As a Ph.D. Student in algebraic topology it is hard to explain to the average person what I study, so it is cool to finally see a very approachable explanation. I personally study how homotopy and homology/cohomology groups change when taking some kind of product of two or more topological spaces, specifically wild topological spaces. It is interesting how the average person might think the fundamental group is trivial to compute, but we still have researchers like me trying to find ways to actually find ways to compute these fundamental groups for some pretty simple spaces.
@mastershooter6411 ай бұрын
Hi, is it possible to extend ideas of homology and cohomology to study infinite dimensional holes on stuff like hilbert manifolds or frechet manifolds (generalizations of manifolds to inf dims)? Is there research being done on this?
@Koisheep11 ай бұрын
@@mastershooter64 Hi, my field of study is singularity theory (more about polynomials and less about groups) but I can tell you that homology and cohomology are defined for any topological space, although there are different "theories" that one uses depending on the context. All of them are equivalent in the sense that you get the same groups no matter what theory you use, but one important thing is that you have a powerful tool called the "Mayer-Vietoris" sequence, which allows you to break out your space into chunks and recompose the (co) homology groups of the whole by using the (co) homologies of the chunks. For example: a circumference can be broken into two overlapping curves. Each curve is a segment, and the homology of the segment is trivial to compute. Therefore, the homology of the segment gives you the homology of the circumference! This is very simplified because this is just a KZbin comment, but I hope this gives you some insight.
@logankennedy708211 ай бұрын
Homotopy groups are valid for any topological space as you are only looking at the mapping of circles and hyper spheres into the space. As for homology, if your manifold is under four dimensional it is triangulable so simplicial homologies and cohomology theories should work, and I don’t see why singular homology and cohomology theories wouldn’t also work in any dimension of these manifolds.
@gianlucadegliesposti724111 ай бұрын
can you point out some literature with the techniques you use? I'm also interested
@Aesthetycs11 ай бұрын
@@mastershooter64 Fun fact: Infinite dimensional holes are contractable, and infinite dimensional space hence have a trivial topology.
@RyeedAglan11 ай бұрын
Me: There's a hole in your proof! Topologist: You're welcome.
@LookingGlassUniverse11 ай бұрын
Beautiful! I love the blending of different styles in this video
@Aleph011 ай бұрын
Thanks Mithuna!
@tracyh575111 ай бұрын
0:12 Bless Poincaré, writing such an important paper at the youthful age of 131 years old.
@Gordy-io8sb8 ай бұрын
He died at 58. That is exactly 73 years younger than 131. I don't think *anyone* has lived to that age.
@Gordy-io8sb8 ай бұрын
The oldest anyone has lived is 122. That's 9 years (a singular year off from being an entire decade) younger than 131. So no, he did not.
@Gordy-io8sb8 ай бұрын
Poincaré didn't even live to his 60s (although he was close), and that's still far, far off from 131.
@jonahansen7 ай бұрын
@@Gordy-io8sb John Smith (Chippewa Indian) claimed to be 137 when he died. Of course, this is disputed but is in Wikipedia...
@nucreation44847 ай бұрын
In the video, the narrator mentioned the date of poincare's paper as being written in the 1980's @@Gordy-io8sb
@rentristandelacruz11 ай бұрын
As a wise philosopher once said "The souls meet where the holes meet".
@kasiphia11 ай бұрын
💀
@pedroivog.s.687011 ай бұрын
Nice, you're talking about the mouths, right?
@PRIYANSH_SUTHAR11 ай бұрын
😶🌫️
@ehfik11 ай бұрын
amazing
@naingaung274811 ай бұрын
Docking?
@kikivoorburg11 ай бұрын
I was just thinking about SO(3) having a hole bc it doesn’t allow for the contraction of 2π-rotation loops, then you used it as an example - fun!
