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Пікірлер
@MrJayprakashgupta Күн бұрын
Limits wrong put kiye hai rhs mein
@nejla76 4 күн бұрын
AB+BC+CA=300+200+100 (10A+B)+(10B+C)+(10C+A)=600 11A+11B+11C=600 11(A+B+C)=600 A+B+C=600/11
@Yoyovpn 5 күн бұрын
Why not the other two solutions?? Is there any restriction given in the qn stating *x* is an Integer?
@icespeckledhens 5 күн бұрын
Very well explained
@zetutor 3 күн бұрын
Glad it was helpful!
@greasyboy349 5 күн бұрын
sir P(A ∪ B) = P(A) + P(B) - P(A ∩ B) your formula is wrong
@mrenergy989 19 күн бұрын
According to noobs 1/infinity is nearly equal to 0 +1 gives 1 and any power on 1 gives 1
@steveharry4678 24 күн бұрын
Thank you so much sir
@zetutor 23 күн бұрын
Most welcome
@rahulbhushna14 25 күн бұрын
Why considering a circle ?
@mrunalikalukhe8159 Ай бұрын
AB+BC+AC=100+200+300= 600 We can write it as =(A+B+C)(A+B+C)=600 =2(A+B+C)=600 =(A+B+C)=600÷2 =(A+B+C)=300
@SmokalotOPott 4 күн бұрын
That’s is not correct, ab+ac+bc is not 2(a+b+c).
@MathLove_1 Ай бұрын
nice integral, solving integrals is so much fun
@avinashmehrunkar5041 Ай бұрын
We can solve it in this way also (a × b) ÷( b × c) =100 ÷ 200 a ÷ c = 1/2 or a = c ÷ 2 Put this value of 'a' in equation c × a = 300 c × c ÷ 2 = 300 c^2 = 600 c = sq root of 600 i.e (10×sq root of 6 = c) c × a = 300 so 10 sq root 6 × a = 300 a = 300 ÷ (10 sq root 6) a = 30 ÷ sq root 6 or (30 × sq root 6) ÷ 6 This gives a = 5 × sq root 6 Putting this value of 'a' in a × b = 100 we get (5 × sq root 6 ) × b = 100 b = 100 ÷ ( 5 × sq root 6) b = 20 ÷ sq root 6 or 20 × sq root 6 ÷ ( 6) i.e b =10 × sq root 6 ÷ (3) So (a + b + c ) = 5 × sq root 6 + 10 sq root 6 ÷ (3) + 10 sq root 6 Solving we get ( 15 × sq root 6 + 10 × sq root 6 + 30 × sq root 6 ) ÷ ( 3) i.e (55 × sq root 6) ÷( 3) (a +b + c) = (55 sq root 6)÷(3)
@avinashmehrunkar5041 Ай бұрын
Thanks 👍
@LOST80_TOPPED Ай бұрын
:)
@LOST80_TOPPED Ай бұрын
hi chat.
@LOST80_TOPPED Ай бұрын
hi chat
@Shadoxite Ай бұрын
So radians and degrees are polar coordinates? Something like 720 degrees
@RonStark-r8i Ай бұрын
Wow nice explanation about JEE, pls upload part 2
@zetutor Ай бұрын
Will do
@MathSolver-p6i Ай бұрын
Great Video, well explained
@zetutor Ай бұрын
Glad it helped
@steveharry4678 Ай бұрын
GOAT
@zetutor Ай бұрын
Thanks
@charlesmrader 2 ай бұрын
That's the hard way to solve the problem. First make the guess that there is a simple x that solves the problem, simple meaning it's an integer. So factor 360 as 6(10) and factor x^3+4x^2 as x^2(x+4). The answer x=6 is staring you in the face. Now since you have a cubic, you know there might be other solutions. So write the cubic as x^3+4x^2-360 =0 and divide by (x-6). The result it a quadratic equation, which you can solve with the quadratic formula.
