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@qtpi07 ай бұрын
differentiate it as a function raised to a constant and then differentiate it as a constant raised to a function and then add the two answers together and see what you get
@NumberNinjaDave7 ай бұрын
Feel free to go ahead and do that to show us your work
@@qtpi0 this method happens to get the answer but isn’t a sound approach First 1/x needs to be taken with caution as what if x is 0? Second, the first half didn’t really make progress. It just landed back at the original problem
@qtpi07 ай бұрын
@@NumberNinjaDave well if x=0 the original problem would be undefined as 0^0 and this is just a trick if you need to impress someone :)
@NumberNinjaDave7 ай бұрын
@@qtpi0 0^0 is defined as 1 (some schools of thought say undefined, but I’m from the school of thought that there’s only one element in the power set of the empty set and so it’s an agreed on multiplicative identity). But your method allows division by 0 in the 1/x step.
@DaanHun7 ай бұрын
i think it would look a bit nicer to just write x^x instead of e^ln(x^x) and factor out the x^x so you get x^x(ln(x)+1). But nice video!
@NumberNinjaDave7 ай бұрын
Thank you! Yeah, just personal preference
@NumberNinjaDave9 ай бұрын
What do you all think of me adding study background music in my videos? Distracting or helpful?
@CarlJohnson-mi2zo8 ай бұрын
That e^ln(x) property is so useful for this kind of weird derivatives
@NumberNinjaDave8 ай бұрын
For sure
@whiteshark60049 ай бұрын
Great content , keep going !!!!
@NumberNinjaDave9 ай бұрын
I appreciate you, ninja
@victorferreira58528 ай бұрын
I dont understand, what is the problem you are talking about? Is it what you just said in the video, about the power not being a constant? I dont know any other issue...
@NumberNinjaDave8 ай бұрын
Yes, a non constant and how to solve it
@NumberNinjaDave9 ай бұрын
Quiz question: why can’t the answer simply be x(x^(x-1))??? Tell me below
@kingbeauregard26 күн бұрын
That's not the result you get by the definition of the derivative.