@eemilwallin334711 ай бұрын
This was a really nice video because I've often seen the symbol for the fundamental group but I have not grasped the concept well enough. Esp. I do know that R^2 minus a point is not simply-connected (or 1-connected), but the fact that the fundamental group is integers is mind blowing. While intuitively the direction of a loop matters, I did not grasp the formal reasoning for it. I'd be delighted if anyone could point it out for me.
@wikiPika11 ай бұрын
Consider two objects in the fundamental group A, B. The group is equipped with an operator * that concatenates the two loops together. Consider the number of times a given object loops around itself as the number of interest. Note that the loops that do not go around the deleted point are homotopic to a point, so they go around themselves zero times (let's define this, as "going around yourself" only makes sense in 2D and points are zero-dimensional) And note that loops that do go around the deleted point are not homotopic to a point, so they must go around themselves at least once (in some direction). Why does the direction matter? This is far easier as a visual proof. Consider loop A, which goes around the origin CW once; loop B, which goes around the origin CCW once. A * B yields an object that first goes CW around the origin once, then CCW around the origin once. But note that there is a way to trace A * B without ever fully going around the origin! Just double back on B's path after finishing A's path. Indeed, A * B is homotopic to a point. Let's assign zero to the "homotopic to a point" loops, positive numbers to the loops that go CW around the origin, and negative numbers that go CCW (or the other way around, it doesn't matter). We see that if we concatenate two CW loops C, D => C * D, the number of times C * D loops is exactly equal to loops in C + loops in D. If we concatenate two CCW loops E, F => E * F, the same applies. But if we concatenate two loops of opposite orientation G, H => G * H, the number of loops subtracts. Each loop in H "undoes" a loop in G until (potentially) no more loops exist; then the rest of the loops (if there are any) will come from finishing the path of H. Well, isn't this just like adding a positive and negative number? Ex. 3 + (-7), the -7 "undoes" 3, and what's left is -4. A CW loop with 3 loops concatenated to a CCW loop with 7 loops yields a CCW loop with 4 loops.
@eemilwallin334711 ай бұрын
@@wikiPika Thank you for your answer! Going "around" a point does seem to formally require an interior, with the loop forming a boundary and "around" being the part of space where the point also is (point p is subset of some set A which is subset of whole space). I guess the point could also lie on on the loop and with the homotopic property a loop which contains the point fits the above pondering about the interior.
@wikiPika11 ай бұрын
@@eemilwallin3347 If the loop has p ON its boundary, then... it actually does not exist! This is because the loop is therefore not within the space X \ {p} (well, no shit, the path contains p). Therefore we can ignore this edge case.
@completo317211 ай бұрын
Here's another explanation of it that doesn't use the concept of fundamental group (in my topology class we didn't get to see the fundamental group, and we saw this at the start of the homotopy lectures). The idea is that you can consider, given a path f from an interval L to the unit circle U, another path g from L to R, the real numbers, such that given the function p from R to U such that p(t) = (cos(2•pi•t), sen(2•pi•t)), you have that f is equal to the composition of g and p. That is just considering g and kind of "projecting it" to the circle. It turns out that not only you can always do this, but also given two homotopic paths from L to U, their respective paths from L to R are also homotopic. The demonstration relies on differential geometry, as you use the existence of an angle function locally and extend it's domain both to find the path from L to R and to have the homotopy property I mentioned previously. Having this fact, it is sufficient to consider two paths (cos(2pi•n•t), sen(2pi•n•t)) and (cos(2pi•m•t), sen(2pi•m•t)) from L = [0,1] to U, these are closed paths on U that do n and m loops around the circle respectively. It is clear that their respective paths from L to R are 2pi•n•t and 2pi•m•t respectively, and those paths can't be homotopic because their ending points aren't the same. Because every two paths with the same starting and ending points in R are homotopic, given two paths f and g from L to U with the same number of loops around the circle and given their respective paths from L to R, f' and g', the last two will be homotopic. As p is continuous, the composition of p with f' and the composition of p with g', that is, f and g, will be homotopic. The redaction isn't the best but I hope it was understandable :)
@chobes182711 ай бұрын
The formal reasoning isn't really in this video at all, and I would argue that this isn't the most visually / geometrically apparent fact. The fact that the fundamental group of the punctured plane is the integers is typically proven by reducing the problem to computing the fundamental group of a circle (the rigorous details are a bit lengthy and typically use even more machinery, but it's a lot easier to intuitively convince yourself of this). The idea behind the reduction is that we can continuously map each point in the punctured plane to a unique point on the unit circle (the map is dividing a point x by its norm) while fixing the entire unit circle. Then, we can construct a homotopy between that mapping and the identity map on the punctured plane (each point moves towards the unit circle along the unique line connecting it to the origin). Using this homotopy, we can show that our map from the punctured plane to the circle is "homotopy equivalent" to the inclusion map from the circle to the punctured plane (this means if you compose the two maps in either order, the result is homotopic to the identity map in the image space). Using some algebraic / categorical tools we can easily show that homotopy equivalent spaces have isomorphic fundamental groups. Thus we can conclude that the fundamental group of the punctured plane is isomorphic to the fundamental group of the circle, which is Z.
