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@nobody-fq9hc
@nobody-fq9hc 22 сағат бұрын
Thank you sir
@SomithanKamal-nv1yc
@SomithanKamal-nv1yc Күн бұрын
I am in Sri Lankan sir we are so blessed because of your vedio you and your family have a wonderful life always
@OwenChen-e4r
@OwenChen-e4r 5 күн бұрын
there is something missing at the last expression it should be ai = <phi*|f> instead of phi
@giriff8398
@giriff8398 5 күн бұрын
Very nice intro❤❤❤
@rishabghosh7685
@rishabghosh7685 7 күн бұрын
Thank you very much for these videos. You are a life saver.
@nghiaphan3318
@nghiaphan3318 8 күн бұрын
pls help me how to add frame.file into this molecule, now I just have 1 frame for this molecule, so I cannot make my molecule vibrated
@lzk9933
@lzk9933 8 күн бұрын
very clear explanation, thank you!
@manfredbogner9799
@manfredbogner9799 10 күн бұрын
Sehr gut
@MissionSilo
@MissionSilo 24 күн бұрын
Thanks. Not sure how this would help a wanna be hobbist but thanks
@MinooRezaie-fv8se
@MinooRezaie-fv8se 25 күн бұрын
I can't download the slides from the link , I think it has a problem
@zafhalasdfn3324
@zafhalasdfn3324 Ай бұрын
Thanks guy. Much appreciated.
@user-to3fx2do4d
@user-to3fx2do4d Ай бұрын
Unfortunately, in general, neither symmetric nor anti-symmetric wavefunctions can be said to be eigenfunctions of the Hamiltonian. The wave function for an electron in a hydrogen-like atom with atomic number Z in the ground state is RZ(r)=2(Z/a0)^(3/2)*exp(-Zr/a0). RZ(r) is an eigenfunction of HZ=1/(2m)*p^2-Ze^2/(4πε0r). But RZ(r) is not an eigenfunction of HZ'=1/(2m)*p^2-Z'e^2/(4πε0r), Z'≠Z. Let us consider the case where a hydrogen-type atom with atomic number Z and a hydrogen-type atom with atomic number Z' are sufficiently separated from each other. And each electron in each atom is in the ground state. The anti-symmetric wave function Ψ={RZ(r1)RZ'(r2)-RZ(r2)RZ'(r1)}/2^(1/2) is not an eigenfunction of the Hamiltonian H=1/(2m)*p1^2-Ze^2/(4πε0r1)+1/(2m)*p2^2-Z'e^2/(4πε0r2). It should be an ironclad rule of quantum mechanics that the wave function is an eigenfunction of the Hamiltonian.
@RAWM13
@RAWM13 Ай бұрын
Do you like Spartan? My prof uses it but I have never heard of it
@strikegamer4832
@strikegamer4832 Ай бұрын
Thank you so much ❤
@walacross
@walacross Ай бұрын
For some stupid reason I couldn’t figure out what I would do if it wasn’t a cubical box due to the equations in my textbook simply writing L^3, but you writing them separately as lx,ly,and lz made it make way more sense, thank you so much :D. Sometimes these simple concepts can be overlooked.
@madhurjyachakravarty7237
@madhurjyachakravarty7237 Ай бұрын
@madhurjyachakravarty7237
@madhurjyachakravarty7237 Ай бұрын
🙏
@SampleroftheMultiverse
@SampleroftheMultiverse Ай бұрын
This video shows under the right conditions, the quantization of a field is naturally produced. The ground state energy is induced via Euler’s contain column analysis. The containment of the column must come in to play before over buckling occur or the effect will not work. The system response in a quantized manor when force is applied in the perpendicular direction. Bonding at the points of highest probabilities and maximum duration( peeks and troughs) of the fields/sheet produced a stable structure out of three fields People say I am just plucked guitar strings. I said you can not make structures with vibrating guitar strings or harmonic oscillators. kzbin.info/www/bejne/raOlpKSfepWpfZYsi=waT8lY2iX-wJdjO3 In the model, “U” shape waves are produced as the loading increases and just before the wave-like function shifts to the next higher energy level. Over-lapping all the waves frequencies together using Fournier Transforms, I understand makes a “U” shape or square wave form. If this model has merit, seeing the sawtooth load verse deflection graph produced could give some real insight in what happened during the quantum jumps. You can reproduce my results using a sheet of Mylar* ( the clear plastic found in school folders.
@Everson_Computational
@Everson_Computational 2 ай бұрын
Great video.
@Everson_Computational
@Everson_Computational 2 ай бұрын
Thanks.
@mahmoudhammad812
@mahmoudhammad812 2 ай бұрын
6:43; it should be 5 and not 4
@yarenderinel6926
@yarenderinel6926 2 ай бұрын
what if the max values are present but the another term for -1 is lost ?
