Adjacency Matrix | Linear Algebra
26:08
Cubic Spline | Numerical Computation
32:19
Diagonalization | Linear Algebra
38:06
Пікірлер
@madwin11
@madwin11 Күн бұрын
Hey, I noticed a mistake in your calculation for a) You actually calculated the decimal number for 0 11010111 01101010000000000000000 You just had the Exponent wrong. Nevertheless, thank you so much! Because of you, I understand the converting now.
@Computervirusworld
@Computervirusworld 4 күн бұрын
👍
@moodman6426
@moodman6426 23 күн бұрын
thank you so much, I have an exam today and this video just saved me
@theinfinitemath11
@theinfinitemath11 23 күн бұрын
Glad it was helpful…
@RomanKnav
@RomanKnav Ай бұрын
could you please explain how you got 7.8125 and 10^-3 when solving for the smallest number?
@maxima4116
@maxima4116 2 ай бұрын
i picked the interval (0,1) and my root is 0.5859375
@maxima4116
@maxima4116 2 ай бұрын
what i dont pick the (1, 3.2) interval, would it still yield the same result if i were to pick (0,1)?
@47srinjoyraychaudhuri75
@47srinjoyraychaudhuri75 2 ай бұрын
Is the formula shown in 4:01 correct?....some other channels are doing with some other formula. Are there any other formula?
@spreadingknowledge2658
@spreadingknowledge2658 2 ай бұрын
thanks u so much you have a good way to explaining
@theinfinitemath11
@theinfinitemath11 2 ай бұрын
Glad it helped!
@sopharesmith5432
@sopharesmith5432 2 ай бұрын
Thank you madam 😊
@theinfinitemath11
@theinfinitemath11 2 ай бұрын
Glad it was helpful…
@salimhossennizamnizam6007
@salimhossennizamnizam6007 2 ай бұрын
Nice vedio❤
@shaziakakar5962
@shaziakakar5962 3 ай бұрын
Ma'am books name please
@oguzyucel8216
@oguzyucel8216 3 ай бұрын
ok thanks but how do we find the error value after the first iteration because xnew is obtained but there is not a xold value? btw i got an exam tomorrow im praying that you'd answer this 'till tomorrow
@ahsanahmedbappy5620
@ahsanahmedbappy5620 3 ай бұрын
please upload forward , backward and central 3rd and 4th order
@AWAISKHALID-ze5cw
@AWAISKHALID-ze5cw 4 ай бұрын
such a rubbish video
@HashemAljifri515
@HashemAljifri515 4 ай бұрын
I found it to be - 2.4 how it is positive?
@user-kp5pn2qj5g
@user-kp5pn2qj5g 4 ай бұрын
Thanks madam
@theinfinitemath11
@theinfinitemath11 4 ай бұрын
Glad it helped…
@janroseathena8075
@janroseathena8075 5 ай бұрын
Thank you for this! I love how I can learn just by hearing your voice T_T thank youuuuu. You are truly a gem!
@theinfinitemath11
@theinfinitemath11 5 ай бұрын
You're so welcome dear… And thank you too…
@janroseathena8075
@janroseathena8075 5 ай бұрын
i love your teaching <3 so inspiring
@theinfinitemath11
@theinfinitemath11 5 ай бұрын
Glad you enjoy it!
@Pakistani_media
@Pakistani_media 6 ай бұрын
Madom hamein to Urdu bari mushkil se samjh ati ha ap English m Bta rhi hain😮😢
@user-wc3qg4ci5l
@user-wc3qg4ci5l 6 ай бұрын
You voice made me focus 100% and i got it 100% too. You have a nice voice. Thanks
@theinfinitemath11
@theinfinitemath11 6 ай бұрын
Glad you got the concept…
@user-yz9ew7ow5z
@user-yz9ew7ow5z 6 ай бұрын
Do you guys have a Instagram page?
@ArifurRahman-ng6zt
@ArifurRahman-ng6zt 3 ай бұрын
Yea
@DeepakYadav-ys7dg
@DeepakYadav-ys7dg 7 ай бұрын
The method and everything is easy but the formula 😵
@AJTimePyro
@AJTimePyro 7 ай бұрын
Tu yaha kya kr rha hai?
@adarshbajpai4902
@adarshbajpai4902 8 ай бұрын
U noted wring question dude
@adoptedshrek6655
@adoptedshrek6655 8 ай бұрын
Thank u mam'
@theinfinitemath11
@theinfinitemath11 8 ай бұрын
Most Welcome…
@adoptedshrek6655
@adoptedshrek6655 8 ай бұрын
shukria
@HH-yb2dv
@HH-yb2dv 8 ай бұрын
Hello
@MVBMOHDSHADAB
@MVBMOHDSHADAB 9 ай бұрын
Ma'am can you please help me out in finding the magnitude of largest/smallest integer/float for 16/32 bits and also relative error bound for 32 bits.
@n_hayo6125
@n_hayo6125 9 ай бұрын
Backward difference is wrong ma'am but thank u for the explanation
@theinfinitemath11
@theinfinitemath11 9 ай бұрын
The correction is in the description of the video. Glad it was helpful…
@muhammadnathem7664
@muhammadnathem7664 9 ай бұрын
what do you mean use radiant in my calculator?