@Npvsp11 ай бұрын
Adding a resource: I studied algebraic topology from the book of Spanier (algebraic topology, Springer), and to me this is the best reference possible. Hatcher is fine, but Spanier book is perfect.😊great video as always!
@UJ-nt5oo11 ай бұрын
0:15 bro you legit had me thinking poincare was still alive. i think you meant 1895
@eguineldo11 ай бұрын
I rewatched several times because I heard it too.
@nahidhkurdi674011 ай бұрын
Beacause I know Poincare was dead since 1912, I did not hesitate. I presumed he meant 1895.
@StratosFair11 ай бұрын
I am into analysis and statistics so I know nothing about this stuff, but I was always interested to learn it. So thank you for giving a super accessible intro, and happy new year !
@maynardtrendle82011 ай бұрын
This was absolutely wonderful!😊 Thank you for the clarity.🌱
@tylerbakeman10 ай бұрын
*Every Set that has those 3 properties is referred to as a “Groupoid” (A Category with isomorphisms). A “Group” restricts the Signature of the System to a single operation (sometimes called the group “action”). Russel set / generalized set is implied here if that’s important to anyone.
@luquest184811 ай бұрын
Thanks Aleph0, always look forward to your videos
@celkat11 ай бұрын
Very cool - subscribed. (Microquibble: Analysis Situs was published in 1895, not 1985)
@pursuingstacks11 ай бұрын
Was about to point this out but then I saw this comment.
@rhodesmusicofficial11 ай бұрын
wonderful! it's so awesome to see your iconic style of presentation applied to my favorite subject
@emilmullerv351911 ай бұрын
Some obersevartions are needed. 1. The fundamental group doesnt necessarily encode our intuitive idea of a hole ina. Space. Take the topologist circle, which has fundamental group trivial, but clearly has a hole. Or a sphere. 2. The fundsmental group also requires to fix a point in space, however for path connected spaces, the point you choose doesnt chsnge the structure of the group, so it can be avoided to simplify the notstion. 3. While I like your explanation for the fundamental group of the circle, I've liked if you had mentioned hiw extremely hsrd is to justify that intuition, and how in general computing htje fundamentsl group is an extremely complcated task
@gabrielvieira302611 ай бұрын
What are you taking as topologist sine? The curve glued like a strange circle?
@Aesthetycs11 ай бұрын
It is quite easy to prove R/x has a hole.
@emilmullerv351911 ай бұрын
@@gabrielvieira3026 mistake on my part, I meant the topologist circle.
@emilmullerv351911 ай бұрын
@@Aesthetycs it's not lol, the intuition is easy. Show me an "easy" proof
@Aesthetycs11 ай бұрын
@@emilmullerv3519 Basically for any missing point in R, for any pair of path connected points, and for any region of space you can define having the missing point within and the pair on its boundary, the two pieces of boundary connecting the pair do not have the inner region as their path homotopy since a homotopy function should have the entire region as its domain yet the function is undefined on the missing point.
