GMAT Data Sufficiency | GMAT Number Properties Sample Questions | 2 GMAT Hard Math Questions

[@DubCmusicTV]

Really liked the p^2-1 , a multiple of 12 question

[@Wizako]

Hi, Many thanks for your feedback! Glad you liked it! 🙌 Best wishes for your GMAT preparation!

[@venkateshsrinivasan6642]

Thank you Bhaskar for your valuable videos. It's really helping me prepare better

[@Wizako]

Venkatesh, thanks for your feedback. You could also try the free topic, statistics and averages, on our online learning platform. You can sign up as a trial user at wzko.in/core.

[@TheDHemant]

Clap clap clap. .. Sir, you are Super Sooper Dooper

[@snowflake_VEVO]

Prof could u confirm if this is true . For instance In question 1 the easiest way to solve a No/Yes question is by Molinsky Theory: It says try to find a concrete example from the statement which answers No to the question .If such answer is available then the statement is Not sufficient. Only Applicable on non Always Yes/Always No quest

[@Wizako]

Hi, Yes you can very well use that idea as well to solve these type of questions. Cheers & best wishes.

[@kalyanbiswal7771]

I thought i got both of them correct, but i failed again. I am loving these DS questions thanks

[@Wizako]

Hello Kalyan In response to your earlier comment, zero is undoubtedly an even number. Zero is neither positive nor negative. Can you please tell me in which video had I made the mistake of stating that zero is neither even nor odd. Would like to edit it so that it does not misguide others.

[@kalyanbiswal7771]

Wizako I think sir i must have mistakenly thought you mentioned 0 as neither even nor odd when you actually mentioned it is neither positive or negative. Sorry for the confusion sir.

[@Wizako]

No issues at all. Thanks for your reply.

[@bhavyamadan6177]

Hi sir, how did you get p-4, p-2, p, p+2, p+4 to be divisible by 5? In the previous qs, we used the property that if there are n consecutive integers, then one number must be divisible by n. But these are consecutive odd numbers of consecutive numbers. What is the proof?

[@Wizako]

If there are n consecutive odd integers, then one number must be divisible by 'n' is also a property that holds good for all sets of numbers. One more derived property: Because the first property holds good - i.e., if there are n consecutive integers, one of the numbers must be divisible by 'n', it will hold good for any consecutive multiple of numbers. i.e., one among n consecutive multiples of 3 will be divisible by n. You could replace 3 with any integer for that matter.

[@amitmaroo6147]

@@Wizako Sir, can "If there are n consecutive odd integers, then one number must be divisible by 'n' is also a property that holds good for all sets of numbers." be true for n = 4 ?

[@amitmaroo6147]

@@Wizako Please elaborate. TIA

[@tegvirpaintal981]

If we just use the example method and choose a number for P in (P-4), (P-2), P, (P+2), (P+4) we still don’t get a definite answer as P can be prime or not prime

[@Wizako]

Hi, Using both statements we have derived in the video (from timestamp 17:22) that P cannot be prime in any case.

[@ishitagupta7376]

i did not understand why the AP is consecutive odd integers in Q2?

[@muhammadibrahim754]

8:30

[@saurabh3206]

question 2 can be solved by if p is a decimal than also it can done

[@Wizako]

Hello Saurabh Statement 1 says P + 2 and P + 4 are prime. Prime numbers are subsets of positive integers. So, If (P + 2) and (P + 4) are positive integers, P has to be a positive integer. Same goes for statement 2. So, in question 2, P cannot be anything other than a positive integer.

[@saurabh3206]

@@Wizako question says its a positive number , question never says its a integer

[@Wizako]

Saurabh The question says it is a positive number. I am not doubting that. But when you start evaluating either of the statements, it is clear that P + 2 is prime or P - 2 is prime. There are no prime numbers that contain decimals in them. So, if P + 2 or P - 2 is an integer, P has to be an integer.

[@ishitagupta7376]

i did not understand q2