Support the production of this course by joining Wrath of Math to access exclusive and early videos, original music, plus the real analysis lecture notes at the premium tier! kzbin.info/door/yEKvaxi8mt9FMc62MHcliwjoin Real Analysis course: kzbin.info/aero/PLztBpqftvzxWo4HxUYV58ENhxHV32Wxli Real Analysis exercises: kzbin.info/aero/PLztBpqftvzxXAN05Gm3iNmpz9SkVfLNqC
@thedeathofbirth0763 Жыл бұрын
This is how a person who truly understands logic, can beautifully and precisely communicate it . Thank you.
@WrathofMath Жыл бұрын
Thank you!
@punditgi3 жыл бұрын
Very clear proof. Well done!
@WrathofMath3 жыл бұрын
Thank you, glad it was clear!
@ryantrynda30293 жыл бұрын
why is it called triangle inequality thou
@edisonnogalesantezana47612 жыл бұрын
The triangle inequality states that for any triangle, the sum of the lengths of any two sides must be greater than or equal to the length of the remaining side.
@androidandroid9591 Жыл бұрын
An excellent AND simple way to grasp a crucial theorem for the understanding of analysis. Txs.
@WrathofMath Жыл бұрын
Glad to help!
@clementecarbonaro619Ай бұрын
Thank you sir ❤. Your videos are helping me study for my Principles of Mathematics for Economics exam. Your lessons are fast and intuitive
@red39872 жыл бұрын
Beautiful and concise!! thank you for helping me understand this proof better!
@WrathofMath2 жыл бұрын
Thanks so much, glad it helped! Thanks for watching and let me know if you ever have any questions!
@red39872 жыл бұрын
@@WrathofMath WIll do!!!
@punditgi3 жыл бұрын
Can you do an entire video on absolute value identities as building blocks for other theorems? I would also illustrate these both on a 1D number line and on a 2D plane as vectors.
@davaariantara37043 жыл бұрын
like |xy|=|x|*|y|? i think you will find it obvious if you proof it by case-by-case like above in the above video or you can even proof it by |x|=squareroot(x^2) ^ just trying to give you an idea that its not hard
@Alan-sv6ym2 жыл бұрын
We really love you here in south Africa 🇿🇦😭💜💜💜
@WrathofMath2 жыл бұрын
Thank you so much! Love back from the USA's east coast!
@johnsally8320 Жыл бұрын
My man, you're awesome! Much love from Toronto, Canada.
@WrathofMath Жыл бұрын
Thanks so much!
@benjtheo4143 ай бұрын
if 2:44 wasn't directly obvious to you as it was for me you can use this in the proof: a1
@H3XED_OwO10 ай бұрын
beautiful and simple proof!
@WrathofMath10 ай бұрын
Thanks for watching!
@shhaque9448 Жыл бұрын
This guy really did a 2 hour lecture in 5 minutes
@mahmoudalbahar16414 жыл бұрын
Many thanks for this good video.
@EgonuPatrick24 күн бұрын
Am passing maths analysis because of you much love
@WrathofMath23 күн бұрын
Glad to help - thanks for watching!
@Bhaskar3D3 жыл бұрын
It's very good sir. I am from Assam, Indian.
@harjassingh775810 ай бұрын
thank you bro / sir appreciated !!
@husseinsslehi44283 жыл бұрын
Very clear explanation thank you
@WrathofMath3 жыл бұрын
Thanks for watching! If you're looking for more analysis, check out my playlist: kzbin.info/aero/PLztBpqftvzxWo4HxUYV58ENhxHV32Wxli
@jamesjones63593 жыл бұрын
Great explanation. Thank you.
@WrathofMath3 жыл бұрын
My pleasure, thanks for watching and check out my Real Analysis playlist if you're looking for more! kzbin.info/aero/PLztBpqftvzxWo4HxUYV58ENhxHV32Wxli Many new real analysis lessons are coming this year, let me know if you ever have any requests!
@TahaCodes Жыл бұрын
Very nice and neat. Thank you. Got yourself a new sub!!!
@valeriereid23372 жыл бұрын
Thanks for explaining this clearly. If you are able to, please do some work from Abbott's "Understanding Analysis." It would be awesome.
@putin_navsegda64872 жыл бұрын
great proof, very understandable! Thank you!
@WrathofMath2 жыл бұрын
Thank you, glad it helped! Check out my analysis playlist for more! kzbin.info/aero/PLztBpqftvzxWo4HxUYV58ENhxHV32Wxli
@ProgressiveVoice7 ай бұрын
Thanks!