@cephassvosve2967 ай бұрын
This was the best explanation that helped me understand the poincare conjecture!
@languafranter345011 ай бұрын
Excellent work down, I really enjoy this kind of explanation in the field of pure mathematics :D
@BriggsProgrammingDevelopment11 ай бұрын
Your videos are always precise, while digestible, this video is no exception
@jilljohn263810 ай бұрын
So I can eat the vid?????????????????????????? *proceeds to eat part of my memory card*
@gregoryfenn146210 ай бұрын
What we can all agree on is that each of these holes is indeed a goal.
@xzockerx519711 ай бұрын
This is a great video, although there is a detail that should not be ignored. The fundamental group depends on a point in the topological space X. It is NOT the set of all loops with concatenation as binary operation. It is the set of all loops starting in a specific point p of X with the concatenation as binary operation of loops. This is important for two reasons: 1) The space X can have more than one connection component. If the space X is path connected, then one can show easily that the fundamental group is up to isomorphy uniquely determined, i.e. not point dependent. But if this is not the case, then it can depend on the connection component. An easy example would be the disjoint union of two topological spaces, one with a trivial fundamental group and one with a nontrivial one. 2) The fundamental group would not be a group without this point dependence, because the concatenation of two loops, starting at different points is not defined. Without these two remarks the video could be a bit misleading, cause for example at minute 5:11 the "multiplication" (concatenation) wouldnt even be defined, but since R\{0} is path connected, everything works out nicely.
@soundzz487111 ай бұрын
at 4:20 , 1 should be the order of the group pi(R) to be precise (or pi(R) the group that only has the neutral element, depending on what you were going for here)
@dottormaelstrom11 ай бұрын
Just a heads up, the fundamental group doesn't encode holes precisely: for example it doesn't distinguish a ball from a sphere (which, arguably, has a "hole", that being the "missing interior"), they both have fundamental group 1. The correct mathematical structure to model holes is called homology, and in some cases it is linked to the fundamental group (for example in the case of compact 2-surfaces without boundary they are actually equivalent), but generally the homology groups contain more information than just the fundamental group. You could consider higher homotopy groups but those turn out to be unmanageable in practice.
@persistenthomology11 ай бұрын
Came here to comment this. Homology would've been more appropriate here I think. Homotopy groups aren't really about holes as they are about maps of spheres into your space.
@dottormaelstrom11 ай бұрын
@@persistenthomology it perplexes me because this channel also has an excellent video about homology in which the guy defines holes in the correct way, so I'm not sure what the deal is
@gchtrivs789711 ай бұрын
Homology also doesn't define what a hole is. "Hole" is not a well-defined mathematical concept.
@logankennedy708211 ай бұрын
Homology groups actually lose information about the space in order to more conveniently describe the structure of the holes in the space.
@gabrielvieira302611 ай бұрын
Fundamental Group and Homology don't coincide for all compact 2-manifolds, just for the Sphere, the Torus, and the Real Projective Plane. The others don't have Abelian Fundamental Group.
@estebanguerrero68211 ай бұрын
Love the content, thanks so much
@user-cw7kl6fu7p10 ай бұрын
Lovely! My background is physics and my intended applications are in physics and engineering. During my studies my mathematics books had the addition "for physicists", like "Group Theory for Physicists". Can you recommend a resource covering the topic of holes but "for physicists"? In case you are interested: I am currently doing a project which involves moving holes around using solid bodies. A single hole is trivial, simply have a single hole in a single body and move the body. The non-trivial problem is: take three holes in the plane. Let their motion perform a braid (yes, a braid theoretical braid), find a set of solid bodies which accomplishes this. Why? In engineering you need to actuate motion. Using solid bodies to hold a tube and move in in the plane is a more elegant way (my physics background) of actuating motions than gears and sticks and sticks and gear and....linearized inelegant simplicity.