@zetutor 2 ай бұрын
That works
@fitnesspoint2006 2 ай бұрын
Likely not good for your lungs shaking those metal filings
@logicalgamerz8291 2 ай бұрын
Heyy that's pretty cool 😂
@zetutor 2 ай бұрын
yep
@xinpingdonohoe3978 2 ай бұрын
Just take 4th roots on both sides. a⁴=(a-1)⁴ a=(a-1)e^(2πni/4) a=(a-1)e^(πni/2) a=e^(πni/2) / (-1+e^(πni/2)) n=0, you get 1/0. It doesn't work, but I guess ∞ is kind of applicable as an extended answer. n=1, you get i/(i-1)=1/2 - i/2 n=2, you get -1/(-1-1)=1/2 n=3, you get -i/(-i-1)=1/2 + i/2
@AayanKumar-s9t 2 ай бұрын
Thanks 👍
@zetutor 2 ай бұрын
Welcome 👍
@mangojulie123 2 ай бұрын
Good one. But I don't think there was any trick there. I think you worked backwards from the answer to arrive at the problem. LOL
@fancyfouchard3491 2 ай бұрын
cool
@Orewa_Artist2 2 ай бұрын
Thanks sir! ❤
@Maxmilian666 2 ай бұрын
0 or 2
@xnx_3609 2 ай бұрын
Multiply everything by i and you find that zi = 1 - z. But zi = z + i and for that reason z = (1 - i)/2
@UNOREBAIXADO. 2 ай бұрын
What? If you multiple by i we get (Z+i).i=(zi).i Zi=Zi²-i²=(Z-1).i² That's not Zi= 1-Z
@Naufal-nf2ok 2 ай бұрын
z=2 i=2
@zetutor 2 ай бұрын
no
@rodbennett 2 ай бұрын
No need for division. Just multiply it out, set the equation equal to 0 by putting all on the left hand side, and then solve the equations for the real and imaginary parts- which are a+b=0 and a-b=1
@Leo-io4bq 2 ай бұрын
I wont even watch the video. Easy z = i = 0
@Mrrrmaaaaaaaa 2 ай бұрын
i=0 ????????? are u fr
@Leo-io4bq 2 ай бұрын
@@Mrrrmaaaaaaaa yes, w.l.o.g. we can assume that, which completes the proof.
@zetutor 2 ай бұрын
Ha ha
@uncannyroaches5933 2 ай бұрын
very funny brother i an laughing on the ground@@Leo-io4bq
@Leo-io4bq 2 ай бұрын
@@uncannyroaches5933 I am glad
@steveharry4678 2 ай бұрын
WoW. Learned a lot. I will take a day to solve
@zetutor 2 ай бұрын
All the best
@Now_Kai 2 ай бұрын
Id jump to see if the same thing would happen to me 😂😂
@zetutor 2 ай бұрын
lol
@unclassifiedclips 2 ай бұрын
Around four friends , Now who is going to pick that ball
@potatochipss1 2 ай бұрын
Magnufficent
@shootertiger6128 2 ай бұрын
INCREÍBLE 😮
@konroh2 2 ай бұрын
The question is how do you go to the intuitive leaps, making a^2 into 6a^2 - 5a^2? This is where it's a problem.
@zetutor 2 ай бұрын
There are multiple ways to factor a cubic equation. The one we used in this video, it's like a trial-and-error process
@konroh2 2 ай бұрын
@@zetutor Thanks, I can appreciate the beauty of this, but it seems harder than seeing cubes and squares of numbers. Trial and error just finding something that can be factored out like a-5. Are other ways more complex math?
@SpongeSven 2 ай бұрын
also, if you put all the numbers of a line next to each other, you have the number equal to 11 to the power of that line (if you count the first 1 as line 0), i found this out by accident and idk if any1 else has noticed
@warrenwelch6295 2 ай бұрын
🎉🎉
@whataheapofpish 3 ай бұрын
This is wonderful - why does this happen? What does it tell us about the universe?
@zetutor 2 ай бұрын
Pascal's Triangle is used for binomial coefficients, combinations, probability calculations, and contains interesting mathematical patterns.
@Ziad3195 2 ай бұрын
This law was not synthesised by Pascal. It was synthesised centuries before by the Persians and the Chinese.
@spaceymilk 2 ай бұрын
@@Ziad3195also the Indians
@Ziad3195 2 ай бұрын
@@spaceymilk Indeed. In fact, most Mathematical theorems were synthesised in the Islamicate World, like the Middle East, Al Andalus, even Sicily and other regions under Muslim/Arab rule, as well as Asian regions, like India and China, centuries before Western mathematicians ever synthesised them, yet Westerners take the credit. It's really quite a shame.
@darkbadger3855 3 ай бұрын
Me just solving it in 15 secs. by hit and trial 6^3-5^3=91.
@LondonBusThrashes 2 ай бұрын
I said 4 and -3 or 3 and -4
@alvindzaki6594 3 ай бұрын
Mind boggling
@MedAb8 3 ай бұрын
"xy can be positew or negatew"
@zetutor 2 ай бұрын
true
@craig2828 3 ай бұрын
Ok…, but why do you use piss?
@chrisnorton2356 3 ай бұрын
Density. Not density and gravity. Just density.
@TRVladdy 3 ай бұрын
Congratulations. you managed to say the exact same sentence 5 times using slightly different wording.
@themelancholyofgay3543 3 ай бұрын
fr
@myfav2178 3 ай бұрын
Its called atmospheric pressure in an open system. But, when there is a closed system, the levels will depend on the local pressure-volume-temperature, P-V-T) conditions explained by Boyl's Law. And thers is no Paradox. Just open and closed systems. Aaand I think our universe is a jackfruit. Your take?
@iRemainNameless 3 ай бұрын
Density and pressure. Not gravity.
@alllibtardsmustdie 3 ай бұрын
that was amazing
@NielsSHansen 3 ай бұрын
Who has ever thought the pressure of a fluid was influenced by the shape of a container????