WHAT IS THE LOCATION OF ICR JUST AFTER STRING IS CUT ? | JEE ADVANCED | QUICKIES

[@AdityaGupta-xq8ud]

yes it came in fiitjee aits part test 1 mains similiar type of question thankyou

[@johncena-fy3mo]

I have done my part by liking videos with my 13 accounts now I hope others will do their job as well and not become lazy

[@mayankd8362]

8.13 1) A. As if string was not there and same velocity of rod particles would be there so it is space point 2) 0

[@sohansingh2022]

Also came in fiitjee aits. Thx for making it 600 likes 😭.

[@sohansingh2022]

Aaaj kal aapka videos itne kam aate hai. Notification aate hi maja aa jata hai ki aaj kuch naya sikhne ko milega. Thank you 🧡

[@uttambose2723]

Sir thanks for bring back such delicious concepts 😋....

[@suyogbewle5636]

1) B. 2) 0

[@debu6157]

7:08, A and g(b/a)

[@rajeevkumarsam5499]

Very nice lecture.kindly upload more lecture

[@Dead-ot4pd]

8:13 1:(a) 2:0

[@arnavborse5944]

Thankyou sir

[@Fighter_Believer_Achiever]

Thank you very much sir 😇😇😇😇

[@elonrusk3292]

4:55 I have two doubts 1)Does the rod gain angular acceleration alpha at this instant immediately after cutting of the string? if yes then wouldn't it give the rod cm an acceleration in the horizontal component too? 2) how exactly does the point A get acceleration? I'm unable to figure out the forces which are causing its acceleration

[@PHYSICSSIRJEE]

1) alpha is generated immediately due to torque. a cm is vertical only as net external force is the only thing responsible for cm acc. INTERNAL forces don't matter 2) The neighbourhood of part of point A of the rod pushes and also applies twist forces to generate acceleration for any point like A. The acceleration of A and value of alpha in turn should ensure that a cm is not horizontal

[@JEEAspirant-ub3id]

Amazing sir thank you

[@Viveksingh_18]

You are also here I see you at vinay uppal sir channel last video

[@AnjuSingh-ks5hc]

For q1.. I think the icr point is material point as we have used string constraints..

[@sachinbeniwal8481]

👍👍👍👍👍👍👍👍👍

[@arpitbansal4911]

Majjo he aa gya bhau

[@nishkarsh5487]

Hello sir, Sir how a has accn if there is no force in x direction?

[@PHYSICSSIRJEE]

External force decides direction of acceleration of CM only and not of other points

[@nishkarsh5487]

Ok sir. Thank you very much.

[@dimondais2034]

1 a 2.0

[@PHYSICSSIRJEE]

Check the next video, solution is made

[@JEE-zm3sh]

4:36 Sir why can't acceleration have an upward component? I have seen the same question in books but no explaination give...pls clarify sir🙏

[@PHYSICSSIRJEE]

The end point of the thread can have acceleration along the thread while rotating, the value is centripetal= Lw^2 ... When omega =0 , in spl case like here at 4:36 , that acceleration of end = 0 in upward direction

[@JEE-zm3sh]

@@PHYSICSSIRJEE thanks for responding to our doubts even years after the video sir☺

[@JEE-zm3sh]

​@@PHYSICSSIRJEE Sir but lw^2 is upward acceleration only if point A moves in a circular path right...how is this established?? Like i dont understand why the string cant become slack

[@pankajdeeps]

Space point

[@satwik1268]

Love these videos! 7:08 I think the answer of 1st is b) but still I'm confused as to why can't we say that the body rotate about the space point just below the ICR(as both Vel of ICR and the space point = 0 so at that instant the velocity of all points of body about space point will be as same as about ICR and if the body rotates about ICR then it should rotate about space point too at that instant!) Maybe b) is wrong to begin with.