@cparks100000011 ай бұрын
The fundamental group doesn't count all holes. Simply consider the 3-dimemsional Euclidean space with the origin removed and call it X. The map f(x,t)=x/((1-t) + t |x|) is a homotopy from X to the 2-sphere. Since the 2-sphere is simply connected, X has trivial fundamental group. However, the unit sphere in X cannot be contracted, so X has a hole. Also, forgetting the base-point of the fundamental group doesn't help the exposition in my opinion.
@Rubikorigami11 ай бұрын
Really nice and clear video ! I gotta say, I'm more of a fan of the all-paper look of your previous videos as it feels a lot more cohesive design-wise, but I get the need for 3d stuff and CG anims. Also, I think there may be a tiny issue with the exporting of the video where you play with the plate - it looks super pixelated for me even though the rest of the vid was nice and crisp. Anyway, nice work as always ! Keep it up :)
@davidsuchodoll412411 ай бұрын
I am so sorry to be specific, but you are defining the Fundamental Groupiod, if you choose not to specify a basepoint. You run into problems, e.g. if you have more than one component
@punditgi11 ай бұрын
Fascinating video! 😊
@mikelolis375011 ай бұрын
Just to add to the resources: Hatcher tends to handwave quite a bit in his book and is sometimes difficult to follow. If you're more algebraically minded Rotman has an excellent book on the subject
@DiggerDwarfy11 ай бұрын
I wouldn't call it handwaving, but his sentences are very dense and often times hard to follow if you don't already know where he's going with all of it. From personal experience, I'd say his book is a lot better as a second look to deepen your understanding of the topic (his examples are often gorgeous) but is really bad to get through the first time around without a guide (like a lecture series)
@newwaveinfantry836211 ай бұрын
One of the best math channels.
@1987Raziell2 ай бұрын
your content is significantly more difficult than 3blue1brown, Numberphile and etc. // love it!
@Nylspider11 ай бұрын
New Aleph 0 video dropped :3
@TotalTimoTime11 ай бұрын
I think this video could have benefited from a little more explanation on the procedures. Like the beginning example looks like you could just shrink the loop further over the hole because its 3d. Or the fact that all loops in the plane are the homotopic to a point. Or the whole plate and arm thing: you are saying the plate ends at the same point but are showing it moving on the screen with two different positions. Im sure if you know all these concepts it makes sense but stuff like this makes the learning inaccessible. I‘d encourage just a little more exposition when doing „experiments“ with the viewer
@aretorta11 ай бұрын
This! I had a hard time understanding the arm trick because of the lack of context. One needs to firmly establish the analogy.
@jongraham886611 ай бұрын
By the way, your videos make me think that perhaps, if I worked hard enough, I could understand some higher math. Keep it up!
@stevenfallinge714910 ай бұрын
Start with reading a book about mathematical logic. It's the most important subject for understanding math at all.
@Kycilak10 ай бұрын
@@stevenfallinge7149 The playlist Proof Writing by MathMajor (second channel of Michael Penn) might be a good intro?
@ChaabaneGaith11 ай бұрын
this is gold
@GiovannaIwishyou11 ай бұрын
This is exactly what I'm studying right now 🤩
@rndmstff51611 ай бұрын
Every hole's a goal
@felicote11 ай бұрын
Can't wait for the homology one
@nimrodgutfreund473411 ай бұрын
Amazing video as usual!
@strangeWaters11 ай бұрын
if you use groupoids, your loops can have MULTIPLE basepoints :)
@whizeezihw11 ай бұрын
Thanks for this!
@yonatanharris153911 ай бұрын
New alpeh 0 vid. the sun is shining the birds are singing
@kaidenschmidt15711 ай бұрын
Upon rewatching, I realize I have a question: no matter how small you shrink a loop it will always be missing its interior. I seem to understand how a contracting loop will become caught on a hole of finite size, but from the plane minus the origin, perhaps P\O I might say, how might it get caught on that hole? If I idealize my loop to a disk centered on the origin and shrink it down, it will always be a disk, so how could it know if I only delete a single point?
