a diode on top, sounds delicious. Adding small cap on the base of Q1 can expand your slew. I know many think this is a bad thing but, it's how rock-n-role survived a light show. The inductor was a hodgepodge of long conductors hung on iron pipes by mentally altered monkeys who have the magical ability to make voltage appear inexplicably. Sometimes from using beer as a conductor, circuits could fall like dominoes. Extreme measures were needed. Two way protection. First a half bridge, then a BJT with cap, then maybe a resistor every 200 feet. Rely on just one diode? No, not with a monkey assembled systems. It was a good presentation and I love your scope.

[@PlasmaHH]

The choice of a diode is important when you want to control the switchoff time of the relay. People use zeners, cascaded diodes, diodes with resistors etc. to dissipate the energy faster. Some people also just use a LED to even have a visual indication of this process.

[@ichigo_varactor358]

You'll find the same thing on the primary of the flyback transformer of old TV's. Their horizontal output transistors usually have that diode built in along with a breakdown voltage of 1500v. There are also some retrace capacitors on it to slow down the collapse of the magnetic field. That is just an interesting application of flyback diodes.

[@brucenguyen6527]

Very thorough explanation. My professor sent me here and I’m glad I listened…this time

[@44mod]

Great Video. you made the video in 2014 and today I am still learning from your video in 2020. Thank you so much. I saw a video and can not find it again with a compositor was used between the emitter and collector. I can not remember why it was used and I am going back to research why.

[@robytryall]

This was the best educative video, I have seen in a while!

[@dp0813]

Awesome video! I understood this concept in theory in my power Electronics classes for my electrical engineering curriculum, but never actually got to see it in practice like you've demonstrated here. Definitely very helpful and a must for any University teaching this type of material!

[@jluke6861]

What a great video and great explanation. Thank you for taking the time and sharing this with us.

[@robertcalkjr.8325]

Thanks Alan. There is so much to learn that it's easy to forget basic stuff sometimes.

[@dirkg3343]

When using a MOSFET instead of a bipolar transistor to control the relay, the reverse recovery time of the flyback diode may become important as the switch-off time of the MOSFET is much lower. I experienced that many years ago when using a 1N4001 with trr of 1500 ns instead of an 1N4148 with trr of 4 ns. The MOSFET died after only one operation due to excessive Drain-Source voltage.

[@jimfromcolo]

I've used diodes for this reason for many years, I've added them across relays on older American cars with relay operated components to make the switches last longer, it eliminates the transient spike across the contacts as the switch was turned off.

[@Observ45er]

+Jim Patterson That's a common example. When the switch opens, the inductor's high voltage causes the switch contacts to arc. This shows very well how the inductor will "Do what it takes" to the voltage, to maintain the current flowing through it.The high voltage arc that forms as the switch contacts spread apart will erode the contact material.

[@conorpodonoghue]

Great video - comprehensive and to the point. Many thanks.

[@kresoptube]

Hello ! I have a few questions. 1. Why did you put 50 ohm shunt resistor? 2. At 4:30 It took almost 10us for that first transistor to start shutting down and another 4us to shut down. Is it possible to read that from data sheet? Second transistor started shutting down immediately 3. Why did the current go negative (Ch3) ? It looks like current through the diode when it gets reversed biased and diode is still conducting due to recovery time but transistor didn't get reversed biased here. I like your videos because you show what is going on in that split second when in the book we only see straight line (usually vertical) Thanks!

[@rodeliohernandez2251]

....the videos you present here are basically the ACTUAL tools technical guys needs to start with.....maraming salamat ( thank you in Filipino).

[@w2aew]

Rodelio Hernandez ikaw ay malugod! (thank you google translate!)

[@will.patton]

Excellent post - thank you! I was surprised to see the voltage so high (i.e. nearly 300v). Thank you for explaining that most any diode/rectifier will do, too.

[@VeryMuchBlessed]

Super helpful in understanding and seeing in real-time the wave-form generated with/without the snubber diode. I've been using them in my circuits but it's cool to see it on the oscilloscope which makes it much more clear. Thanks much

[@AB1Vampire]

Really good video, I learned much thanks for posting. I recently found some TE Application Notes that tried to minimize the coil collapse time of a NO DC relay by adding a series zener to the diode. Apparenly such an arrangement reduces the average 19ms coil collapse time for a diode alone. Zener & diode connected parallel to coil in K to K or Anode to Anode.

[@onurolce]

13:03 I've a question. Should we use another diode for protect power supply from inductive spike which is going to eliminate by flyback diode? Think that put another serial 1N4001 to +5V ?

[@dancoz5477]

Bien expliqué avec démo pratiques appropriés et suivis. Bravo monsieur.

[@wk2w]

Very effective demonstration. I've recommended this video to others when the subject comes up.

