2 жыл бұрын
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@stevetsirbas Ай бұрын
Excellent work, thanks for your efforts!
@KHENISIR Ай бұрын
Thank you so much sir...
@sandy3781 Ай бұрын
Sir plz explain in hindi ......aapka English me samjh nhi aa rha h
@KHENISIR Ай бұрын
Dear friend Will soon upload explanation in hindi or try to dubbed surely.... Thanks for suggestion
@mrhurricane8346 Ай бұрын
Thanks sir
@kennethnyakinye1351 Ай бұрын
I don't understand how you get ordinates on the maximum bending moment 3.6,4.8,4.2 and 3.4 and also maximum shear ordinates 0.13,.0.23,0.3
@KHENISIR Ай бұрын
Dear friend I used Similar triangle rule... For Bending moment.... Peak value 4.8 or say section BM ordinate value is as per derivation which is (L-x) *x/L After that as per location For left riangle use.... At 8 m value is 4.8 than at 6 m how much value??? Similarly for all ordinate, we can find values using similar triangles... Hope your query will resolve now
@kankiritharan3418 2 ай бұрын
Thank you sir
@KHENISIR 2 ай бұрын
Always welcome..... Hope you like learning
@theequeenlulu 2 ай бұрын
Thank you so much 🙏🏾
@amanmirza1029 3 ай бұрын
Sir what's the steps for finding SHEAR STRENGTH OF BOLT ?? Please help
@KHENISIR 3 ай бұрын
Dear Aman Vdsb and Vdsf both are the equation for the Shear strength But as per Bolt Value or say Bolt strength We have to taken in account Vdpb Value In short Shear strength is similar to bolt value
@jobotieno4649 3 ай бұрын
The My =Pey
@KHENISIR 3 ай бұрын
Dear.... As per Moment defination It is multiplication of Effective Load and perpendicular distance from CG of load to the point of application of load While you find Moment w.r.to y axis Then perpendicular distance must be in X axis
@AnjaliMeshram-yr2ve 3 ай бұрын
Sir aapme 6 baad 5.81 , 4.31, kaise nikale ho please tell me
@KHENISIR 3 ай бұрын
Dear Friend Its Similar Triangle Rule Man lo ke Jese kisime 10m per ordinate value 40 hai to 3.8m par kitana hoga?? Ye rule lagake sare ordinate find kiya hua hai I hope you got the answer
@smspyderyt4526 3 ай бұрын
Thank you so much sir❤
@sindhuduba3961 4 ай бұрын
Sir both delta v are negative how to knowing which load is taking at c
@KHENISIR 4 ай бұрын
Dear Friend.... Its trial method We have to start from first or last load of given train load as trial When delta V value changes its sign i.e negative to positive or vice versa... We have to take that trial load on section Hope you understand...
@Coloursss27 4 ай бұрын
thankyou so much sir
@KHENISIR 4 ай бұрын
Most welcome dear
@ajaypatel1834 4 ай бұрын
Nice explanation sr
@KHENISIR 4 ай бұрын
Happy you like that.... Keep learning
@civil.engr2018 4 ай бұрын
.5*6*22=?
@ankurchaubey2951 6 ай бұрын
❤❤❤
@satazer5824 7 ай бұрын
Thank you for the video sir, One question, if I asked to find the radius when the tensile stress is zero in any place, how it should be?
@satazer5824 7 ай бұрын
Thank you so much! Really helps.
@KHENISIR 7 ай бұрын
Thanks....happy you like this....keep learning dear.
