Submit your math problems to me at mathoutloud40@gmail.com and I'll attempt a solution as I see it for the first time. Follow me on Twitter: / mathoutloud40 Follow me on Mastodon: mathstodon.xyz... #math #maths #mathematics
Пікірлер: 9
@RobertssUАй бұрын
yea in the one which has square root of 10!, you forgot to write the squared, which was already given in the denominator, so squaring it again would make it ^4
@SadBoys.1996Ай бұрын
bro i dont even know what im looking at. this could be sanscript for all i know
@mathoutloudАй бұрын
We all start learning from the same level! I definitely didn’t wake up one day understanding this “language” out of nowhere ;)
@claireloubАй бұрын
For (D) can we not just say 2^5 = 32 so log2 (30) < 5 and 3^4 = 81 so log3(85) > 4 so smaller/bigger means overall it's definitely less than 5/4. For (C) you forgot the squared on the 6!, but with all the cancelling what you get is comparing 7/4 to 7/(very big)
@mathoutloudАй бұрын
This is what I eventually did, I just didn’t see that earlier in the work. I’m happy my mistake with the 6! didn’t throw off the correct answer.
@slytherinbrianАй бұрын
I always have a lot of fun with problems like this. Here was my approach: I started by comparing the first two (since 5/4 is nice and easy)... sqrt(7)/2 is sqrt(28)/4. sqrt(28) is a little bit more than 5, so (A) must be more than (B). Looking at (C), I canceled a bunch of terms and got sqrt(7)/2160, which is a VERY small number, so obviously that's not it. For (D), I observed that log2(30) is slightly less than 5, and log3(85) is slightly more than 4, which means it is less than 5/4. (E) was the trickiest, but I wanted to compare it to (A)... so I set up the question sqrt(7)/2 (1 + sqrt(6))/3. I cross multiplied to get 3 sqrt(7) 2 + 2 sqrt(6). Then I moved the coefficients inside the square roots to get sqrt(63) 2 + sqrt(24). The left side is slightly less than 8 (but greater than 7), the right side is 2 + slightly less than 5. So that means the left side is greater. So the answer is (A).
@humanbean4014Ай бұрын
you missed that the 6! was squared in option C, although it didn't matter because squaring it would make the number 6! times smaller