Hey, I noticed a mistake in your calculation for a) You actually calculated the decimal number for 0 11010111 01101010000000000000000 You just had the Exponent wrong. Nevertheless, thank you so much! Because of you, I understand the converting now.
@Computervirusworld4 күн бұрын
👍
@moodman642623 күн бұрын
thank you so much, I have an exam today and this video just saved me
@theinfinitemath1123 күн бұрын
Glad it was helpful…
@RomanKnavАй бұрын
could you please explain how you got 7.8125 and 10^-3 when solving for the smallest number?
@maxima41162 ай бұрын
i picked the interval (0,1) and my root is 0.5859375
@maxima41162 ай бұрын
what i dont pick the (1, 3.2) interval, would it still yield the same result if i were to pick (0,1)?
@47srinjoyraychaudhuri752 ай бұрын
Is the formula shown in 4:01 correct?....some other channels are doing with some other formula. Are there any other formula?
@spreadingknowledge26582 ай бұрын
thanks u so much you have a good way to explaining
@theinfinitemath112 ай бұрын
Glad it helped!
@sopharesmith54322 ай бұрын
Thank you madam 😊
@theinfinitemath112 ай бұрын
Glad it was helpful…
@salimhossennizamnizam60072 ай бұрын
Nice vedio❤
@shaziakakar59623 ай бұрын
Ma'am books name please
@oguzyucel82163 ай бұрын
ok thanks but how do we find the error value after the first iteration because xnew is obtained but there is not a xold value? btw i got an exam tomorrow im praying that you'd answer this 'till tomorrow
@ahsanahmedbappy56203 ай бұрын
please upload forward , backward and central 3rd and 4th order
@AWAISKHALID-ze5cw4 ай бұрын
such a rubbish video
@HashemAljifri5154 ай бұрын
I found it to be - 2.4 how it is positive?
@user-kp5pn2qj5g4 ай бұрын
Thanks madam
@theinfinitemath114 ай бұрын
Glad it helped…
@janroseathena80755 ай бұрын
Thank you for this! I love how I can learn just by hearing your voice T_T thank youuuuu. You are truly a gem!
@theinfinitemath115 ай бұрын
You're so welcome dear… And thank you too…
@janroseathena80755 ай бұрын
i love your teaching <3 so inspiring
@theinfinitemath115 ай бұрын
Glad you enjoy it!
@Pakistani_media6 ай бұрын
Madom hamein to Urdu bari mushkil se samjh ati ha ap English m Bta rhi hain😮😢
@user-wc3qg4ci5l6 ай бұрын
You voice made me focus 100% and i got it 100% too. You have a nice voice. Thanks
@theinfinitemath116 ай бұрын
Glad you got the concept…
@user-yz9ew7ow5z6 ай бұрын
Do you guys have a Instagram page?
@ArifurRahman-ng6zt3 ай бұрын
Yea
@DeepakYadav-ys7dg7 ай бұрын
The method and everything is easy but the formula 😵
@AJTimePyro7 ай бұрын
Tu yaha kya kr rha hai?
@adarshbajpai49028 ай бұрын
U noted wring question dude
@adoptedshrek66558 ай бұрын
Thank u mam'
@theinfinitemath118 ай бұрын
Most Welcome…
@adoptedshrek66558 ай бұрын
shukria
@HH-yb2dv8 ай бұрын
Hello
@MVBMOHDSHADAB9 ай бұрын
Ma'am can you please help me out in finding the magnitude of largest/smallest integer/float for 16/32 bits and also relative error bound for 32 bits.
@n_hayo61259 ай бұрын
Backward difference is wrong ma'am but thank u for the explanation
@theinfinitemath119 ай бұрын
The correction is in the description of the video. Glad it was helpful…
@muhammadnathem76649 ай бұрын
what do you mean use radiant in my calculator?
