Because the MOSFET consumes some of the voltage, in the 100% mode, the output voltage is lower than the input

Is anything else to get 100% output.

No it isn't

@@Skill_DIY Thanks a lot for your nice answer,my bro..

No dear friend

@@Skill_DIY Irfzn 44n mosfet 10k potentiometer जोडकर push बटन, dpdt switch जोडकर और 775 dc मोटर को Reveres or Forwarded कर के दिखाव Bro. *Please Replay*

The 24V input power supply may heat up the MOSFET and damage it, but you can use it in the short term.

input voltage is 12v

Hello , Welcome to "Skill DIY" Channel ! I'm glad the video was helpful.

Hello, About 5 to 10 minutes

Hello, dear friend, thank you for your opinion, but please make the circuit and test it, it will work for sure.

Thank you for your comment !🌺 Welcome to "skill diy" , I hope you enjoy watching the videos.

The way the potentiometer works is that if you connect the middle pin to one place and the side pin to another place and turn the volume, you can change the resistance. And that I only connected the negative line to the middle pin and the side pin of the potentiometer is connected to the MOSFET

Hello, dear friend, make sure you have closed the connections correctly and if there is still a problem, a part may be burnt

Thanks bro ban gya mera Potentiometer dusra tha isilye

Hi dear friend. Yes, at normal currents, the heating produced by the MOSFET is normal, and a heatsink is good.

Hello, dear friend, welcome to the channel ! No, I have built this circuit and tested it for a relatively long time Are you sure you used the mentioned parts and schematic in the video?

@@Skill_DIY yes

Hello, dear friend, welcome to the channel ! Probably, but this circuit is not suitable for this use

same, i want to make a hand fan using tamiya dc motor, but this will burn the potentiometer

Thank you dear friend. I'm very glad that it was useful to you. have a nice day 🌺

@@Skill_DIY it stopped working 😢 nothing is wrong tooo

What motor did you use? Did you put a sink for the MOSFET?

@@Skill_DIY I used a 755

This motor draws a lot of current and you need to use a large heatsink and a fan to cool the MOSFET because if the MOSFET gets too hot it will burn. Also, this circuit should not be used for a long time for this motor.

Hello dear friend. 🌺 Yes, I agree with you. I will try to make more practical things in the future. But in this video, I have made a circuit for testing parts and wires 👇👇 kzbin.info/www/bejne/hnyTdJuPrKyYjK8

You can buy parts from electronic parts stores or Amazon

Hi dear friend! I am very glad that it was useful to you. have a nice day. 🌺🙏

Hello, thank you very much for your comment. have a nice day. 🌺🙏

Hello, dear friend, no, this antenna is very simple and can receive many channels for its size. Please test it and place it on the roof for better results.

Thank you dear friend 😁🌺

I don't recommend

Thanks a lot 🌺 glad it was helpful!

Grazie per il tuo commento, sono felice che questo video ti sia stato utile. 🌺😁

It's an interesting idea😂😂😁

Thank you 🌺 I'm glad it was useful to you✨️

I agree with you, but this circuit is very simple and good for short term use. I have also said this in the description of the video.

Dear friend, for the 12V input, you can put two 5kOhm resistors in series instead of a 10kOhm resistor.

Yes, I agree with you. 💯 Thank you very much for your nice suggestion. 🌺🌺

​@@Skill_DIY you're welcome. I updated my comment to an even simpler mod. I hope it works as intended.

The maximum voltage I recommend is 12 volts

You're welcome I'm glad it was helpful! 🌺

Directly placing a potentiometer in line with the motor can result in its burning due to the passage of high current through it. Potentiometers have a specific power rating and cannot withstand the motor current, thus excessive current flow causes overheating and burning. Therefore, we use "power MOSFETs" or "power transistors" capable of handling high currents. The w13009 is a type of power transistor that can be used for this purpose.

@@Skill_DIY makes sense.

@@Skill_DIY but what if the potentiometer is 250 k?

Thank you dear friend, I am glad that it helped you 🌺

Thank you for your comment! 🌺

The purpose of this video is to know if it is really possible to generate free electricity in this way or not? 🌺

شكرا لتعليقك يا صديقي العزيز 🌺🌺

شكرا لدعمكم 😉🌺

Unfortunately, I don't have the ready circuit now. You can set the potentiometer for 50 degrees, then disconnect it and measure its value, then replace it with a resistor of about the same value.

না প্রিয় বন্ধু, এই সার্কিট 6 থেকে 12 ভোল্ট পর্যন্ত কাজ করে

Please explain a little more and tell why hysteresis feedback should be added? 🤏❤️🌺

@Skill_DIY Hi, it would switch on the fan at a certain temperature and switch it off as soon as the temperature drops a certain amount of degrees ( also adjustable if needed). This will ensure a more 'relaxed' regime of switching on and off instead of responding to any tiny difference in temperature.

​@@ottonormalverbrauch3794 hi is there any circuit which like you know combines this idea along with a condition to be satisfied I'm guessing simple logic gates with transistors can help

@dundermiflinaerospace7557 Hello, if you use an opamp with the temp sensor in a resistor grid on the non inverting input resulting in a higher voltage with higer temperatures and a variable voltage with a divider of a resistor to + and potentiometer P1 to - on the inverting input you can switch a transistor on and off with the output of the opamp. If you now feed the opamp output via a variable resistor P2 to the non inverting input you can use P1 to adjust the temp where the fan gets switched on and P2 to create a temperature drop before it will switch off again. Experiment with resistor values to get the desired effect.