Sir You take minimum to maximum..... maximum to minimum 🤔🤔🤔
@prajwalgowda97736 ай бұрын
Sir minimum energy is 270 . but you take 295 ? how sir posible
@resueltoalma47737 ай бұрын
thank you❤
@michaelthomasrex7 ай бұрын
You're welcome 😊
@nsulwachugambuli70017 ай бұрын
What about to draw a failure envelope and estimate the coefficient of friction for the failure
@nsulwachugambuli70017 ай бұрын
Your the great thank you
@michaelthomasrex7 ай бұрын
Thanks for the compliment
@richbob58 ай бұрын
For the radius: R=87.32 For the Max shear stress: τmax=87.32MPa For principal stresses: σmin=82.32MPa and σmax=92.32MPa For the angle at which we have to rotate to get to get the point A&B at in the horizontal plane is: 2θp=66.37° And the orientation of the principal plane is: θp=33.19° Can someone confirm these answers for me?
@michaelthomasrex7 ай бұрын
The answer is available in the description of the video
@manikandaprabhug44718 ай бұрын
Thankyou Sir
@michaelthomasrex7 ай бұрын
You are welcome
@abhishekdhabarde82148 ай бұрын
Thank you so much sir 🙏 Nice explanation 👍
@michaelthomasrex7 ай бұрын
Most welcome
@edn86248 ай бұрын
Thank you so much
@michaelthomasrex7 ай бұрын
You're most welcome
@sadhvikbutti.sadhvik29878 ай бұрын
Sir Ra+Rb=48+45=93 But u consider 48+40=88
@michaelthomasrex7 ай бұрын
"There's a typo in the question; please consider replacing '45' with '40'."
I like the video and I I want to know where to find more videos for different exercises
@michaelthomasrex7 ай бұрын
I will upload it soon
@abdulsamad-tr1jw9 ай бұрын
Why the Mohor circle the y components of central of circle is taken is zero And why the x component is not taken is zero
@michaelthomasrex9 ай бұрын
When considering the Mohr circle for stress analysis, it's essential to understand the coordinate system used. Typically, the x-axis represents the normal stress, and the y-axis represents the shear stress. In the center of mohr's circle, shear stress is zero because it represents the stress state where the maximum and minimum principal stresses act on the same plane
@HassanIftikhar-q6d9 ай бұрын
Man you make a mistake as in mohr circle y axis in 3 or 4 block must be +ve while -ve in 1 and 2 block
@michaelthomasrex9 ай бұрын
There is no thumb rule in selecting positive and negative axes, so it is not a mistake. You can choose as you wish. However, the x-axis represents normal stress, and the y-axis represents shear stress
@imanayt_j10 ай бұрын
You have my heart ❤️ Thank you so so much
@michaelthomasrex9 ай бұрын
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@Firas.710 ай бұрын
Perfect ❤
@michaelthomasrex9 ай бұрын
Thanks for watching. Kindly subscribe to the channel.
@Firas.78 ай бұрын
@@michaelthomasrex ok
@farismashaqbah579111 ай бұрын
👍🇯🇴
@michaelthomasrex9 ай бұрын
Thanks for watching. Kindly subscribe to the channel.
@galibshaikh363211 ай бұрын
Subscribing because of your this wonderful explanation!!! Thanks sir🫂
@michaelthomasrex10 ай бұрын
Thanks and welcome
@ArifinIndaka11 ай бұрын
Tutor?
@michaelthomasrex9 ай бұрын
I will update it soon. Kindly subscribe to the channel.
@rakshithkumarrakshithkumar-h6f11 ай бұрын
❤
@michaelthomasrex9 ай бұрын
Thanks for watching. Kindly subscribe to the channel.
@sundaresanmurali7949 Жыл бұрын
Thanks to my guru.
@michaelthomasrex Жыл бұрын
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@AbhishekKumar-vf5ep Жыл бұрын
Sir kindly help..how to give proper constraints in case of both end fixed??
@michaelthomasrex9 ай бұрын
I will post the video soon. Kindly subscribe to the channel.
@reinahadassa Жыл бұрын
Sir, I think the sign convention for Normal Stress is wrong. The tension should be negative and compression is positive.
@michaelthomasrex Жыл бұрын
Any Sign convention is correct. However, you have to maintain it throughout the problem. The answer will not change.
@TroyAlfred-li6rf Жыл бұрын
This video was so helpful. However i just wanna confirm my answers. For the radius: R=83.82 For the Max shear stress: τmax=83.82MPa For principal stresses: σmin=78.82MPa and σmax=88.82MPa For the angle at which we have to rotate to get to get the point A&B at in the horizontal plane is: 2θp=72.64° And the orientation of the principal plane is: θp=36.32° Can someone confirm these answers for me?.
@michaelthomasrex Жыл бұрын
Thanks for watching. The answers are correct.
@LebogangMnisi-v2j9 ай бұрын
Help I'm getting 87,32 as my R 😭
@raoneialves1138 Жыл бұрын
Excellent..
@michaelthomasrex Жыл бұрын
Keep watching! Kindly subscribe to the channel.