[@debu6157]

The origin is also moving bro

[@sunitagoel888]

Where does the horizontal velocity come from

[@PHYSICSSIRJEE]

For the left end ? From material contact of this dm element with rest of the rod

[@sunitagoel888]

I understood may be it's due to the angular acceleration I was not able to figure it out that time

[@puspalpaul185]

Sir is this video just made.....coz i did not find it in uploads

[@PratyushKumar-d9f]

Sir is it not possible at that the point A remains at rest?

[@PHYSICSSIRJEE]

Since point (0,0) has acceleration (as decided by writing equations of force and torque), it is concluded that it moves towards left in the next period

[@PratyushKumar-d9f]

@@PHYSICSSIRJEE yes sir understood

[@amittiwari7405]

sir 8 31 ans is option b

[@aryansaxena8081]

sir could you pls suggest me an article or a paper or a book for electron and photon gas actually i liked your photon gas "Original problem" the one you prepared for fizika very much but sir i dont know much about photon gas and electron gas so pls could you provide me a link to a page or any recommended book where i can find these topics to understand them some little more { like you asked for efficiency of photon gas cycle if it behaves like carnot in that video } Also sir i know its time for jee advance related questions more but sir can you pls make a video on that efficiency part of photon gas cycle to help us understand more about that topic

[@PHYSICSSIRJEE]

www.cpp.edu/~hsleff/PhotonGasAJP.pdf

[@PHYSICSSIRJEE]

You can find more resources if you need , from the end of the paper. But , whatever was needed for JEE advanced was already covered by me in that fizika video

[@aryansaxena8081]

@@PHYSICSSIRJEE thank you so much sir pls also make that efficiency part video if you get free time sir just 1 video only for that efficiency of cycle part rest all is perfect sir. Thanks sir for all the help of 250 videos you made till now

[@aryansaxena8081]

@@PHYSICSSIRJEE sir now no need for efficiency video actually i found that part in your given paper

[@DeepakSingh-or3cl]

sir at timestamp 4:26 the point A wont have the the centripetal acceleration??

[@PHYSICSSIRJEE]

Omega is zero at this instant

[@fighter6492]

😎😍🙏

[@Sonu-hv4ef]

Hi sir. As a Physics lover I am a big fan of this channel 🙂. Can you please provide a seperate video explaining the energy changes in questions of angular momentum conservation. How energy changes while folding arms or while someone walking on a rotating disc. Where is the energy going or coming from. I tried finding this on "Physics stack exchange" but couldn't find a proper explaination. If possible please help.

[@PHYSICSSIRJEE]

It's explained in short in one of the examples at the end of my old video on Lectures channel here 👇 kzbin.info/www/bejne/hamuhXptlM-ipKM It's a useful lecture that was uploaded by management in that channel. Go to the end

[@PHYSICSSIRJEE]

At approximately 1 hr 46 min on the video

[@AryanYadav-rh8iy]

@@PHYSICSSIRJEE Sir may you respond to my query too ???

[@PHYSICSSIRJEE]

@@AryanYadav-rh8iy I didn't find any query of yours. It's also better if you can post below the video itself or in telegram or in discord server

[@PHYSICSSIRJEE]

@@AryanYadav-rh8iy whenever I am free or get an alert , I will respond to relevant queries

[@tanayagrawal1695]

👍

[@bhagwatnawale293]

Why we can't take centre of mass as a icor??

[@ayonnsoum4753]

7:38 C 8:06 (0) Are they correct sir??

[@nishchalsrivastava6944]

👍💯

[@navhis]

Sir, hungry plz bring food nither died of starving

[@aryankatiyar3940]

750

[@mohitverma6291]

great video sir :)

[@yashwantrao5905]

Sir please videos ki frequency badha dijiye

[@PHYSICSSIRJEE]

It's increased today to 6 days as target likes are reached 👍🏼

[@AryanYadav-rh8iy]

@@PHYSICSSIRJEE Sir pls respond to my query :(

[@yashagrawal8592]

1-(a) , 2 - 0 ? As initial angular velocity is zero So if ICR would have an acceleration in any one particular direction then both origin and com can't have there acceleration in horizontal and vertical direction respectively , while I guess string point on (0,b/2) have a acceleration proving that it's not a material point

[@AryanYadav-rh8iy]

Its most likely material point of rod coinciding on string, here just the case is that the acc of IOR coming zero makes us believe its space point , but its not bc at a later moment IOR will get acc while space point all points have zero acc .