@dongliu7739 8 ай бұрын
The FEM for ba should be (3/16)*P*L, for bc should be wL^2/8
@KHENISIR 8 ай бұрын
Dear Friend, if propped cantilever beam is given than final moment at fixed end (ie Ma) will be (3/16)*p*l and for simply supported beam loaded with UDL over entire span, Max moment at centre of the span is wl^2/8... For Moment Distribution, each span is assumed as fixed for analysis purpose and the end moment is asuumed as Fixed End Moment (FEM) which are as described in example first step... Hope your doubt is clear now... Keep Learning
@sriram-c-0682 8 ай бұрын
Thank you sir ❤
@KHENISIR 8 ай бұрын
Most welcome dear ❤️
@sriram-c-0682 8 ай бұрын
Thank you sir ❤
@KHENISIR 8 ай бұрын
Most welcome dear 💗
@sriram-c-0682 8 ай бұрын
Thank you sir ❤
@KHENISIR 8 ай бұрын
Most welcome dear 💓
@sriram-c-0682 8 ай бұрын
Thank you sir ❤
@KHENISIR 8 ай бұрын
Most welcome
@gnidnoeled786 9 ай бұрын
Let's say we have a moving loads crossing that beam. The wheel loads are 45kN, 25kN and 20kN. 45 and 25 is 4 m apart while 25 and 20 is 1.5 m apart. 20kN is the front wheel load of the truck. How shall we do it to get the max shear and moment at the midpoint of the beam?
@KHENISIR 9 ай бұрын
Dear friend... Kindly provide your email id so that I can drop solution of your mentioned example...also need span value which is missing...
@duraimurugan2998 9 ай бұрын
Sir explain how sigma bxx is negative and sigma byy is positive waiting for your reply thanks..
@KHENISIR 9 ай бұрын
Dear Friend.... Eccentric Stress will be positive or negative as per eccentric distance and its quadrant.... For example, during calculation of Sigma Bxx, we have to consider ey value and if ey distance is in negative quadrant then we have to consider sigma bxx as negative.... hope I can explain your query....
@wansanbansamshrek991 10 ай бұрын
Sir can you teach us how to draw ild for three hinged arch also.? Your explanation for ild for beam is very understandable..🙏🏻
@KHENISIR 10 ай бұрын
Dear Friend Will put the topic of ILD for arch in pipeline Will definitely cover in future as soon as possible Thanks for the suggestions 🙂
@wansanbansamshrek991 10 ай бұрын
Can you explain if load 20 and 15 cannot interchange (ie 20 kn load always lead)
@KHENISIR 10 ай бұрын
Dear Friend.... If 20kN load is always lead it means load position is fixed.... For such case Calculation steps are same as explained in this example but we have to take right side first load as 20kN and succeed load or say second load as 15kN Hope you understand the concept..😀
@wansanbansamshrek991 10 ай бұрын
@@KHENISIR thank you so much sir🙏🏻
@KHENISIR 9 ай бұрын
Welcome Dear friend 😊
@niranjan3869 10 ай бұрын
Great video! <3
@KHENISIR 10 ай бұрын
Happy you like it...
@parthivrathod5669 11 ай бұрын
Next level and easiest way
@KHENISIR 11 ай бұрын
Happy you like the method.... Keep learning
@parthivrathod5669 11 ай бұрын
Well done sir
@KHENISIR 11 ай бұрын
Thank you for appreciating dear Parthiv
@parthivrathod5669 11 ай бұрын
Really nice sir
@KHENISIR 10 ай бұрын
Keep watching
@parthivrathod5669 11 ай бұрын
Great sir
@svmexplainz 11 ай бұрын
Sir 4 ki jagah pe 1/4 ayega
@KHENISIR 11 ай бұрын
Dear Friend Its 4 not 1/4 As its 1/4 is iin denomination of 1 So actually its 4 in nominator
@anujgarg8002 Жыл бұрын
Sir isme mass kahi pr bhi nhi ayega kya ...............how unit will satisfy
@KHENISIR Жыл бұрын
Dear Anurag ... Its for a 2D element And Moment of Inertia means Second moment of area... hence mass is not calculated
@KHENISIR Жыл бұрын
And unit of Moment of Inertia is Unit^4
@MotivaMillionaire2.0 Жыл бұрын
Really very nice explanation sir, Thanks for the video ❤
@KHENISIR Жыл бұрын
Thank you for your great appraisal 🙏
@user-iq4il1kz1b Жыл бұрын
if no. of bolts required are 5 then we have to take it as 6 bolts and put 3 bolts on one plate and 3 bolts on another , by your detailing its shown that you put total of 10 bolts not 5 bolts. do clarify
@KHENISIR Жыл бұрын
Dear Friend During calculation, if anyone consider bolt in double shear or load of both plates and you get 5 bolts then have to use total 6 bolt (3 in each) But during calculation of this example, its taken as single shear as well only one plate load, so total 5 nos are required for only 1 plate hence total 10 nos of bolts ( 5 in each) is provided Hope you got an answer now.....
