Z Transform and Inverse Z Transform: Relation with Discrete Fourier Transform

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[@iqcreatives1031]

Crystal clear explanation

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[@praveenrahuls4548]

Thanks brother...👐🏻

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Your welcome

[@harshildave330]

Sir your explanation is superb 👌

[@EngineeringFunda]

Keep watching

[@chaturvedielectricalinstit9009]

very good explaination sir

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[@Ananya-o3l]

Thank you for help

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[@AdityaThakur-qu6ss]

U made a mistake at 3:54, u wrote DFT but actually it is DTFT

[@TusharKumar-iu4nt]

Sir if this is in discrete time then why are we integrating?

[@EngineeringFunda]

In time it is discrete but by frequency it has continous magnitude.

[@ececse]

Thankyou sir

[@EngineeringFunda]

Your Appreciations, care and share matters a lot to me. #EnginneringLove. All the subjects playlist of Engineering Funda is available in comment section. Share it with your friends to support us. Your positive comments motivates me and person like me get boosted by my students feedback. Thanks and welcome 🙏

[@debojitdeori4837]

It's discrete time Fourier transform

[@champakdaas]

Smart boy

[@themoonlight1922]

Sir, while substituting z = re^(jw), the limits of integration will be changed from [-oo , oo] to [0,oo]. Am I correct?

[@prathmeshdesai6806]

no

[@venkatalovakumar8614]

Sir why did you taken Z= r.e^jw .?

[@SIREESHAkolluri-nv5og]

It is a formula of a polar form

[@monkeykingagain]

classic

[@fazilkhan6907]

Karri pooku , kampu dengutundi