[@debu6157]

@@AryanYadav-rh8iy bhai origin also moving

[@AryanYadav-rh8iy]

@@debu6157 so what? Space points are all rest points (no acc no velocity)

[@AryanYadav-rh8iy]

Origin is material point

[@yashagrawal8592]

@@AryanYadav-rh8iy space points are theoretical points which we could assign any velocity or acceleration

[@shrawon3605]

1) c both 2) ag/b I'm not sure if they are correct. I just tried them. Probably both are wrong. Please tell, sir

[@nikhilkumar-ps4wg]

Sir please upload your problems sets on website asap ☺️🙏📖.I do not have any coaching material 📓✒️

[@WORLD-rm2tm]

Sir one suggestion if you want more number of views or subscribers then u can join unacademy u will develop huge fan following like nitin sir

[@PHYSICSSIRJEE]

Offline job , like online job , has it's own advantages . Let's see , where life takes us. Let's try to find ways to contribute to KZbin with my way of "physics" videos and see how much more time I can run this channel. But , one thing is for sure , as long as videos are uploaded on this channel , I will try my best to teach something new in every video 🙂. ps : I will benefit if students keep liking and sharing good Physics videos of mine

[@AryanYadav-rh8iy]

@@PHYSICSSIRJEE sir ofc we will share :) , pls reply to my doubt too :)

[@vaibhavpandeynitr1391]

Falling in love with these problems ❤️

[@beluga8956]

obsession with these videos making my brain obese

[@anushkrajbordia1873]

Good Wordplay 😂

[@beluga8956]

@@anushkrajbordia1873 i should have used quickies instead of videos it would have been more cool

[@anushkrajbordia1873]

@@beluga8956 😂😂

[@WORLD-rm2tm]

🤣

[@aubade8093]

Third comment

[@krish7245]

Everyone likes fast food

[@drsonaligupta75]

1) b Material Point on string at (0,b/2) as we have the to take Acceleration in Psedo torque according to that. Sir I have another question as to what if the string is tilted, i tried myself but I couldnt find a definate point other than the it will be along the Line of string below the rod.

[@princekumar8285]

Practice problem one:) correct answer is option "A" Because accleration of any point on string at this instant is perpendicular to the string , but icr has different direction of accleration

[@godisgood2482]

Thought this video would be in hindi😊

[@siddharth9668]

Sir can you please give solution to this JEE Mains 2011 question : "The specific heat capacity of a metal at low temperature (T) is given as Cp (kJ K-1kg-1) = 32(T/400)^3. A 100 g vessel of this metal is to be cooled from 20 K to 4 K by a special refrigerator operating at room temperature (27°C). The amount of work required to cool the vessel is (a) equal to 0.002 kJ (b) greater than 0.148 kJ (c) between 0.148 kJ and 0.028 kJ (d) less than 0.028 kJ" I'm really confused with this question. I've found different solutions to this questions from different teachers. So can you please take this questions in one of the upcoming videos 🙏🙏

[@PHYSICSSIRJEE]

Already covered in JEE Mains revision series video on calorimetry 👇. It's at 52nd minute. kzbin.info/www/bejne/e37PdYd9ZcqraJI Please cover all the previous videos , it would be difficult to answer solutions in comments section. Also , you may post your doubts in telegram group or discord server . Other students will answer your doubts when I am busy

[@siddharth9668]

@@PHYSICSSIRJEE Thank you very much sir

[@AryanYadav-rh8iy]

@@PHYSICSSIRJEE Should i send here the query itself Sir of that video of yours?

[@devarora8948]

thank you sir