[@DonatoGreco]

I really enjoy this kind of educational with the scope to showcase the theoretical concepts. A big thumbs up 👍

[@kristhetrader5029]

Excellent video as always Alan! As for my myself, for all of the signal dual latching relays I use in my designs (about 80 relays on one of them) I use the famous ULN2003D relay driver which happens to include that protection diode as standard, highly recommended for many signal relays. Keep them up!!

[@fahey6797]

Now I understand how an ignition coil works. Thanks.

[@SujeetKumar-lv2dd]

Now I got Power to visualise the Saturation of Transistor Vs non Saturation Graph. Thanks for discussing every minutes​ of snubber :)

[@TheRedLava]

Amazing video! Even after 5 years of being posted it's gold! Thank you very much for your knowledge sharing :)

[@G4KDXlive]

Thank you. I am about to build an RF triggered switchover for a transmitter. I wondered why there was a diode across the antenna relay. All is now clear.

[@guillep2k]

I'm a simple man. I see a four channel oscilloscope and I upvote.

[@josmunpav]

Great video, very easy to understand why the diode is needed. By the way, awesome Oscilloscope you have there, I checked it out and is about 15 grand!!!

[@spu3]

Excellent! Very clear and useful. Enjoyed the use of the oscilloscope. Really helps to visualize what's going on.

[@uiticus]

At timeline 5:09 , why didn't the high voltage pulse of nearly 250 volts appear at the collector of the transistor the instant the trigger pulse went to zero volts? There was a delay of the high voltage pulse appearing at the collector. Also, could you have used a capacitor instead of a diode to squelch the high voltage pulse?

[@Yojimbonh]

Great explanation. I especially like seeing the waveform shapes to see what is actually happening.

[@bigstuff52]

Enjoy your video tutorials. Also your use of graph paper. I picked up on using it also, when I started reading Forrest Mims in the early 70s from his Radio Shack tuitorials....thanks..

[@salocin86]

Very informative video. This information pertains to a DIY circuit I am currently trying to figure out. I hadn't though about Inductive Kickback. Now I have to start from scratch to figure out how to wire up my water pump setup with two float switches. Everything is running on 12VDC. If you're getting 100V from just a 5V input, I can't imagine how high my voltage will go. Pump is running about 1.5 amps running. I don't have an inrush current reading.

[@schmittenhammer]

Thanks, very informative and clear. Appreciate your time in sharing this information. Maybe I will stop burning up transistors.

[@chawkzero]

Thoroughly informative as always! Thank you, Alan. Back to basics are my favorites! I do have a question regarding the flyback voltage from the inductor forcing current into the positive supply. In general, is this potentially harmful to a DC power supply? Does it vary by power supply type (battery vs linear regulated vs switch-mode, etc)? In simpler DC circuits without inductive kickback, this is generally not something I have to worry about in my analysis, but obviously in this case, the voltage is indeed rising above the supply, so it seems current should be flowing _into_ the supply rather than _out of_ like I'm used to. Is it useful to include this in the circuit analysis? I'm not sure what to make of it. As a hobbyist and self-learner, thanks again for all your work!

[@kalhana_photography]

The current doesn't flow into the supply rails. It circulates through the diode and back through the coil in a circle and the energy eventually dissipates in the parasitic resistance of the coil and diode etc. The 5.8V at the anode is seen because of the forward voltage drop of the diode. (The anode must be ~0.7V above the cathode which is connected to 5V rail for the diode to conduct)

[@w2aew]

kalhana1 Exactly right.

[@chawkzero]

kalhana1 Ah of course! That makes sense. Are there any circumstances in which there could be current actually flowing into the supply? Thanks!

[@kalhana_photography]

chawkzero It can happen when controlling motors. When you want to stop the motor (braking stage), you may get this issue if the PSU can't accept the regenerated energy. There are different ways to deal with it such as dump resistors etc. Check out the following link from TI. e2e.ti.com/blogs_/b/motordrivecontrol/archive/2013/10/18/the-art-of-stopping-a-motor.aspx

[@Observ45er]

kalhana1 This is absolutely correct. When you slow a motor, it *can* become enough of a generator to actually drive current into the power supply rail and raise the voltage. In designing an AC 3-phase induction motor (yes induction) variable speed drive, if the drive tries to slow the motor faster than it will naturally coast down, a circuit I was part of a design team on, did that and would blow some output transistors. This was before we installed a circuit to keep the drive from getting ahead of the motor coast-down rate, so to speak. We did not have breaking circuitry in there for that. 73

[@ericprice2033]

This was a great find. I like how you explained things. Exactly what I needed to get my electromagnet circuit going.

[@pboston6RR]

Fantastic presentation! The Arduino projects that I have been doing show how susceptible the Arduino is to this back EMF. Projects that work on the bench before connecting to the external relays we use work fine until the first turnoff of the circuit and the relay is released. Crashes almost every time. Sometimes it takes out the Arduino itself. 😳

[@stefflus08]

A flyback is something I've just done, it's very nice to finally see it visualized in traces. But I've been wondering, if there's very little "absorption" in the 5v rail in this instance, maybe a 7805 or a USB and little or no capacitance (bypass caps for instance) could it spike on that rail instead?

