Structural Analysis

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@samarjyoti-ray Ай бұрын

21:29

@mani-qd7sl 3 ай бұрын

can anyone know Fik calculation ???

@aerodynamico6427 3 ай бұрын

What a TERRIBLE example of IIT standard teaching! Simply HORRIBLE!!!!!!

@aerodynamico6427 3 ай бұрын

Confusing bending moment with shear force again and again at 16:00 onward is CRIMINAL in a teaching class.

@aerodynamico6427 3 ай бұрын

Not "fishing stick", but "fishing rod." Not "clothe hanging rod", but "clothesline". If you are importing foreign pictures, at least use the correct nomenclature!

@aerodynamico6427 3 ай бұрын

Your cursor is flying all over the place and is EXTREMELY irritating and distractive.

@aerodynamico6427 3 ай бұрын

"If you, if you, if you, if you, if you...." Yes. yes, yes, we heard it! STOP!

@apidennalive 4 ай бұрын

Best teacher

@komal-ql1qm 4 ай бұрын

How to find Fik anyone?

@kishlayjha1561 5 ай бұрын

Values may be wrong in rare cases but concept is crystal clear ❤.

@bilalpt8526 5 ай бұрын

Why you have not considered the rxn (By) of internal hinge for further calculations from 13:40 onwards, actually (By) is not equal to Zero.

@hariharanrangarajan657 5 ай бұрын

Your anological explanations are very good and easily understandable sir. Thank you

@Shivanshyadav1582 6 ай бұрын

Excellent lecture! nobody taught this!

@ravibhosle8478 6 ай бұрын

in in in in in in in...

@bhooshan25 7 ай бұрын

Content is great but volume is bit low

@abbashusainkhan8249 7 ай бұрын

29:17 max bm in bc will be 12

@abbashusainkhan8249 7 ай бұрын

Delta will be positive

@kumawatnikhil 7 ай бұрын

Its very helpful for me i like to learn with teachers like ❤u always enjoy how you explain all concepts 🥰

@aerodynamico6427 8 ай бұрын

"...they will reach, ...they will reach..." Why are you repeating yourself?

@Chaman47858 8 ай бұрын

I have got reappear in structure analysis -1 and watching this....loved so much ur lectures..❤❤❤loves alot sir ....

@moviemangaworld 9 ай бұрын

Why Fde is not considered ?

@arslangul6872 10 ай бұрын

What a beautiful teacher.

@MOTIVATESSOMEONE 10 ай бұрын

Bro which cllg

@mukassarnajeeb7608 Жыл бұрын

😊amazing explanation

@gauharmaqubool7208 Жыл бұрын

VERY LUCID EXPLANATION! SIR

@factz8633 Жыл бұрын

aagae ka toh padhao displacement triangle non symmetric systm

@kishlayjha1561 Жыл бұрын

Thanks a lot sir.

@kishlayjha1561 Жыл бұрын

Dear nptel team member FEM calculated by sir is seriously wrong. It should be Mab = -Mba =24 Knm And you people never respond

@kishlayjha1561 Жыл бұрын

Dear nptel team i have mailed him also related to the query of BMD drawn by him, the BMD of members AB and CD should not be cross it should be straight according to values.

@kishlayjha1561 Жыл бұрын

If i have to do the same i will do but atleast there should be a explanation for that Please ask sir to reply me.

@abshaw1978 Жыл бұрын

The sign convention for the Bending moment is used as Clockwise positive (+) and Anti-clockwise negative (-). Based on this sign convention all algebraic operations are performed. However, BMD is drawn based on the sense of the bending moment. It means whether the bending moment is sagging or hogging. In the BMD here, at A, B, C, and D the moments are shown on the sides where tension is developed in the member.

@kishlayjha1561 5 ай бұрын

Thank you sir I searched that email again yesterday and got the answer. Great explanation❤️.

@kishlayjha1561 Жыл бұрын

k(BC) should be 3/10 EI.

@kunalchandrakar4741 Жыл бұрын

What are the best books recommended for learning structural analysis ?

@kishlayjha1561 Жыл бұрын

Dear nptel team please resolve my query ask sir about this. He is not replying in mails given by him earlier also.

@kishlayjha1561 Жыл бұрын

Dear sir, At 22:28 The BMD of problem 1 why are you making AB and CD cross diagram according to values it should be straight.

@Northstar66 Жыл бұрын

Thank you Sir

@Northstar66 Жыл бұрын

Thank you so much Sir

@Northstar66 Жыл бұрын

Thank you sir

@Shivanshyadav1582 Жыл бұрын

Very awesome teaching

@wa8609 Жыл бұрын

Super,🔥🔥

@shivamsharanlall672 Жыл бұрын

Wherever 3EI/L is used as a stiffness factor at the pinned joint, the carried over factor should be zero at the far end of the same span. This is because the far end contains the pinned joint not a fixed joint. Thus, C(BC)= 0

@shivamsharanlall672 Жыл бұрын

Although the moments obtained are very close.