@kaidenschmidt15711 ай бұрын
Thank you, this is an excellent reply and I appreciate your thoughtfulness. I admit that I'm still a little puzzled--for the function on this interval, if the interval is [a, b] is f(a) required to be f(b), such that the function intuitively forms a closed loop in the space? Secondly, how could this function detect if there's a deleted point on the interior of the loop if it doesn't need to get "caught" on it? My questions make not make any sense, but if you can attempt to see what I'm getting caught up on, it would be appreciated. Also, the comment on algebra becoming like geometry is interesting! @LoveFalastin4034
@angelmendez-rivera35110 ай бұрын
@@kaidenschmidt157 Indeed, a loop is a _continuous_ function f from [a, b] to the space X in question, with f(a) = f(b). Alternatively, you can define a loop as a continuous function from S^1 to X, where S^1 is the unit circle in R^2 centered at the origin. The loop itself tells you nothing about holes. What you need is to talk about a homotopy H between two loops f and g.
@Sciophile11 ай бұрын
I've come to think it is homology, not homotopy, that correctly captures the notion of a hole, and homotopy groups carry more (e.g. fibrational) data than this. Hence why higher homotopy groups of spheres are so complicated.
@justforfunforever101011 ай бұрын
Good video!
@jjjj-wk9gt11 ай бұрын
A goal.
@DEVSCBA10 ай бұрын
Fire in the hole.
@themelk0r2111 ай бұрын
Really awesome video, I’m definitely going to check out some of those resources you listed!
@Words-.11 ай бұрын
Thanks!
@harlanweid772310 ай бұрын
2:30 Aren't green and red loops homotopic? If you fix upper point of a green loop and stretch the bottom part to the left, you can move green loop next to the red ones.
@adriansison150311 ай бұрын
this is absolutely fascinating, im still in Apostol's analysis and baby rudin. About to study topology and abstract algebra nxt year and i cant wait to study algebraic topology.
@beautyofmath682111 ай бұрын
Really nice video, I learned a lot, thanks for sharing
@orisphera11 ай бұрын
What about the following (equivalent) definition? A space has a hole if there's a loop that can't be filled. By filling, I mean continuously mapping the disk in a way that its boundary is mapped in the given way
@ethanbottomley-mason844711 ай бұрын
A disk is just a cylinder but you have contracted one of the ends to a point (A disk is homeomorphic to a cone). So what you said is the same as the definition in the video because the fact that one of the ends is a point forces the loop to contract to a point.
@orisphera11 ай бұрын
@@ethanbottomley-mason8447 [removed - I probably misunderstood]. Also, I put the fifth word in the comment there before you made the reply
@gigantopithecus825411 ай бұрын
it is so intresting how so mant things are groups
@SydiusVideo6 ай бұрын
Thank you!
@Kualinar10 ай бұрын
When you realize that something that look trivially obvious is NOT trivial at all.
@AvanaVana11 ай бұрын
1:25 “a loop in your space x” I heard “a Hyperloop in your SpaceX”
@o0QuAdSh0t0o11 ай бұрын
Taurus
@NonExistentAlex11 ай бұрын
Can anyone explain how for SO(3) travelling around the non-constant loop twice yields the constant loop? Struggling to visualise this!
@cubing727611 ай бұрын
look up dirac's belt trick
@NonExistentAlex11 ай бұрын
@@cubing7276 thanks for this!
@nicolasberube11 ай бұрын
His illustration of the plate trick is not well done in the video. What should have been done is holding a plate in your hand, and imagine that there is food on the plate and that you don't want to spill it. Now try to perform a 360 degrees rotation of the plate (around an imaginary vertical rotation axis, without spilling). You can do it but your own arm is twisted. However, if you continue another rotation in the same direction, your arm untwists. One of the rotation is done with the plate above your arm, the second one with the plate below your arm. It's complex to explain through text.