@theinfinitemath119 ай бұрын
Good to see you are focused on the details. Use your calculator in the Radians mode and not degrees here when you are working with sin, cos, tan. The following link might help clear your doubt: kzbin.info/www/bejne/kHaTcoSff5uSitksi=rvja9PEgn3X7dGnb
@GLuna1239 ай бұрын
Hi! Shouldn’t it be 5*10^-2 as the exponent was 1-3? Minute 3:49 I started with numerical computation this semester and your playlist will be very helpful. So far it has been clear and easy to follow, thanks!
@theinfinitemath119 ай бұрын
Great to hear the tutorials are helping you! Regarding your question, the answer in the video is correct. What we are solving here is: (1/2) x 10^(-2) = 0.5 x 0.01 = 0.005 = 5 x 10^(-3) I hope this helps…
@GLuna1239 ай бұрын
Indeep, it helped. Thanks!@@theinfinitemath11
@ShahrukhKhan-cy7hg10 ай бұрын
Very helpful video thank you
@theinfinitemath1110 ай бұрын
Glad it was helpful…
@marcoamir510710 ай бұрын
great
@andilengcobo511110 ай бұрын
why did you upload the video with such mistakes though
@andilengcobo511110 ай бұрын
nonsense
@guddukumarray902010 ай бұрын
Thank god I found it
@farazsshaikh11 ай бұрын
u did a mistake in backward difference but it is okay we understood, thanks
@hammadkhan363011 ай бұрын
Tomorrow i have terminal of numberical analysis it's great too be that you explained better to our cobra pro max 😂😂😂😂
@IkramKhan-qh1lh Жыл бұрын
Your from Bangladesh??
@maheshikarathnayake3389 Жыл бұрын
Thank you 🌹
@avnishojha4744 Жыл бұрын
how did you obtain those function values?
@theinfinitemath11 Жыл бұрын
Hello… Could you please detail your question? So I can understand your area of doubt.
@adenikeogunyemi6515 Жыл бұрын
please how do u get x2=2.4 am confused
@theinfinitemath11 Жыл бұрын
If you could specify where exactly you are facing the problem would be good. Anyhow assuming you are having problems with calculation part, I got the answer in the following way: X2 = 2 - [(-2)[(2-3)/(-2-3)]] X2 = 2 - [(-2)[-1/-5]] X2 = 2 - [-2/5] X2 = 2 + [2/5] X2 = 2.4 Hope this helps!
@delleuniverse27353 ай бұрын
@@theinfinitemath11 The answer should be x2= 0.8 if you follow the formula you gave us
@delleuniverse27353 ай бұрын
f(xn) is outside the bracket
@mustafaazhar4004 Жыл бұрын
what if x date is not increase by 1 ! you take example h=1 what if the different between x- date is not same iteration !
@makifalbsuloandrews9488 Жыл бұрын
Check (II) for us
@theinfinitemath11 Жыл бұрын
Thank you for bringing the mistake to light... The answer to question (ii) absolute error is not correct somehow. It is supposed to be, 2.818 x (10^(-4)). However, the relative error for the same question is correct!
@conde3915 Жыл бұрын
I can tell you're cute
@siam-ulhaqueshownaq108 Жыл бұрын
Can you kindly show me for third order central difference? Thank you
@alshookryalsir4707 Жыл бұрын
Thanks for this gorgeous explanation 💕
@nicholasmartinez9247 Жыл бұрын
your bounds for (i) doesn't seem correct. If we are using (Z_i+1) then we would stop at z_3, since when i = 2, Z_(i+1) = Z_(3), However we don't have x_3, y_3. So It would make more sense to bound i to be less than or equal to 1, not 2. when i = 1, Z_(i+1) = Z_2. Which would also be our final Z. if you set some variable k = i + 1, then you can bound k to being less than or equal to 2.
@dekatsan1705 Жыл бұрын
Very nice and clear expline&tutorial Thank you!
@ikramaghouri6786 Жыл бұрын
Superb, that was literally my assignment question ....... You saved my life ❤️
@da-ksh Жыл бұрын
you have a nice voice and explaination could be have been better