@gaurigadgil5966 Жыл бұрын
Will the second moment of inertia formula be same for inverted triangle?
@KHENISIR Жыл бұрын
Yes Its same as Centre of gravity never changed either you orient it in any direction
@navneetumariya5532 Жыл бұрын
Thank you sir 😊
@fun_seekers Жыл бұрын
How to find the cg distance??
@KHENISIR Жыл бұрын
Dear friends.... CG distances for predefined shapes are known.... For that kindly visit CENTRE OF GRAVITY playlist
@Paulinekeshi Жыл бұрын
Where does -M come from? Why does M negate?
@KHENISIR Жыл бұрын
Dear friend.... As per Euler's theory The moment is taken as negative due to the sign convention assumed by Euler.... And M means the sectional Moment on the span as per the method
@M.Hassan19 Жыл бұрын
Easily explained. Thank you sir
@KHENISIR Жыл бұрын
You are welcome
@pankajsinghrana8144 Жыл бұрын
Thannnkuu
@-IndraneelMitra Жыл бұрын
It should be 3EI/4L
@KHENISIR Жыл бұрын
Dear Indraneel.... If you consider relative factors then its right but if you consider columns individual distribution factor than its as explained .. hope you got the point
@abhishekrai7008 Жыл бұрын
sir in the question u have taken the load 15 but in diagram u have taken load as 30 the video is very good but I thought to tell u this
@KHENISIR Жыл бұрын
Dear Abhishek.... UDL load intensity is taken as 30kN/m and in moment its (30x^2)/2 so its 15x^2
@riachisimba Жыл бұрын
Is possible for you to show an example with a continuous with an overhang cantilever and 2 pin supports please
@KHENISIR Жыл бұрын
Definitely Ms Ria.....lecture of the mentioned points will be covered soon in future plan
@patelheri1091 Жыл бұрын
For Parabola c.g. distance = 3/4
@KHENISIR Жыл бұрын
Dear Heri.... Its symmetrical parabola... Hence CG is at axis of symmetry... If not symmetrical than its 3/4 or 5/8 as per parabolic curve
@kushalwankhede8575 Жыл бұрын
Sir your Zxx and Zyy values are wrong, Zxx= 4.5*10^6 and Zyy= 36*10^6 But my concept are clear by your video sir Thanks
@KHENISIR Жыл бұрын
Thank you Dear Kushal....it's already written in a description about value.... Keep learning
@zacharysagwemagaregisuboy7651 9 ай бұрын
Exactly you have seen what I have seen
@KHENISIR 9 ай бұрын
Dear Friends It has been mentioned that in description about that Depending upon value and its by mistake interchanged..... But happy for you all that you got the concept
@qinisohlabangane3675 Жыл бұрын
thank you ✔✔✔✔
@KHENISIR Жыл бұрын
Welcome 😊
@pvt765 Жыл бұрын
In second triangle...??? Why you take cg distance 1/3×2....it is 2/3×2 hoga....???
@KHENISIR Жыл бұрын
Dear Friend..... As per rules the CG distance for traingle from apex is 2/3 and its 1/3 of distance from side...... If you go through this, you will get 1/3 of distance for 2nd traingle...
@fh8kk3tq6y Жыл бұрын
Thank you sir 😊❤
@KHENISIR Жыл бұрын
Most welcome 😊
@parthivrathod5669 Жыл бұрын
Really great sir