I assumed Z0 = 1 instead of 0, and got the right answer. i don't really know why but it works.
@muwongeevanspaul91662 жыл бұрын
Thanks so much. What a nice and wonderful Job....am so blessed. Thanks so much. You have my subscription. Notify me always with all.
@theinfinitemath112 жыл бұрын
You are most welcome and thank you too…
@burakgecer84712 жыл бұрын
Loves from Turkey
@theinfinitemath112 жыл бұрын
Thank you a lot..
@nicholasmartinez9247 Жыл бұрын
your bounds for (i) doesn't seem correct. If we are using (Z_i+1) then we would stop at z_3, since when i = 2, Z_(i+1) = Z_(3), However we don't have x_3, y_3. So It would make more sense to bound i to be less than or equal to 1, not 2. when i = 1, Z_(i+1) = Z_2. Which would also be our final Z. if you set some variable k = i + 1, then you can bound k to being less than or equal to 2.
@AJ-et3vf2 жыл бұрын
Awesome video! Thank you!
@theinfinitemath112 жыл бұрын
You are most welcome!
@shaziakakar59626 ай бұрын
Ma'am books name please
@yogeshnath66692 жыл бұрын
Nice
@LOVEPREETSINGH-xh5uz3 жыл бұрын
you teach very well but little slow,i watch at 2x but it is still slow. and you donot covers cubic splines.
@DeepakYadav-ys7dg10 ай бұрын
The method and everything is easy but the formula 😵