WMA11/01 Pure Mathematics P1 (IAL) Jan 2020 Q6 Straight Line Graphs

Check out the links at the end of the video to find playlists for questions on this same topic
You can find my AS and A Level material here:
drive.google.com/drive/folder...
An index of IGCSE Questions arranged by topic as well as papers can be found here:
drive.google.com/file/d/1iOMB...
If you find these videos useful and wish to help me to give more time to my channel and produce even more material going over past paper questions for IGCSE,AS and A Level Maths, you are welcome to donate here:
paypal.me/MrHassaan?locale.x=...

[@omarsameh8277]

Sir, i just wanna say, you're an absolute legend, thank you very much

[@mahmoudibrahim8734]

Thank you mr hassaan ❤

[@sophiawatt7021]

very useful, thanks!

[@saranjr4957]

16:00 is there any other way to do this question as vectors is not taught in P1

[@ahuman4294]

Too late now, but if you go at 16:00 and look at the diagram made, we can assume that because it bisects perfectly from the middle, the y c-ordinate for S will be -5 (as the y co-ordinate for Q from the origin is 5). Because now we know that the line l2 passes through R and S, we can use the equation for l2 (y = 3/4x - 6) and substitute y as -5 to solve for x

[@aHumanBeing_]

@@ahuman4294 thank you so much

[@youssefelshoukery4608]

how did u assume the position of S to be below R, why couldn't it be above the point R then it will a have a positive y coordinate instead ?

[@MrHassaansMathsChannel]

Normally a polygon is named with letters in alphabetical order. so PQRS would form the parallelogram as I drew and is also shown in the mark scheme. some students however may have drawn the parallelogram PQSR in which the S would be above R as you mentioned and although it is more fitting for the letters to be in alphabetical order, the mark scheme has allowed for that scenario as a special case in which case the coordinates of S would be (44/3, 5)

[@youssefelshoukery4608]

@@MrHassaansMathsChannel alright got it thank you so much

[@thaliaissa3009]

How dd u know ino S isnt located on the y-axis

[@MrHassaansMathsChannel]

Because the opposite sides of the parralelogram are parralel and equal in length

[@antisocialbarbie1587]

Sir how can I get you to teach me 😭

[@saadwaheed5624]

If im not wrong...u are sir hassan jamal (manarat) right?

[@MrHassaansMathsChannel]

Jamal? Nope... I'm Mr Hassaan

[@saadwaheed5624]

@@MrHassaansMathsChannel i might be wrong on the full name BUT u are a teacher in manarat right?

[@saadwaheed5624]

@@MrHassaansMathsChannel and u were the HOD of maths ...right?

[@MrHassaansMathsChannel]

@@saadwaheed5624 Which Manarat?

[@MrHassaansMathsChannel]

@@saadwaheed5624 Nope I dont like taking such positions as HOD. I prefer to just teach

[@carljohnson2194]

you got it wrong. -20/3 is not 6 times 2/3. so in the end your coordinates got wrong as well. You first wrote them correctly then changed to one 1 times 2/3

[@MrHassaansMathsChannel]

I'm afraid you maybe have misread what I wrote ... I didnt say -20/3 is -6 times 2/3.... I wrote it as a mixed number -6⅔. If you check the mark scheme you will see my answers are completely correct. drive.google.com/folderview?id=1RKTff0t_t8e8a6pNFMtwQcz0ttzXR7ig

[@carljohnson2194]

@@MrHassaansMathsChannel oh ok