This is the most clear and concise intro to mods I have found on YT. I will definitely be sharing this with my students. Keep up the great instructional content!
@WrathofMath3 жыл бұрын
So glad you found it clear, thanks a lot! Looking forward to making more lessons on the topic!
@maxien1019 ай бұрын
I wish i found this before my exams! Absolutely golden explanation
@shambo9807 Жыл бұрын
Thanks for this clear explanation of how it works for negative numbers. I finally understand it now.
@nancynguyen22442 ай бұрын
Thank you!! The example right in the beginning helped a lot.
@daisyg5092 жыл бұрын
Thank you SO much
@rajendranchockalingam10792 жыл бұрын
Good morning sir Excellent explanation I am from Tamil Nadu Thank you sir
@luisdfernandez26013 жыл бұрын
I have to laugh. I kept asking myself "how did he get 4 as a remainder??" And then, I remembered we're dealing with whole numbers and that 6 can't go into 4 therefore it is 0 and the remainder is the actual 4. It had me scratching my temple for a minute or two LOL
@madihachaklader2378 Жыл бұрын
I thought it’s only me… as for a moment I thought it’s 0.6 then I realised it’s 0 multiplied with 6 hahah
@srinidhinagendran75234 жыл бұрын
Thanks for clean explanation
@luisdfernandez26013 жыл бұрын
On 3:50 do you mean a = 14 and b = 8? Because on the previous example you used the same numbers as an example but got a positive 2 as a remainder and here you get a -2 as remainder.
@yousufh50535 жыл бұрын
thank you, very useful and it helps alot . .
@WrathofMath5 жыл бұрын
Thank you for watching, I am glad it helped! Let me know if you ever have any lesson requests!
@janabaijadhav74903 жыл бұрын
Best explaination, Thank you sir
@WrathofMath3 жыл бұрын
Thank you!
@RonUS20094 жыл бұрын
Good job.
@WrathofMath4 жыл бұрын
Thank you, Ron!
@rochellealonzo85193 жыл бұрын
Thank you so much sir. Very helpful😇
@WrathofMath3 жыл бұрын
Glad to hear it! Thanks for watching, Rochelle!
@saritha96234 жыл бұрын
Good explanation. Thank u sir.
@WrathofMath4 жыл бұрын
Glad it helped! You're welcome and thanks a lot for watching!
@jairoselin51193 жыл бұрын
Helpful ❤️
@WrathofMath3 жыл бұрын
Glad to hear it, thanks for watching!
@johnw13683 жыл бұрын
Thank you! Could you please do a video on solving congruence equation? Ex , ax= b (mod") etc etc. But could you please break it down very easily?
@mm-wm6uh9 ай бұрын
1:40 how you get 0 on 4=0.6+4
@universalponcho3 жыл бұрын
Very useful
@WrathofMath3 жыл бұрын
Glad to hear it, thanks for watching!
@oshawastaken4 жыл бұрын
bless got my final in 2 weeks
@WrathofMath4 жыл бұрын
Good luck! Thanks for watching and let me know if you have any questions!
@AbuBakar-f4n6d3 ай бұрын
how to get 2 remainder after dividing 2 by 4
@srinidhinagendran75234 жыл бұрын
I want to know about thereom on this topic
@WrathofMath4 жыл бұрын
Thanks for watching, Murali! Is there a particular theorem you have in mind you'd like to see?
@user-is8fw2je1y4 жыл бұрын
Hi, I have doubt. There are 2 ways of solving modulo systems I guess. So my professor gave an example: 14 congruent 2 (mod 12). We solved it like: 14-2=12, and 12 would be an integral multiple of m. But when I tried the same problem with your method, I am getting different remainders for both. Why is that?
@mandy72123 жыл бұрын
14 = 1(12) + 2 2 = 0(12) + 2 I read this mentally as: "14 is 1 multiple of 12 plus 2", and "2 is 0 multiples of 12 plus 2". In both cases, the remainder is 2. Thus, 14 ≡ 2 (mod 12). Note it is the case that 12 | (14-2) or 12 | (2-14)
@julventuba15155 жыл бұрын
Can you give example of this theorem? if ca and cb is congruent mod n, then a and b congruent modulo n/d where d= gcd (c,n)
@WrathofMath5 жыл бұрын
Thanks for watching! Sure, let c = 12, a = 3, and b = 7. Then ca = 36 and cb = 84. Then we have a few options for n if we want congruence mod n. Let's pick n = 8. Notice 36 is congruent to 84 mod 8. Then, d = gcd(12, 8) = 4. Thus, the theorem tells us 3 is congruent to 7 mod 8/4. Simplifying we have 3 is congruent to 7 mod 2. Indeed this is true, as 7 - 3 is divisible by 2, or equivalently, they both have remainder 1 when divided by 2.
@julventuba15155 жыл бұрын
Thank you so much! Big help
@ahmedmghabat79824 жыл бұрын
3/n(n^2 -1) ? For every n natural Actually i had it in my previous exam to answer if its true or false . Please can you solve it?
@exercisefitnesshealth89654 жыл бұрын
thank you for the video, sir. how about this? Find x: 1. 8 = x (mod 3) 2. x = 38 (mod 4)
@OMPRAKASHVerma-dh6ve4 жыл бұрын
I think x might be equal to 38
@fergusjohnson37884 жыл бұрын
@@OMPRAKASHVerma-dh6ve when we divide 8 by modulus 3 (8:3), then we obviously get the result with a remainder 2. So, to get 8 back, we have to multiply 2 by 3 and finally add 2 (8=2*3+2). To get X, we use the same division strategy when it comes to dividing x by 3 (x:3). As b=x, a=8, and c=3, we have to find the number as when it is divided by 3 the remainder should exactly be 2. So, it is 38. PROOF: 38=12*3+2.
@OMPRAKASHVerma-dh6ve4 жыл бұрын
@@fergusjohnson3788 ooo yes
@jamaicarabino78974 жыл бұрын
Nice
@WrathofMath4 жыл бұрын
Thanks for watching!
@d12kiem74 жыл бұрын
wiping my tears....still trying to get it
@WrathofMath4 жыл бұрын
Do you have any questions I can help clear up?
@koshka022 жыл бұрын
My prof is so garbage compared to these videos My prof doesn't explain anything, and I'm genuinely trying my hardest to learn then I go here and you explain it so simply My tuition should be going here, not my prof
@WrathofMath2 жыл бұрын
I'm glad to help! Thanks for watching and let me know if you have any questions!