@the.kemetic.Religion.believers
@the.kemetic.Religion.believers 2 ай бұрын
great job from egypt
@Abcs-o7j
@Abcs-o7j 2 ай бұрын
Please make some lectures on machine learning in chemistry
@sdeb3333
@sdeb3333 2 ай бұрын
Great job ! We need more tutors like you. ❤
@manrajlally
@manrajlally 2 ай бұрын
Thanks
@hayleebridge5156
@hayleebridge5156 2 ай бұрын
thank you thank you thank you
@hewaahmedmustafa8027
@hewaahmedmustafa8027 2 ай бұрын
these preprint papers claimed reversing entropy by mixing Raoult's law with osmosis principle and extended Gibbs Donnan Equilibrium . What do you think about this novel approach? Title of the papers: Experimental Demonstration of Energy Harvesting by Maxwell's Demon Device DOI: 10.20944/preprints202403.1698.v1 .... An Autonomous Mechanical Maxwell's Demon DOI: 10.14293/S2199-1006.1.SOR-.PP5S6NK.v1
@InquilineKea
@InquilineKea 3 ай бұрын
What is sigma h of water
@kekero540
@kekero540 3 ай бұрын
Time for me to develop another unhealthy hyperfixation for the next few months.
@Kevinfreddo
@Kevinfreddo 3 ай бұрын
Do the terms [aa|bb] & [ab|ba] represent the exact coulomb and exchange integrals (with double integration over x1 and x2), or do they represent the mean field approximation (with a single integral over solely x2?) I can’t tell if the Fock operator results from the substitution of the approximate mean-field integrals for J and K, or if the Fock operator is a natural result (without any need for substitution in this derivation) of assuming the total electronic wave-function takes the form of a slater determinant of one-electron spin orbitals
@wendellespinales1714
@wendellespinales1714 3 ай бұрын
Great video 👌👌
@Unidentifying
@Unidentifying 3 ай бұрын
I think theres something wrong with your partition function notation Q, when you sum over the states and use index i, the E_i would also change , so you change/sum over the energy level and not the states which you say it will do? Confusing
@Everson_Computational
@Everson_Computational 3 ай бұрын
Thank you so much.
@InquilineKea
@InquilineKea 3 ай бұрын
what are triply/quadruply excited determinants?
@alexandrfedorov7297
@alexandrfedorov7297 3 ай бұрын
You are the best😮
@martinsisrael12
@martinsisrael12 3 ай бұрын
Quem entender esses princípios entenderá o inicial conceito de como funciona o computador quântico e o que é o conceito da superposição. Não é tão fácil quanto as portas lógicas mas com a mente aberta é possível começar a compreender esses conceitos.
@ezequielson5677
@ezequielson5677 3 ай бұрын
So good. I loved the explanation. Thank you!!!
@ariadnaborrasbadia1146
@ariadnaborrasbadia1146 3 ай бұрын
you sound like ryan reynolds
@b6kf367
@b6kf367 3 ай бұрын
in the previous video, J, K were having 2 indices now why it's only one here?
@b6kf367
@b6kf367 3 ай бұрын
okay I got it's due to mean field but J need 2 wave functions on the right to operator right? your green equation on right has only 1 electrons wave fucntion
@user-eb3th4hb3d
@user-eb3th4hb3d 4 ай бұрын
the un(x,t) function serves as the basis of U(x,t) wave. Is un(x,t) quantised here? or components withing un(x,t) are quantised? I feel un(x,t) shouldn't be quantised since we get to choose the coeff. An, so unless An are equal to 0,1,2,3...(integral values) I feel I'm thinking something wrong please correct me and share the correct way to look at this problem(What exactly is quantised here)
@jaybae8056
@jaybae8056 4 ай бұрын
so how do you get the overall N factor? i am new to this. can you do the complete thing for lets say 2s e-? like, all longhand.
@TheOwlGilga
@TheOwlGilga 4 ай бұрын
You're the king of chemistry, doing the job of 10 of my professors as what appears to be from your latest video's comment section, pure altruism. I am constantly at the verge of being expelled from my chemistry major for being so bad at chemistry in my university (in my nation you get banned from your major nationwide if you fail an exam thrice) yet your videos always come in clutch. 🤗
@NVANAPALLIVENKATASATYAUMASHANK
@NVANAPALLIVENKATASATYAUMASHANK 4 ай бұрын
thank you
@NVANAPALLIVENKATASATYAUMASHANK
@NVANAPALLIVENKATASATYAUMASHANK 4 ай бұрын
thank you so much
@rebekkakanerva4292
@rebekkakanerva4292 4 ай бұрын
My material science prof decided not to go over this at all because "surely you've all already familiar with the Schrödinger equation", which we chemistry students, in fact, were not. So this was such a great and clear explanation of this model! Thank you!
@GiStormy
@GiStormy 4 ай бұрын
Thank you so much for this!
@sriram.s6297
@sriram.s6297 5 ай бұрын
On expanding the hamiltonian, why is there a negative sign in front of the potential energy of the nucleus?
@dirklutz2818
@dirklutz2818 4 ай бұрын
because the potential energy increases
@user-uj2iq2dq2d
@user-uj2iq2dq2d 5 ай бұрын
COME BACK...!!!!😔
@helza9623
@helza9623 5 ай бұрын
i dont understand a single word but thank you anyway