[@structure7]

I'm glad this was the first video that came up searching for this topic! Thank you!

[@billybonewhacker]

Thank you so much. It's very helpful to see it all on a scope. Plus it forces me to remember how current flows through a circuit. Great job.

[@edwardvan00]

Always a good refresher for saving sensitive electronics around solenoids and such in an RV. Thanks for the tutorial and excellent video. I share it as questions come up in various forum.

[@cmuller1441]

The problem with that diode is that the current in the coil and its magnetic Flux decrease quite slowly because dI/dt=V/L. So we want to let the highest possible voltage appears on the coil terminals. Of course we should limit it to avoid any damage to the transistor. Do you think that adding a zener diode (reversed) in series to the diode to keep the one way behavior but with higher threshold could be a solution?

[@MrKlautman]

Really excellent video, Alan. Just happened to stumble across it looking for this sort of information, but for AC-driven coils, Any chance of you doing a video on those? Snubber design is a little more complex for them, which is why I'm seeking out info. Also, at 1:51 you state that the current induced by the collapsing magnetic field flows in the same direction as the original current, and reiterate this at 6:50. I've always been confused by this issue since (1) there's no place for the current to "go," so it shouldn't flow anywhere, and (2) the voltage drop across an inductor is L * di/dt, so the voltage drop must be negative as the current goes to 0, so current must be negative since V = I * R. But a negative current implies it flows into the power supply. It'd be great if you could sort this out.

[@w2aew]

When the transistor turns off, the current that was flowing out of the "bottom" of the coil now sees a different (much higher) impedance, thus the voltage rises. Since the "top" of the coil is "pinned" to the supply, the voltage at the bottom begins to rise. The math works - the current is falling, so the di/dt term is negative, and this corresponds to the voltage across the coil reversing its polarity. The current flows through the diode that is in parallel with the coil.

[@IsaacC20]

@7:05 Where does the excess current flow? Back through the 5V supply or through the probes? both?

[@MS-ef1gy]

Through the top of coil...the diode is connected directly to the top of the coil...so current takes less resistant path back through the coil. The schematic makes it appear to some like it passes through the 5V supply...when actually the wire is connected back to the top of the coil.

[@philipsilvester]

you said i hope you learnt a little, i learnt alot thanks for sharing.......thanks phil.....can i just say those scope shots were fantastic..

[@FluorescentApe]

Really enjoyed the explanation, easy to follow, but i really love those instruments you're using! Sadly i don't wanna give my arm for those.

[@w2aew]

Yeah - one of the benefits of working for Tektronix as a Field Applications Engineer - I get access to really great tools!

[@johnbyrne1022]

The waveforms around 1:20 are fascinating. I've seen this before with crankshaft sensors, but I don't understand it. Why are there 2 peaks, one positive and one negative? Which part of the waveform corresponds to the inductor being closest to the magnet? If the motion is constant, then I would expect the wave to be symmetrical, in which case the zero crossing is the closest point. But then what causes the voltage to change direction just before and just after that point?

[@emilrodriguez5696]

Great explanation! Very helpful! I'm also with @James Wood, it would be great if you could cover how RC snubbers are designed and work. For example, for the case when an AC Motor or other inductive load is connected to the contacts of a Relay. I've noticed sufficient disturbance on the control circuit to cause microcontroller reset and other unwanted effects...

[@nickpelov]

what about other type of snubbers and benefits (release time, relay life) from them - RC, Zener+diode ... etc. could you make a video about them?

[@supernova86]

I wonder the same thing

[@freddiemortos8519]

Another great back to basic tutorial. Looking forward to see more on this in your future video.

[@hadibq]

Impressive how high the voltage can go with a little 5v coil 👍 Thanks for sharing the experiment 🙏

[@stephenhearn472]

Awesome video! Thanks for taking the time.

[@stoneslice]

Outstanding and informative video. Thanks so much Alan for making it. The current probe is a great bit of kit!

[@StrummerDave]

Best explanation I’ve ever heard. Thx

[@akashnigam010]

Thanks for such a great video.....Surely, I am not going to miss putting a fly back diode with the relay after watching this video.

[@grampymeyer6603]

As usual you make it simple (aka back to basics).. anyway, I love that your magnet is on a free Harbor Freight flashlight.. I recognized it immediately, I must have 20 of those layin' around the shop....

[@jimadams2473]

Another GREAT video. THANKS!! This is the best video on electro-magnetics I have seen. Appreciate the time and energy you inject into these instructional videos.

[@ralphchen1125]

Nice explanation. Do you know what will happen when current flow back through flyback diode? Will this damage the power supply?

[@w2aew]

no damage to the power supply.

[@famossfla]

Another superb explanation... Thanks again Alan.