Where to put the third charge so the net force is zero

[@NaseemAkhtar-q5p]

Sir plz keep continue making this type of series for every topic.. you never know how much you are helping us out more than our professors!!!🥺

[@c1o_87]

Excellent Explanation ❤

[@danthetutor2624]

Concise comment 👍

[@kimsordyl]

I am surprised this vid doesn't have more thumbs up. So helpful and prefect for MCAT review as well. Thanks!

[@danthetutor2624]

Glad you liked it! Tell your friends!

[@Olena-g7o]

Super ! Very good explanation!…The best among many!…Thanks!

[@danthetutor2624]

Thank you!

[@akash_3307]

Can't we bring (4+x)²/x² to one side and 8/5 to the other side and then apply roots on both the sides so we get... (4+x)/x=√1.6 and on solving x we get the same value ... Its quite fast to solve like this I feel. Thanks a lot for the examples...it was a good revision 👍

[@danthetutor2624]

Oh yeah, that does work. Wow, very clever!

[@Hala-ep1ti8gg4z]

Very, very helpful. Thank you!

[@danthetutor2624]

You're very very welcome!

[@mariamziad9379]

This was very helpful, thank you!

[@ahmarscott1706]

This has helped me!! Thank You God Bless!

[@danthetutor2624]

That’s what I’m here for

[@KipomaiKama]

You are the best ..so helpful 🙏 Thank you very much.

[@danthetutor2624]

Always happy to help!

[@SbongakonkeZondi-f5q]

thank you so much , i have been so confused but you just made everything clear to me

[@danthetutor2624]

That’s what I’m here for!

[@ItsSkyler007]

Thank you! I was so confused on this topic but now it makes sense. 😁

[@danthetutor2624]

Glad to hear it!

[@jadonw192]

Hey dan, thanks for this. Why can we assume it is a positive charge for the second question. If it was a negative charge would its position be the same or on the other side.

[@danthetutor2624]

Hey, that's a good question, I didn't explain that very well. When they don't tell you what the charge is (positive or negative), there's a good chance that the charge cancels out later in the problem. For that reason, you can choose the third charge to be whatever you want (positive or negative). And it doesn't matter because it cancels out later in the problem.

[@jadonw192]

@@danthetutor2624 Ah I see, thanks a lot for the help

[@Adeline-l1b]

Thanks a lot for this video!!! It helps me a lot and it is much clearer !!! I understand that it works for the Electric field, does it also work for Electric Potential?

[@danthetutor2624]

Happy to help! For electric potential, it’s similar but different. Watch another video for that topic.

[@Adeline-l1b]

Thanks for your reply 🙂! Is it this topic - Electric Potential (Voltage) in Physics that I can find the solution?

[@danthetutor2624]

Yep!

[@Adeline-l1b]

👍I am going to watch this video, thanks a lot for your help!!!!

[@ii_1pr054]

Why you took -x² while trying to make it equal to zero

[@geoffphillips8183]

Brill vid !! Thnx . How would we calculate the magnitude of charge we add to make net force zero? I found this in a question & couldn't do it coz the new q kept cancelling out

[@danthetutor2624]

Thanks! So with your question, it’s the same equation (Coulomb’s Law), but now you’re solving for q. Remember that force is a vector, which simply means it has direction (positive or negative). And you need those vectors to cancel out to zero.

[@geoffphillips8183]

@@danthetutor2624 ok thanks Dan! Now I understand 💪💪

[@FilipinoPride21]

Why crash out the negative?

[@elbilala]

Which one is smaller 5c or -8c charge?

[@danthetutor2624]

Depends on what you mean by “smaller”. If you’re referring to charge, the answer is 5C. But if you’re saying force, then they’re equal. They are equal because we put the third charge closer to the 5C (because its charge is smaller), thus increasing the force by the 5C to make it equal to the 8C.

[@elbilala]

Thank you so much for replying also for your great explanation it was awesome.

[@danthetutor2624]

No prob! Just don’t forget who’s the best tutor.

[@elbilala]

I think I thought so😊

[@m.m.m.m.m.m.m.m.m.m.m.m121]

Why do you use the quadratic formula while you’re able to factor it normally?

[@danthetutor2624]

I don't think you can factor it normally. Do you think it's (x-12)(x-12)?

[@m.m.m.m.m.m.m.m.m.m.m.m121]

@@danthetutor2624 yes

[@danthetutor2624]

That won't work because after you factor out the negative, you have x^2 + 24x - 144, and (x-12)(x-12) gives you +144 instead of -144

[@ishaannaik2374]

Dan I would suggest you to teach topics from an exam called IIT-JEE. Here in India it is undoubtedly the most competitive PHYSICS+MATH+CHEMISTRY examination. I hope you'll research and bring some next level content :)

[@gynemedee]

That is what I want to say

[@modbusd119]

You saved my life

[@orangeinfotainment620]

thank you!

[@padakutamatar7077]

this is very helpful! thank you

[@danthetutor2624]

Happy to help!

[@ishaannaik2374]

Thanks Dan!

[@aniesha5818]

Thank you...

[@aboeckmann]

very helpful, thank you

[@shalomGebremichael]

Thank you so much!

[@danthetutor2624]

Don’t mention it!

[@letsparty6496]

sir where would be the net charge if the both charges were negative

[@danthetutor2624]

Don’t I cover that in the first example? I think I’m missing something.

[@Sarah-de1nm]

What if the two charges are -7 and 7 ?

[@danthetutor2624]

That’s interesting. I think the answer would be undefined.

[@ghaida76]

cool! keep it up

[@overtongondwe6442]

Kudos

[@usamashehab8138]

Can u become my college professor pls

[@danthetutor2624]

Sure! What college?

[@basil177]

I ly