@hotrod68910 ай бұрын
This helped better with the visualization - kzbin.info/www/bejne/qHSTm3R_eMuBrcUsi=1Ct7Pn4rC7y9bb1L
@lachlan098211 ай бұрын
a goal
@GregoryMcCarthy12310 ай бұрын
A bridge is a hole, and a hole is a bridge
@BMK529811 ай бұрын
Well ... math at andrews university (which is a youtube channel ) team are posting videos conserning algebraic topology course
@authenticallysuperficial987411 ай бұрын
Bro that 720 degree turn must hurt your arm
@nabbet12311 ай бұрын
Great stuff!
@idontwantahandlethough10 ай бұрын
your mom. (but in all seriousness, great video man!)
@marcuscarana924011 ай бұрын
As long as there's a goal.
@christressler385711 ай бұрын
I don't see a link to Pierre Albin's (sp?) videos...?
@DavidPumpernickel11 ай бұрын
Poincare died in the early 20th century. 1885?
@duckymomo793511 ай бұрын
omg you mentione Pierra-Albin videos
@ignacioponsostuni683610 ай бұрын
Isn't the fourth characteristic of groups missing? The one about the groups being closed (mixing elements within that group with one onother cannot result in new elements)
@angelmendez-rivera35110 ай бұрын
This isn't a characteristic of a group. It's implied by the very definition of what an operation is.
@habukichandayo11 ай бұрын
"A hole on M is when a k-form is closed but not exact on M."
@habukichandayo11 ай бұрын
@hybmnzz2658 Yeah, thats because ker(d_i) = im(d_(i+1)) is implied by ker/im trivial and thus no. of close k forms = no. of closed exact forms
@habukichandayo11 ай бұрын
@hybmnzz2658 So essentially the same thing
@habukichandayo11 ай бұрын
@hybmnzz2658 Oh lol
@TalsBadKidney11 ай бұрын
You missed a couple key examples but it's alright your mom has a couple invaluable demos and accompanying lectures
@vencedor177410 ай бұрын
A chance for glory babyeee
@jaysn16836 ай бұрын
If I take R^2\{0}, can’t I also contract any loop into the origin or is this excluded by definition?
@peeper207010 ай бұрын
She said I’m in the wrong hole I said I’m lost uh uh
@jwash430210 ай бұрын
She said im going too fast im exhausted
@ciekawska56311 ай бұрын
Nice example with an arm
10 ай бұрын
2:30 how is the green loop different from the red loop? we can just slide it ower..or maybe im looking at it wrong
@purplenanite11 ай бұрын
if pi_1 of the plane minus a point is Z, what is is minus two points? you can loop around one or the other in complicated knots?
@gchtrivs789711 ай бұрын
Free group on two elements
@ethanbottomley-mason844711 ай бұрын
Essentially. You have two important loops, call them a and b, where a goes around your first point counterclockwise and b goes around your second point counterclockwise. We also have a^-1 and b^-1 which are the same as a and b but go around clockwise. Now any loop in the plane minus two points will be homotopic to a string of a's, b's, a^-1's, and b^-1's. The way you actually figure this out is using deformation retractions. This simplifies the problem of finding the fundamental group of the plane minus two points to finding the fundamental group of two circles stuck together at a single point.
@prakashraj451911 ай бұрын
Hole is where you put the pole
@orisphera11 ай бұрын
I'm pretty sure you've misrepresented the definition of a fundamental group. With the definition in the video, there are cases where the sum belongs to different classes depending on how exactly you compute it. I have two cases of this Let's consider a space formed by excluding three shapes from a shape in the Euclidean space. We can consider a loop around one of the excluded shapes. We can consider a loop around all three of them. It's easy to multiply them in two ways. However, I don't see how the results are homotopic For another example, consider a shape with two excluded shapes. Let's consider the path around both. It's easy to add to itself. But let's say it goes between the excluded shapes. In doing so, it goes through the same point in both ways. (Maybe it would be easier to explain if it goes in a ∞ shape. Both versions work.) Now, there are two ways to add it to itself I cut the space in a way that any continuous deformation of a loop, in the terms of going through the cuts, consists of appearance and disappearance of consecutive pairs of going through the same cut in different directions. One can think of the result as a pseudograph. The nodes are the parts, and the edges are the cuts. In the first case, there are 4 nodes. However, it's symmetrical by swapping any two nodes and the other two nodes. In the second case, there's one node. So, I can think of the fundamental group as the free product of groups for each cut. In the first case, the components are 3 copies of the 2-group. It's abacbc vs acbcab. In the second case, the components are copies of the group of the integers. It's aabb vs abab Wikipedia gives what the video gives in the abstract. However, in the “Intuition” section, it gives a non-flawed intuitive definition. The difference is that in the correct version, the loops are thought of as going through a certain point
@appa60910 ай бұрын
I don't see why a² = 1. Spinning around twice seems different than staying still.
