HUGE SHOUTOUT TO YOU! HELPED ME ON THIS ONE!!!!!!!!!!!!!!!!!
@miyamotomusashi45564 ай бұрын
Amazing video! Thank you.
@chahlabedroh47035 ай бұрын
ty sir
@JarrodKapeluschnik5 ай бұрын
amazing video - this series has helped me so much!!🇿🇦
@FomekongJean-kk6hl6 ай бұрын
Thanks very much ✊🙏
@johnaiii12816 ай бұрын
finally someone taught me how to integrate the normal bell curve, really thanks with all the guided calculations
@yessethiopia77497 ай бұрын
Thank you for sharing
@Mrtnimn7 ай бұрын
For the probability of the home team winning with atleast one goal = 0.4755 And For the probability of the away team winning with atleast one goal = 0.3372 I definitely think I got the right one here💫
@battleshout647 ай бұрын
I love you
@JustGoatthings1018 ай бұрын
i got 0.2912 is that right?
@DarkKittens1235 ай бұрын
no its 0.4756
@alimortadahoumani11348 ай бұрын
wow very nice
@alyaqistina5979 ай бұрын
thankyou. very clear explanation
@s.mugundan9 ай бұрын
super
@ThanhThuy-wb6lm9 ай бұрын
so helpful, thank you 🙏🏼 😊
@rocklemillion80419 ай бұрын
Is the reason that we can simply state that Q=1 rather than +-1 because e raised to a power never creates a negative number?
@janng318011 ай бұрын
Thank you so much!!!!!
@hypergiant03 Жыл бұрын
Tysm sir for this video, it was really helpful.
@maheswaraanubawawidiatna3022 Жыл бұрын
Vid: 🎶🎶🎶🎶🎶🎶 My brain: 📈📈📈
@Bibletalkswithsamu Жыл бұрын
ohn has six 1 rand coins, three 2 rand coins and two 5 rand coin and wishes to buy another item that costs 10 rand which is sold by the vending machine. In how many distinct ways may he correctly insert a total of 10 rand into the vending machine for purposes of buying the item (given that the machine does not give change)?
@aleksandarjankovski6542 Жыл бұрын
BRILLIANT!
@SIRMAPANDAONLINE Жыл бұрын
Good work, Sir 👏
@deepakoct28 Жыл бұрын
Can't wrap my head around the overall volume being the area of one of the equally partitioned regions :)
@ashenafibelete4013 Жыл бұрын
Thank you for sharing
@jonsnow3513 Жыл бұрын
thank you sir
@horiuchiworld Жыл бұрын
1. I used a longer way but I still want to share it On-time = 0.40 Satisfactory = 0.50 Neither = 0.25 Let On-time as A and Satisfactory as B and Neither as the complement of AUB ((AUB)'). We will use this Identity of the Sample Space: P(S) = P(AUB) + P((AUB)') By using the identity of the union of A and B, P(S) = P(A) + P(B) - P(A∩B) + P((AUB)') We can now plug-in the three given values, P(S) = 0.40 + 0,50 - P(A∩B) + 0.25 Since P(S) = 1, 1 = 0.40 + 0,50 - P(A∩B) + 0.25 Finally, P(A∩B) = 0.40 + 0,50 + 0.25 -1 P(A∩B) = 0.15
@DavidWittler Жыл бұрын
I found the same answer to the last question through a more convoluted way. P(CUB/F')=P(CUB)P(F'/CUB)/Law of total probability for F' well I figured C and B were disjoint so P(CUB)= P(C)+P(B), but the hard part was finding P(F'/CUB). P(F'/CUB) is the probability that the component didn't fail out of the class C or B components. given earlier P(CUB)= P(C)+P(B)= .12+.18= .3 If .9 of Components B worked and .82 of components C worked (given by P(F'/B)=1-P(F/B) and P(F'/C)=1-P(F/B)) and they are disjoint one could take the average of the working components in class B and C. Class C and B take up .3 of the sample space, and class B takes up .18 of that .3, while C takes up .12 of that .3. So class B is .6 from sample BUC (18/30) and class C is .4 of BUC (12/30). Taking a weighted average of (.9x.6)+(.82x.4) finds the average probability that Components didn't fail out of class C or B. P(F'/CUB)= (.9x.6)+(.82x.4) = .868. Plugging that back in to the original equation finds 0.2751
@hpicpr8469 Жыл бұрын
This is a true beauty. Thank you and may this video live from 0 to infinity!
@therankingworld7627 Жыл бұрын
i swear this is a stupid video
@bigbarry8343 Жыл бұрын
Great videos but i am getting annoying commercials every 2 minutes.
@jrtthamasha7306 Жыл бұрын
thankyou
@humavocado5614 Жыл бұрын
Thank you very much
@firstkaransingh Жыл бұрын
Great expectation 👍
@mansonvcdl Жыл бұрын
Thanks! Very clear and concise. Really appreciate it!
@elisab.8266 Жыл бұрын
but how can I install a package that I downloaded on my computer? I've got R version 4.2.2 and R studio and my teacher had send me the package "rmf" to install but I don't know how to install it
@wendyekole3564 Жыл бұрын
Thank you for starting with an example
@twilight1176 Жыл бұрын
LIFE SAVER
@rupalimohanty9920 Жыл бұрын
𝓣𝓺𝓼
@tejasdeo1749 Жыл бұрын
Where are the answers to the last 2 exercise questions?
@ling6701 Жыл бұрын
First time I understand covariance, thanks.
@anweshbhattacharyya7763 Жыл бұрын
Awesome 😊🔥👌👍🔥❤️❤️
@Aaridesigns_shorts Жыл бұрын
ggplot2 is not available for 4.2.2 version of r, so what we have to do?,plzz solve my problem 😢