@yibanathimnyanda7253 жыл бұрын
Thank this really helped.
@WrathofMath3 жыл бұрын
So glad to hear it, check out my Real Analysis playlist if you're looking for more, many more analysis lessons still to come! kzbin.info/aero/PLztBpqftvzxWo4HxUYV58ENhxHV32Wxli
@silvo94605 ай бұрын
wow thank you so much sir!!!!!
@Divine_wsk219 ай бұрын
Can you please do the same proof with a,b and c
@ralw76352 ай бұрын
Great, thank you
@samuelbassey6806 Жыл бұрын
Thanks for sharing
@bekhaddaderrar21113 жыл бұрын
Thank you so much for this video
@WrathofMath3 жыл бұрын
My pleasure, thanks for watching! If you're looking for more real analysis, check out my playlist! kzbin.info/aero/PLztBpqftvzxWo4HxUYV58ENhxHV32Wxli
@anasshuaibu25302 жыл бұрын
Very good ' but plz prove it again when â and b are real numbers.
@augustus283411 ай бұрын
great! the only thing that bothered me a little bit is that we didnt take into account when a number is negative and the other is positive. but that case is trivial so i guess doesnt matter that much ahahaha
@rosepierce93824 ай бұрын
I think it doesn't really matter because he is only taking the sum of a + b to be negative or positive.
@jeswintitusjv59272 жыл бұрын
Sir , could I know why this is called as "triangular inequality" ? Is this related to triangle when viewed geometrically ?
@WrathofMath2 жыл бұрын
Thanks for watching and the question! Yes, particularly with vectors involved. Suppose we have points A, B, and C, and then three vectors AB, CB, and AC, that make a triangle. The vector AB is the same as AC + CB if you know vector addition. And this side of the triangle, AB = AC + CB has length |AB| = |AC + CB|, and this length must be no greater than the sum of the other two sides, that is |AC| + |CB|.
@Umar-lj5jx2 жыл бұрын
Thanks a bunch
@ali-hg103 Жыл бұрын
That outro thooo🔥
@WrathofMath Жыл бұрын
Artist goes by Crayon Angel now - love his stuff!
@navjyotsinghvishen32873 жыл бұрын
Group theory from basic 🙏
@TVSuchty4 жыл бұрын
Can you show that over R^n and all possible dot products, where ||a||^2 = a dot a ?
@qedmath17294 жыл бұрын
let a = . By definition of dot product we have a dot a = x^2+y^2. Similarly for a = , ||a|| = sqrt(x^2 + y^2) or ||a||^2 = x^2 + y^2. Hence we see that the 2 are equal.
@TVSuchty4 жыл бұрын
@@qedmath1729 I mean that u show that the theorem holds over all dot products, where by definition ||a||^2 = a dot a
@gianlucalepiscopia3123 Жыл бұрын
Beautiful
@WrathofMath Жыл бұрын
Thanks for watching!
@이머현2 жыл бұрын
super good
@WrathofMath2 жыл бұрын
Thank you! If you're looking for more analysis, check out my playlist! kzbin.info/aero/PLztBpqftvzxWo4HxUYV58ENhxHV32Wxli
@bonniem18659 ай бұрын
Thank you thank you thank you
@WrathofMath9 ай бұрын
You are very welcome!
@muhammadasghar71534 жыл бұрын
I Asked question but you didn't answer me
@pakistaninstituteofmedical71854 жыл бұрын
Yes I also ask question but didn't reply
@ahh614 жыл бұрын
I asked a question and he answered me so be happy. Maybe next time ask a better question.
@muhammadasghar71534 жыл бұрын
Shut up loser baby hahhahah🤑🤑
@ahh614 жыл бұрын
@@muhammadasghar7153 At least I'm not dumb like you. Your question was probably what's 2+2. You stupid. My questions are always answered. He even answered a bunch of my questions on the last live episode.
@WrathofMath4 жыл бұрын
I'm working on it folks, I get a lot of comments and don't have much time. If you ever come by a live stream, that is time I set aside specifically to answer your questions so you can be sure I'll respond if you come by one of those! Thanks for watching and I'm trying to catch up on the comments!
@samborn35152 жыл бұрын
Please I stil find this difficult
@monaalhassanquran2160Ай бұрын
Wow ❤
@existentialrap521 Жыл бұрын
Wrath, once i get this mfing masters degree ima invite you to a carne asada thx G