@gchtrivs789711 ай бұрын
1. "If a space has a hole, there are loops that cannot be contracted" This is false. Take a 3-ball with a hole inside. 2. You defined a loop as a continuous map from a circle to a given space. You didn't single out an orientation nor a basepoint of the circle, making your "definition" of multiplication nonsensical. Now suppose you use the usual definition of a loop and the usual definition of multiplication of loops. Then the multiplication of loops is neither associative, nor has an identity element (which you haven't explained what it is, just said it's "a constant"), nor has inverses. It only becomes a group once you pass to homotopy classes of loops. You mention that later, but still don't make it any clearer why these packets of loops have the properties of a group, or why multiplications is even well defined. 3. You haven't explained why the 360 loop in SO3 is not contractable. You haven't explained why rotating it again makes it contractable. You haven't explained why there aren't any more packets of loops except those two. 4. The titular question "What is a hole" wasn't even attempted to be answered the video. 5. You claim to want to make the intuition of a space having a hole precise, yet almost nothing in your video was precise. Do better
@anywallsocket10 ай бұрын
How do you distinguish twisting your arm once more from untwisting it? Ie, from a double loop to unlooping the first loop? So if a*a = 1, what is a/a ?
@angelmendez-rivera35110 ай бұрын
a/a = aa = 1. What you are ignoring is that a^(-1) = a.
@anywallsocket10 ай бұрын
@@angelmendez-rivera351 that would imply you could not distinguish the two states completely unraveling the analogy - hence why I asked.
@prdoyle11 ай бұрын
Nope, I don't get the plate trick.
@LiamHaleMcCarty11 ай бұрын
0:17 1895 not 1985 :)
@taygrew8910 ай бұрын
I missed you:(
@abdulrhmanaun10 ай бұрын
And thank you for your work 😊
@jackknopf597411 ай бұрын
Correction: 1885 paper, not 1985.
@xoudrion277510 ай бұрын
A hole is a goal, simple as that - A simple man 2023
@Almondz_11 ай бұрын
Omg Aleph null!
@sarahhtonin11 ай бұрын
multiply two loops? bro what?? you can do that?
@CosmicHase10 ай бұрын
Where you shall travel hard.
@jaborl11 ай бұрын
Nice Video!
@RM-xq7gf11 ай бұрын
You didn't have time to watch it when you commented...
@jaborl11 ай бұрын
@@RM-xq7gf I have now
@xyzct11 ай бұрын
An algebraic topologist is someone who can tell his a$$ from _two_ holes in the ground.
@rg341211 ай бұрын
1885 paper
@ahappyimago11 ай бұрын
Wittgenstein has entered the chat
@ProfJigsaw11 ай бұрын
Nice video. A small correction. Poincaré died in 1912. He couldn't have published his "Analysis Situs" in 1985. I think you mean't 1895.
@Aleph011 ай бұрын
Yup, thanks for the correction! I’ve added this correction to the description.
@dillonsharpton595210 ай бұрын
Holes don't exist in the physical world! The ibky way the coul is if there are holes in space time. Holes the absence of a surface. People get upset with me when I tell them this after they ask me how many holes does a straw have.
@angelmendez-rivera35110 ай бұрын
*Holes the absence of a surface.* Ergo, holes do exist lol.