XI-12-4 Carnot's Cycle (2015)Pradeep Kshetrapal Physics channel

[@georgejohny4800]

59:00 in adiabatic compression the area under the graph should have been DFEAD not DCHFD which is the same as isothermal compression

[@samikshabagai4418]

Sir your videos are very helpful. The way you teach makes every doubt clear. Thank You so much☺️ God bless you sir.

[@SiddharthChakravarthyS]

sir net work done is v4 upon v3

[@Kripan12334]

Shouldn't the work done for adiabatic expansion @32:00 be divided by 1-(Gama)?

[@anush7386]

Sir in book its is given negative why it so in isothermal compression ?

[@dhruvkhush5345]

very informative video. every topic is clear with the help of this video

[@internationalremixes6440]

wowww...I don't know...but when u speak in international language..then I feel proud and I understand more...

[@samriddhisaxena5248]

14:52

[@akhileshsinghyadav4440]

sir i love your vidios it help me lot in this lecture to mistake done by you 1 is work done isothermal process and one is area under the graph you wrote same for adiabatic and isothermal DCHFD but in isothermal it different thanks love you sir

[@akrammohammed1167]

Sir, Explain more in Hindi. That's the Best.

[@rohitmadaan8885]

Sir if in isothermal expension work done is Rtlnv2/v1 then how we take it positive work even v2 is less than v1 logv2-logv1 to negative ho jaye ga

[@hridoysaikia4096]

Sir, in the first step how will heat flow when the temp on both sides is equal...- T1

[@hridoysaikia4096]

sir,...plz clear my doubt...!!

[@prashannashrestha9791]

sir how tempr remains constant in initial process?

[@murtazabohra5388]

Prashanna Shrestha it is an isothermal process. The heat given is directly used to do work.

[@rohankumarsaini890]

thank you sir aapki vajah se aaj exam boht accha tha👍👍😊

[@soumyaranjanbanshamishra5211]

sir in work done in adiabatic expansion you didnot mention denominator 1--¥ that WD=R(t2-t1)/1-¥

[@prathamarya9825]

There is some difference between the irreversible adiabatic process and reversible adiabatic process. In real life applications, we came to see irreversible adiabatic process, thus the formula used by sir is of irreversible adiabatic process .Formula is correct !!!!

[@nalinikushwanshi5985]

at 29:00 u said that if volume increase than temperature decreases but how can it possible if temperature is directly proportional to volume ? plz solve it

[@murtazabohra5388]

Nalini Kushwanshi it is due to adiabatic expansion.It is a sudden process.The volume increases on the basis of its internal energy and hence the internal energy decreases.Internal energy and temperature are related more the internal energy more is the energy and vice versa

[@prathamarya9825]

i agree to (its me) but you shouldn't apply Charles law here as the pressure is not constant. Volume decreases because molecules used their internal energy i.e kinectic energy to increase the volume as sir already told temperature is a function of kinectic energy, thereby temperature reduces .. hope you get the point

[@littledancerchinu9304]

nice explanation sir👌👌

[@shubhamprasad3054]

Sir, The work done in isothermal expansion is given by ------(V1/V2). But Sir you have taken this value as------- (V2/V1) when you derive the efficiency of Carnot's Cycle. Plz clarify Sir , which one is correct ......

[@prathamarya9825]

consider (final volume - initial volume) & integral limits don't be confused, Have a good time!!!

[@nalinikushwanshi5985]

what will happen to efficiency of Carnot engine if 51 equal to zero

[@soumyaray6339]

Sir, the working of refrigerator was little bit confusing. how did the hot air outside the refrigerator become so cold when passed through the capillary tube ?

[@murtazabohra5388]

Soumya Ray its because the gas undergoes adiabatic expansion.The gas expands on the account of its internal energy and hence the internal energy decreases and therefore the temperature decreases.

[@ramindersingh6163]

This is Video 12.4. Please make it correct

[@Kripan12334]

Sir, could not understand it as clear as heat engine... 😢

[@sarabjitsinghsandhu2930]

Me too😅

[@shaleensaifi3018]

nice videos sir

[@ganeshdeshmukh2312]

gjbb

[@deepaknager6740]

chemistry se thoda alag he iliye confusion'./;./;

[@mrstudiesmukhilrpillai8175]

Sir one doubt in adiabatic process the work done is R(∆T)/¥-1 PV^¥=K , but you have written that work done = nR∆T

[@prathamarya9825]

There is some difference between the irreversible adiabatic process and reversible adiabatic process. In real life applications, we came to see irreversible adiabatic process, thus the formula used by sir is of irreversible adiabatic process .Formula is correct !!!!

[@IsarAzam]

Thanku sir

[@anikethans4149]

Sir plz pura lecture sunay kariya

[@shodhanshetty7043]

sir pls once check the formula for work done in adiabatic expansion which u have wriiten which is different from that of textbook

[@cripper4]

sir in lecture 12.1 work done by adiabatic expansion was written as " (nR(T2-T1))/1-Y.... sir where did gamma go ?

[@nalinikushwanshi5985]

sir, it is given in ncert as nR(T2-T1) /1-Y

[@prathamarya9825]

There is some difference between the irreversible adiabatic process and reversible adiabatic process. In real life applications, we came to see irreversible adiabatic process, thus the formula used by sir is of irreversible adiabatic process .Formula is correct !!!!

[@siddhijoshi8759]

Sir we are more comfortable in hindi

[@anikethans4149]

Sir plzz use hindi in ur lecture

[@SantoshYadav-qf6hb]

sir please speak in Hindi it is better understand for us

[@drshabbirlehri]

nice sir mut hindi sounds better

[@sunilthalor9489]

sir hindi aachi smg aati hai

[@RohanKumar-fz8cq]

sir pls teach in hindi

[@shubhamprasad3054]

Sir, The work done in isothermal expansion is given by ------(V1/V2). But Sir you have taken this value as------- (V2/V1) when you derive the efficiency of Carnot's Cycle. Plz clarify Sir , which one is correct ......

[@anush7386]

You are correct sir did mistake it happen

[@aniketsingh9502]

v2/v1 is correct

[@rohankumarsaini890]

thank you sir aapki vajah se aaj exam boht accha tha👍👍😊