Physics Ninja looks at the derivation of the wave equation for a wave on a string.
Пікірлер: 31
@millenniumcreativestudio50818 ай бұрын
After this much approximation , I think the equation is literally useless.
@5gallonsofwater4954 ай бұрын
That's just how physicists do their thing. I'm pretty sure this only works for an idealized model. A lot of the proofs I've seen come from idealized models, and the formulas that come out are pretty reliable.
@laddu-jillu3583Ай бұрын
welcome to physics
@sirwinston236811 ай бұрын
Nice derivation. I have watched a few other derivations and yours seemed to make the most sense to me. Appreciate it. Thank you.
@PhysicsNinja11 ай бұрын
Glad it was helpful!
@griffithfimeto33875 ай бұрын
Since tension is unofirm and theta 1 equals theta 2 then sum of forces over Y equals zero not ma
@kina4288 Жыл бұрын
Always appreciate your quality videos. In this instance, does the equation only hold if the angles are small, which was our assumption in the derivation. Thank you.
@PhysicsNinja Жыл бұрын
yes, however the analysis doesn't indicated how small. For large amplitudes there would be another term (non-linear wave equation) that would need to be included. For waves on a string the basic wave equation seems to do a pretty good job for larger amplitudes which tells me that the non-linear terms are probably small.
@edoardo_rubino5 ай бұрын
why do we use theta1=theta1 in the horizontal direction but not in the vertical direction?
@PhysicsNinja5 ай бұрын
You can expand trig function and keep only terms up to linear terms. Others terms will be small if thetas are small. So cos theta is approx 1 and sin theta terms are approx theta.
@mrslave4114 күн бұрын
11:01 “previous” i didn’t watch. now i’m lost. please don’t tell me to watch another video now. 😢😢😢😢
@petergoh5628 Жыл бұрын
Why is delta(m) = mudelta(x)? Shouldn’t it be mudelta(s) which is the segment along the string? Or a we assuming since theta is small delta(s) and x are the same
@PhysicsNinja Жыл бұрын
Yes
@lenops-uu7bw7 ай бұрын
its bcoz mu(the mass density)= del m(mass)/del x(displacement)
@ahmetcoskuntekin59568 ай бұрын
En büyük müsün bilmiyorum ama çok büyüksün ninja abi.
@ecekaraa6 ай бұрын
you explained one by one clearly. Thank you!
@Neel-Joshii5 ай бұрын
At 5:17 -- I understand that you used the small angle approximation assuming that both theta1 and theta2 would be equal along line segments bounded by delta x. My question is how exactly were you able to use the small angle approximation for ALL points along the string. Take for instance the points between any trough and peak, how would you be able to apply the approximation to those points where theta1 and theta2 would (at least by first glance) not be small enough to having sin (theta) = tan (theta)?
@PhysicsNinja5 ай бұрын
You are making small angle approximation for 2 points that are infinitesimally close to each other.
@anilkumarsharma8901 Жыл бұрын
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@mohammadibrahimahmad7546 Жыл бұрын
elaborate explanation, thanks bro
@PhysicsNinja Жыл бұрын
You are welcome
@UtkarshPal23BCE0474 ай бұрын
naah bro explained exponentially better than my proff. 😭
@organic_antelope2 ай бұрын
Very helpful thank youuu
@kw407010 ай бұрын
What's the purpose of the small angle approximation here? And why do we assume theta is a relatively small angle?
@theiigotriangularround48808 ай бұрын
To make the equation easier , you could find this for large angle but irl small angle works just fine
@aditya_asundiАй бұрын
THANKS
@PhysicsNinjaАй бұрын
You're welcome!
@anilkumarsharma8901 Жыл бұрын
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