@theinfinitemath11
@theinfinitemath11 9 ай бұрын
Good to see you are focused on the details. Use your calculator in the Radians mode and not degrees here when you are working with sin, cos, tan. The following link might help clear your doubt: kzbin.info/www/bejne/kHaTcoSff5uSitksi=rvja9PEgn3X7dGnb
@GLuna123
@GLuna123 9 ай бұрын
Hi! Shouldn’t it be 5*10^-2 as the exponent was 1-3? Minute 3:49 I started with numerical computation this semester and your playlist will be very helpful. So far it has been clear and easy to follow, thanks!
@theinfinitemath11
@theinfinitemath11 9 ай бұрын
Great to hear the tutorials are helping you! Regarding your question, the answer in the video is correct. What we are solving here is: (1/2) x 10^(-2) = 0.5 x 0.01 = 0.005 = 5 x 10^(-3) I hope this helps…
@GLuna123
@GLuna123 9 ай бұрын
Indeep, it helped. Thanks!@@theinfinitemath11
@ShahrukhKhan-cy7hg
@ShahrukhKhan-cy7hg 10 ай бұрын
Very helpful video thank you
@theinfinitemath11
@theinfinitemath11 10 ай бұрын
Glad it was helpful…
@marcoamir5107
@marcoamir5107 10 ай бұрын
great
@andilengcobo5111
@andilengcobo5111 10 ай бұрын
why did you upload the video with such mistakes though
@andilengcobo5111
@andilengcobo5111 10 ай бұрын
nonsense
@guddukumarray9020
@guddukumarray9020 10 ай бұрын
Thank god I found it
@farazsshaikh
@farazsshaikh 11 ай бұрын
u did a mistake in backward difference but it is okay we understood, thanks
@hammadkhan3630
@hammadkhan3630 11 ай бұрын
Tomorrow i have terminal of numberical analysis it's great too be that you explained better to our cobra pro max 😂😂😂😂
@IkramKhan-qh1lh
@IkramKhan-qh1lh Жыл бұрын
Your from Bangladesh??
@maheshikarathnayake3389
@maheshikarathnayake3389 Жыл бұрын
Thank you 🌹
@avnishojha4744
@avnishojha4744 Жыл бұрын
how did you obtain those function values?
@theinfinitemath11
@theinfinitemath11 Жыл бұрын
Hello… Could you please detail your question? So I can understand your area of doubt.
@adenikeogunyemi6515
@adenikeogunyemi6515 Жыл бұрын
please how do u get x2=2.4 am confused
@theinfinitemath11
@theinfinitemath11 Жыл бұрын
If you could specify where exactly you are facing the problem would be good. Anyhow assuming you are having problems with calculation part, I got the answer in the following way: X2 = 2 - [(-2)[(2-3)/(-2-3)]] X2 = 2 - [(-2)[-1/-5]] X2 = 2 - [-2/5] X2 = 2 + [2/5] X2 = 2.4 Hope this helps!
@delleuniverse2735
@delleuniverse2735 3 ай бұрын
@@theinfinitemath11 The answer should be x2= 0.8 if you follow the formula you gave us
@delleuniverse2735
@delleuniverse2735 3 ай бұрын
f(xn) is outside the bracket
@mustafaazhar4004
@mustafaazhar4004 Жыл бұрын
what if x date is not increase by 1 ! you take example h=1 what if the different between x- date is not same iteration !
@makifalbsuloandrews9488
@makifalbsuloandrews9488 Жыл бұрын
Check (II) for us
@theinfinitemath11
@theinfinitemath11 Жыл бұрын
Thank you for bringing the mistake to light... The answer to question (ii) absolute error is not correct somehow. It is supposed to be, 2.818 x (10^(-4)). However, the relative error for the same question is correct!
@conde3915
@conde3915 Жыл бұрын
I can tell you're cute
@siam-ulhaqueshownaq108
@siam-ulhaqueshownaq108 Жыл бұрын
Can you kindly show me for third order central difference? Thank you
@alshookryalsir4707
@alshookryalsir4707 Жыл бұрын
Thanks for this gorgeous explanation 💕
@nicholasmartinez9247
@nicholasmartinez9247 Жыл бұрын
your bounds for (i) doesn't seem correct. If we are using (Z_i+1) then we would stop at z_3, since when i = 2, Z_(i+1) = Z_(3), However we don't have x_3, y_3. So It would make more sense to bound i to be less than or equal to 1, not 2. when i = 1, Z_(i+1) = Z_2. Which would also be our final Z. if you set some variable k = i + 1, then you can bound k to being less than or equal to 2.
@dekatsan1705
@dekatsan1705 Жыл бұрын
Very nice and clear expline&tutorial Thank you!
@ikramaghouri6786
@ikramaghouri6786 Жыл бұрын
Superb, that was literally my assignment question ....... You saved my life ❤️
@da-ksh
@da-ksh Жыл бұрын
you have a nice voice and explaination could be have been better