this is insecure to your facebook account cuz we dont know what facebook scraper libariry doing behind scenec

whyyy do you speak sometimes with another language!!!!!! and at the most critical moments when you explain what is the violation!!!!!!! a big disappointment.. I liked your explanation

Is there no option to TYPE in your equation instead of drawing it? For instance, it's difficult to fit the expression y=((cos(x^2)+x))+ln(x) on my phone's screen. It would fit if I could type it, however.

Working ?

Thanks for your video. My husband and I were trying integrals with no luck and then found your video!

..beautiful

.beautiful

..always a joy, to learn .to.be amazed..from Robols ..thnq

It’s unable to give Ogive graph

I did everything to the letter and I got 'comments saved successfully' but nothing was saved and made the comments max = 500 only with a page with over 5k comments

For currency, you can write USD 1 in EUR = to override the default currency

É uma pena que não tenha em português Brasileiro.

Since new update, 3:03 I cannot calculate compound interest by simply hitting the = over and over, what is an easy way to show this year by year?

Where r the solutions provided..

Thanks!! I didn´t know all of this and no one explain it

thats a question from RUET 11-12 session

🎱

We'll information good 😅

Solution: ∫ln(1+x²)*dx = ∫ln(1+x²)*1*dx = ------------------------------------ Solution by partial integration: Partial integration can be derived from the product rule of differential calculus. The product rule of differential calculus states: (u*v)’ = u’*v+u*v’ |-u’*v ⟹ (u*v)’-u’*v = u*v’ ⟹ u*v’ = (u*v)’-u’*v |∫() ⟹ ∫u*v’*dx = u*v-∫u’*v*dx ------------------------------------ = ln(1+x²)*x-2*∫x²/(1+x²)*dx = ln(1+x²)*x-2*∫(1+x²-1)/(1+x²)*dx = ln(1+x²)*x-2*[∫(1+x²)/(1+x²)*dx-∫1/(1+x²)*dx] = ln(1+x²)*x-2*[∫dx-∫1/(1+x²)*dx] = ln(1+x²)*x-2x+2*arctan(x)+C Checking the result by deriving: [ln(1+x²)*x-2x+2*arctan(x)+C]’ = 2x²/(1+x²)+ln(1+x²)-2+2*1/(1+x²) = (2x²+2)/(1+x²)+ln(1+x²)-2 = 2*(x²+1)/(1+x²)+ln(1+x²)-2 = 2+ln(1+x²)-2 = ln(1+x²) everything okay!

Thanks!!

You could also put 𝑢=cos𝜃 it helps us to evaluate the integral ∫₀¹√1−𝑢² d𝑢, what do you think about this idea?

Your solution is simple and nice at the same time, thanks for that.

How long until we can't detect AI at work in all this?

interesting integral, unbearable voice

thanks

Thanks, Bro! I wasn't understand about graphics, but now I'm a new man.

This is why you have to master algebraic techniques because some problems like these do have 90% of algebra manipulation and just 10% of calculus. Thanks For the problem, its cool.

Very informative, presented in an engaging manner!

Split into 2 partial fractions and set x = tan t to get [ 2 / (sec^2 t)^2 - 1 / (sec^2 t) ] (sec^2 t dt) = (2/sec^2 t - 1) dt = (2 cos^2 t - 1) dt = cos 2t dt = sin 2t / 2 + C = sin t cos t + C = tan t / sec^2 t + C = x / (1+x^2) + C. Perhaps this new technique is more useful when f(x) and g(x) are much larger degree polynomials, with or without a minor substitution such as y = x^n

谢谢

a key error on 'comments_full'.

can we use coordinate polar

Bravo et Excellent pour cette solution te merci Mr .

Bravo et Excellent pour cette solution te merci Mr .

Can I use other extension? EditThisCookie is not available anymore

Awesome review of math notes!! Thanks. I noticed that when you entered arcsin(1/2) it reported the answer in radians (not 30 deg). I can't find a way to make it report the answers in degrees initially, is there one or would you then have to convert the radians to degrees and another step?

Finally someone did, what apple could not.... really informative and not like an advert but pure technical review - not easy to find though through a mass of marketing bullshit that does not explain how to type properly ABS to work on this new calc 🤣 Thanks a lot You won't find it on apple tech specs :) - maybe the final screen should be the one to start the whole story or even advertise it.

Hi, Could you post the answer for Problem 3?

Interesting ❤❤

Finally I can understand calc

excellent

doesnt work for me

Hello! Thanks for sharing. I'm doing it but in most of the cases the code print that there are no comments or just extract a low percentage of total :(

Woww i think is so difficult but it turns out it's very simple😮

2:01 What if po Sir ay hindi na-switch ang limits and stayed with a negative 2 multiplier, absolute value lang po ba ang pagkuha ng area?

Or x = tanθ

Nicely illustrated. Your work is top notch 😊

Need more critical problems

Thanks

Great work.❤ Howdo you do voiceovers sir? Using TTS service or recorder service?