You Cannot Solve this in 1st Attempt || Most Likely to Come in IIT-JEE ADVANCE (2023)

[@Sanatan_saarthi_1729]

Calculate p(2),p(3),p(4) using condition. We get pattern an²+bn+c and have 3 condition for that p(0),p(1) and p(2) . Got polynomial easily

[@RZMATHS]

Nice approach 🔥👍

[@siddhantgupta555]

Sir why is it nesscesary for P(X) to be polynomial of degree 2?@@RZMATHS

[@invincible9240]

Probably because the difference of consecutive terms is in ap ​@@siddhantgupta555

[@meetakoul]

Thats op af why dint i think of that

[@tarukhandelwal6471]

Very close to 20k subscribers 🎉

[@anushka._..]

Sir we are always waiting for your maths ques , it really blows ours mind 😊❤

[@rtl78]

Loved it sir

[@animadas4052]

Unique problem unique approach awesome ❤️

[@shreyaspatel2163]

maza aa gaya very good explanation

[@asher46]

thank you so much sir

[@madhubala2049]

What a satisfaction after 15 min of struggle Really worth it❤

[@ronin4923]

just by observation I had a feeling p(x) would be x^2+x+1, and then after that normal tan to cot manipulation to solve the integral. Still a very good advanced level question, very probable

[@maharanapratapinstituteofe9629]

Black book questions certainly

[@tarukhandelwal6471]

When are you uploading next video sir ?

[@nishanthkumaran3168]

One of the only maths channels that provide quality questions consistently, bravo!

[@prathamrana8916]

good one as always thanks sir

[@GaneshKumatole7]

WE CAN ALSO DO ..BY , FINDING P(X) BY , PUTTING VALUES... AND FINDING SOME VALUE @ 2,3,4,... (PATTERN OBS.) , NOW TO FIND GENERAL TERM .... METHOD OF DIFFERENCE.... THEN , INTEGRATE., .. I LIKED THAT MANIPULATION IN INTEGRATION, tan^-1(...)---> Cot^-1(...) ---> back to tan^-1(...) .. ,OTHERWISE MANY TIMES BY PARTS WOULD BE TEDIOUS. TQ , SIR. ♥️🔥💪.

[@GaneshKumatole7]

THIS CONTENT IS HELPFULL FOR THE 15-20% ---> OF THE PAPER WHICH IS BASED ON PROBLEM SOLVING SKILLS. TQ

[@kewalmer7225]

We can just write P(x-1)/P(x)=(x-1)^2+x-1+1/(x^2+x+1) thus p(x) is x^2+x+, also got it in first try though it took some time

[@AdityaSharma-qb5qp]

it mightve worked for you in that case but wont give the right answer always, that way you ignored the possibility of Px being the type of : some constant * (polynomial part). The ratio is just of the polynomial part.

[@kewalmer7225]

@@AdityaSharma-qb5qp yeah I figured it was 1 since p(1)=3 if it wasnt then I wouldve just multiplied the constant but thanks

[@garvittiwari6266]

It won't work everytime cuz it's in ratio..

[@priyanshupratik5197]

A method could be by taking x-1=t and finding p(t) by that we get p(x) and p(t) are looking similar except the variable that in p of t there is t and p of x there is x but we already specified that t and x are consecutive no. Or x-t=1 hence t and x are co prime by that we get p(t)=p(x)=x2+x+1. Hence we proceed. Thank you!!!!!

[@garvittiwari6266]

We can compute p(0) , p(2), p(3) etc and we will get a sequence that we can solve using delta t1 method and get the polynomial

[@chewie2743]

Got it quite easily in first try, very interesting question 🎉

[@nikhil....2021]

This problem is from Sameer Bansal calculus iit jee😊

[@bigdaddy055]

Yes from ex5 definite integrartion

[@godoffootball537]

Exactly

[@potath10e]

Got it in first attempt using pure intuition

[@piyushtechnology6578]

Thank u for the short integration.... 😊😊

[@patel565]

Sir aap A² sir se padhe ho kya Atish Agarwal sir se please reply

[@aditsaini5094]

11:08 nv sir reference??

[@hmm.3367]

12?

[@hmm.3367]

Let's goo Got it in the first attempt

[@sanketpathak6621]

@@hmm.3367 yup that's correct

[@MRCRAZYSAURABH]

IIT B

[@parijatpushpam7500]

Hii sir. If possible can I connect with you on LinkedIn?

[@tarukhandelwal6471]

Yes