@Gokhulkumarkashyap01 Жыл бұрын
Thank you sir
@michaelthomasrex Жыл бұрын
Keep watching. Kindly subscribe to the channel 🙂
@chelluboinasaivamsi1757 Жыл бұрын
Nice explanation sir
@michaelthomasrex Жыл бұрын
Keep watching. Kindly subscribe to the channel 🙂
@md.alimalrabby2713 Жыл бұрын
mind blowing teaching
@michaelthomasrex Жыл бұрын
Keep watching. Kindly subscribe to the channel
@shukurullomeliboyev2004 Жыл бұрын
thank you a lot, you made it very easy and understandable, thanks again😊👌🇺🇿
@michaelthomasrex Жыл бұрын
You are welcome! Kindly subscribe to the channel.
@zirotube123 Жыл бұрын
isnt it counterclockwise positive and clockwise negetive???
@michaelthomasrex Жыл бұрын
The clockwise rotation created by the shear forces at any face is always positive. Similarly, the counter clockwise rotation created by the shear forces at any face is always negative.
@PereraArunodha Жыл бұрын
Perfect sir😊❤
@michaelthomasrex Жыл бұрын
Keep watching. Kindly subscribe to the channel.
@DerrickTenkorang Жыл бұрын
Can i compare answers for the 2nd question
@michaelthomasrex Жыл бұрын
The principal stresses: 88.8 Mpa & 78.8 Mpa Position of Principal Plane :36.3 degree (CCW)
@talha9276 Жыл бұрын
Nice video to watch before exam
@michaelthomasrex Жыл бұрын
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@godwinayamga9156 Жыл бұрын
Please how can I find the magnitude and direction of principal stresses?
@michaelthomasrex Жыл бұрын
The magnitude of the principal stresses are the distance of extreme stress values from the centre to the points where the circle intersects the horizontal axis. Please refer the video in time line 17.52 for orientation of principal plane.
@sj4s Жыл бұрын
Nice.Informative
@michaelthomasrex Жыл бұрын
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@freemanfootball647 Жыл бұрын
omega r(sintheta+ cos2theta/n)=0 why remain ncostheta+cos2theta =0, where omega r ??
@zohainapasandalan4324 Жыл бұрын
Thank you so much for the precise and clear explanation sir❤
@michaelthomasrex Жыл бұрын
You are most welcome. Kindly subscribe to the channel.
@muhdlufy6185 Жыл бұрын
VERYVERY GOODSIR,GOOD TO KNOW SOMEONE LIKE U EXISTED ❤
@michaelthomasrex Жыл бұрын
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@Rbsk25 Жыл бұрын
Thanks Sir for this video and way of explanation
@michaelthomasrex Жыл бұрын
Most welcome.kindly subscribe to the channel.
@NAGUMURALA Жыл бұрын
Sir I didn't understand why theeta is only pi/2 in tmax
@michaelthomasrex Жыл бұрын
The maximum torque is obtained at exactly middle of the power stroke. Hence the angle is pi/2. The total angle covered during the power stroke is pi.
@MechTechSimulations Жыл бұрын
Nicely explained professor!
@michaelthomasrex Жыл бұрын
Many thanks!
@mdistaz2002 Жыл бұрын
It is so simply way to explain a a lot of thanks sir
@michaelthomasrex Жыл бұрын
You are most welcome. Kindly subscribe to the channel.
@DadaAdebayo-nf9sg Жыл бұрын
I've been watching series of videos on this particular Mohr's circle and I'd say this is the best so far!!! You're a great teacher sir!❤❤❤
@michaelthomasrex Жыл бұрын
You're very welcome! Kindly subscribe to the channel and share it with your friends.
@Khaǔ-Kanǎn Жыл бұрын
For me too.🎉🎉🎉
@mr__xeditorgaming7062 Жыл бұрын
I think I found one mistake, in 6(circle) the x distance you write 1 , while in drawing it's 10 cm , please ans me ,may be i am wrong !
@michaelthomasrex Жыл бұрын
It is mentioned as 1.0 cm in the drawing. I think, the dot may be not visible. Thanks for the comments. kindly subscribe to the channel and share the video lecture with your friends.
@avishkar4131 Жыл бұрын
You have not converted kg/mm2 into N/mm2 by multiplying by 9.81 Except that everything is perfect
@michaelthomasrex Жыл бұрын
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@axk7516 Жыл бұрын
Good expalination brother, easy to understand❤
@michaelthomasrex Жыл бұрын
You are welcome. Kindly subscribe to the channel and share the video lecture with your friends.
@Epic_multiverse Жыл бұрын
Nice explanation. While orientation, how did you recognised max and min force will be along y and x axis
@michaelthomasrex Жыл бұрын
In this problem, the point A denotes the X face. When is rotated to the horizontal in CCW direction, we have got principal stresses. So the intersection point is 9.66 Mpa. Hence the 9.66 Mpa is considered along X axis while orienting principal stresses. Similarly, the point B denotes the Y face. When is rotated to the horizontal in CCW direction, we have got principal stresses. So the intersection point is 13.66 Mpa. Hence the 13.66 Mpa is considered along Y axis while orienting principal stresses. Hence, the maximum and minimum just represent the numerically maximum and minimum value among principal stresses.
@sundaramsingh752 Жыл бұрын
Amazing explanation sir , thank you so much Sir for a good video.
@michaelthomasrex Жыл бұрын
You are welcome. Kindly subscribe to the channel and share the video lecture with your friends.
@tgshamimamelin1621 Жыл бұрын
Where can i check my ans
@michaelthomasrex Жыл бұрын
Thanks for the comment. It is now available in the description.
@michaelthomasrex Жыл бұрын
The principal stresses: 88.8 Mpa & 78.8 Mpa Position of Principal Plane :36.3 degree (CCW)